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Tests for Descriptive Stats—315

Descriptive Statistics for LWAGE

 

 

 

Categorized by values of MARRIED and UNION

 

 

Date: 10/15/97

Time: 01:08

 

 

 

 

Sample: 1 1000

 

 

 

 

 

 

Included observations: 1000

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

UNION

MARRIED

 

Mean

Median

Std. Dev.

Obs.

0

 

0

 

1.993829

1.906575

0.574636

305

 

 

1

 

2.368924

2.327278

0.557405

479

 

 

All

 

2.223001

2.197225

0.592757

784

1

 

0

 

2.387019

2.409131

0.395838

54

 

 

1

 

2.492371

2.525729

0.380441

162

 

 

All

 

2.466033

2.500525

0.386134

216

All

 

0

 

2.052972

2.014903

0.568689

359

 

 

1

 

2.400123

2.397895

0.520910

641

 

 

All

 

2.275496

2.302585

0.563464

1000

 

 

 

 

 

 

 

 

For series functions that compute by-group statistics, see “By-Group Statistics” on page 579 in the Command and Programming Reference.

Boxplots by Classification

This view displays boxplots computed for various subgroups of your sample. For details, see “Boxplots” on page 409.

Tests for Descriptive Stats

This set of submenu entries contains views for performing hypothesis tests based on descriptive statistics for the series.

Simple Hypothesis Tests

This view carries out simple hypothesis tests regarding the mean, median, and the variance of the series. These are all single sample tests; see “Equality Tests by Classification” on

page 318 for a description of two sample tests. If you select View/Tests for Descriptive Stats/Simple Hypothesis Tests, the Series Distribution Tests dialog box will be displayed.

Mean Test

Carries out the test of the null hypothesis that the mean µ of the series X is equal to a specified value m against the two-sided alternative that it is not equal to m :

H0: µ = m

(11.5)

H1: µ m.

If you do not specify the standard deviation of X, EViews reports a t-statistic computed as:

316—Chapter 11. Series

 

X

m

(11.6)

t = ---------------

s N

 

where X is the sample mean of X, s is the unbiased sample standard deviation, and N is the number of observations of X. If X is normally distributed, under the null hypothesis the t-statistic follows a t-distribution with N − 1 degrees of freedom.

If you specify a value for the standard deviation of X, EViews also reports a z-statistic:

----------z =

X

----- m

(11.7)

σ N

 

where σ is the specified standard deviation of X. If X is normally distributed with standard deviation σ , under the null hypothesis, the z-statistic has a standard normal distribution.

To carry out the mean test, type in the value of the mean under the null hypothesis in the edit field next to Mean. If you want to compute the z-statistic conditional on a known standard deviation, also type in a value for the standard deviation in the right edit field. You can type in any number or standard EViews expression in the edit fields.

Hypothesis Testing for LWAGE

 

Date: 10/15/97

Time: 01:14

 

Sample: 1 1000

 

 

Included observations: 1000

 

 

 

Test of Hypothesis: Mean = 2

 

 

 

Sample Mean = 2.275496

 

Sample Std. Dev. = 0.563464

 

Method

Value

Probability

t-statistic

15.46139

0.00000

 

 

 

The reported probability value is the p-value, or marginal significance level, against a twosided alternative. If this probability value is less than the size of the test, say 0.05, we reject the null hypothesis. Here, we strongly reject the null hypothesis for the two-sided test of equality. The probability value for a one-sided alternative is one half the p-value of the two-sided test.

Variance Test

Carries out the test of the null hypothesis that the variance of a series X is equal to a specified value σ2 against the two-sided alternative that it is not equal to σ2 :

H0: var( x) = σ2

(11.8)

H1: var( x) ≠ σ2.

 

 

 

 

Tests for Descriptive Stats—317

 

 

 

EViews reports a χ2 statistic computed as:

 

 

χ

2

=

( N − 1) s2

(11.9)

 

-----------------------

 

 

 

σ2

 

where N is the number of observations, s is the sample standard deviation, and X is the sample mean of X. Under the null hypothesis and the assumption that X is normally distributed, the statistic follows a χ2 distribution with N − 1 degrees of freedom. The probability value is computed as min ( p, 1 − p) , where p is the probability of observing a χ2 - statistic as large as the one actually observed under the null hypothesis.

To carry out the variance test, type in the value of the variance under the null hypothesis in the field box next to Variance. You can type in any positive number or expression in the field.

Median Test

Carries out the test of the null hypothesis that the median of a series fied value m against the two-sided alternative that it is not equal to

H0: med( x) = m H1: med( x) ≠ m.

X is equal to a speci- m :

(11.10)

EViews reports three rank-based, nonparametric test statistics. The principal references for this material are Conover (1980) and Sheskin (1997).

Binomial sign test. This test is based on the idea that if the sample is drawn randomly from a binomial distribution, the sample proportion above and below the true median should be one-half. Note that EViews reports two-sided p-values for both the sign test and the large sample normal approximation (with continuity correction).

Wilcoxon signed ranks test. Suppose that we compute the absolute value of the difference between each observation and the mean, and then rank these observations from high to low. The Wilcoxon test is based on the idea that the sum of the ranks for the samples above and below the median should be similar. EViews reports a p- value for the asymptotic normal approximation to the Wilcoxon T-statistic (correcting for both continuity and ties). See Sheskin (1997, pp. 82–94) and Conover (1980, p. 284).

Van der Waerden (normal scores) test. This test is based on the same general idea as the Wilcoxon test, but is based on smoothed ranks. The signed ranks are smoothed by converting them to quantiles of the normal distribution (normal scores). EViews reports the two-sided p-value for the asymptotic normal test described by Conover (1980).

318—Chapter 11. Series

To carry out the median test, type in the value of the median under the null hypothesis in the edit box next to Median. You can type any numeric expression in the edit field.

Hypothesis Testing for LWAGE

Date: 10/14/97 Time: 23:23

Sample: 1 1000

Included observations: 1000

Test of Hypothesis: Median = 2.25

Sample Median = 2.302585

Method

Value

Probability

Sign (exact binomial)

532

0.046291

Sign (normal approximation)

1.992235

0.046345

Wilcoxon signed rank

1.134568

0.256556

van der Waerden (normal scores)

1.345613

0.178427

Median Test Summary

Category

Count

Mean Rank

 

 

 

Obs > 2.25

532

489.877820

Obs < 2.25

468

512.574786

Obs = 2.25

0

 

 

 

 

Total

1000

 

 

 

 

Equality Tests by Classification

This view allows you to test equality of the means, medians, and variances across subsamples (or subgroups) of a single series. For example, you can test whether mean income is the same for males and females, or whether the variance of education is related to race. The tests assume that the subsamples are independent.

For single sample tests, see the discussion of “Simple Hypothesis Tests” on page 315. For tests of equality across different series, see “Tests of Equality” on page 380.

Select View/Tests for Descriptive Stats/Equality Tests by Classification… and the Tests by Classification dialog box appears.

First, select whether you wish to test the mean, the median or the variance. Specify the subgroups, the NA handling, and the grouping options as described in “Stats by Classification” beginning on page 312.

Mean Equality Test

This test is based on a single-factor, between-subjects, analysis of variance (ANOVA). The basic idea is that if the subgroups have the same mean, then the variability between the

Tests for Descriptive Stats—319

sample means (between groups) should be the same as the variability within any subgroup (within group).

Denote the i-th observation in group g as xg, i , where i =

1, …, ng for groups

g = 1, 2, … G . The between and within sums of squares are defined as:

 

G

 

SSB =

Σ ng(

 

g

 

 

)2

(11.11)

x

x

 

g = 1

 

 

G ng

 

SSB =

Σ Σ ( xig

 

g)2

(11.12)

x

g = 1 i = 1

where xg is the sample mean within group g and x is the overall sample mean. The F- statistic for the equality of means is computed as:

SSB

⁄ ( G − 1 )

(11.13)

F = -----------------------------------

SSW

⁄ ( N G)

 

where N is the total number of observations. The F-statistic has an F-distribution with G − 1 numerator degrees of freedom and N G denominator degrees of freedom under the null hypothesis of independent and identical normal distribution, with equal means and variances in each subgroup.

For tests with only two subgroups ( G = 2) , EViews also reports the t-statistic, which is simply the square root of the F-statistic with one numerator degree of freedom. The top portion of the output contains the ANOVA results:

Test for Equality of Means of LWAGE

Categorized by values of MARRIED and UNION

Date: 02/24/04 Time: 12:09

Sample: 1 1000

Included observations: 1000

Method

df

Value

Probability

 

 

 

 

 

 

 

 

Anova F-statistic

(3, 996)

43.40185

0.0000

 

 

 

 

 

 

 

 

Analysis of Variance

 

 

 

 

 

 

 

 

 

 

 

Source of Variation

df

Sum of Sq.

Mean Sq.

 

 

 

 

 

 

 

 

Between

3

36.66990

12.22330

Within

996

280.5043

0.281631

 

 

 

 

 

 

 

 

Total

999

317.1742

0.317492

 

 

 

 

 

 

 

 

320—Chapter 11. Series

The analysis of variance table shows the decomposition of the total sum of squares into the between and within sum of squares, where:

Mean Sq. = Sum of Sq./df

The F-statistic is the ratio:

F = Between Mean Sq./Within Mean Sq.

The bottom portion of the output provides the category statistics:

Category Statistics

 

 

 

 

 

Std. Err.

UNION

MARRIED

Count

Mean

Std. Dev.

of Mean

0

0

305

1.993829

0.574636

0.032904

0

1

479

2.368924

0.557405

0.025468

1

0

54

2.387019

0.395838

0.053867

1

1

162

2.492371

0.380441

0.029890

 

All

1000

2.275496

0.563464

0.017818

 

 

 

 

 

 

 

 

 

 

 

 

Median (Distribution) Equality Tests

EViews computes various rank-based nonparametric tests of the hypothesis that the subgroups have the same general distribution, against the alternative that at least one subgroup has a different distribution.

In the two group setting, the null hypothesis is that the two subgroups are independent samples from the same general distribution. The alternative hypothesis may loosely be defined as “the values [of the first group] tend to differ from the values [of the second group]” (see Conover 1980, p. 281 for discussion). See also Bergmann, Ludbrook and Spooren (2000) for a more precise analysis of the issues involved.

We note that the “median” category in which we place these tests is somewhat misleading since the tests focus more generally on the equality of various statistics computed across subgroups. For example, the Wilcoxon test examines the comparability of mean ranks across subgroups. The categorization reflects common usage for these tests and various textbook definitions. The tests may, of course, have power against median differences.

Wilcoxon signed ranks test. This test is computed when there are two subgroups. The test is identical to the Wilcoxon test outlined in the description of median tests (“Median Test” on page 317) but the division of the series into two groups is based upon the values of the classification variable instead of the value of the observation relative to the median.

Tests for Descriptive Stats—321

Chi-square test for the median. This is a rank-based ANOVA test based on the comparison of the number of observations above and below the overall median in each subgroup. This test is sometimes referred to as the median test (Conover, 1980).

Under the null hypothesis, the median chi-square statistic is asymptotically distributed as a χ2 with G − 1 degrees of freedom. EViews also reports Yates’ continuity

corrected statistic. You should note that the use of this correction is controversial (Sheskin, 1997, p. 218).

Kruskal-Wallis one-way ANOVA by ranks. This is a generalization of the MannWhitney test to more than two subgroups. The idea behind the Mann-Whitney test is to rank the series from smallest value (rank 1) to largest, and to compare the sum of the ranks from subgroup 1 to the sum of the ranks from subgroup 2. If the groups have the same median, the values should be similar.

EViews reports the asymptotic normal approximation to the U-statistic (with continuity and tie correction) and the p-values for a two-sided test. For details, see She-

skin (1997). The test is based on a one-way analysis of variance using only ranks of the data. EViews reports the χ2 chi-square approximation to the Kruskal-Wallis test

statistic (with tie correction). Under the null hypothesis, this statistic is approximately distributed as a χ2 with G − 1 degrees of freedom (see Sheskin, 1997).

van der Waerden (normal scores) test. This test is analogous to the Kruskal-Wallis test, except that we smooth the ranks by converting them into normal quantiles

(Conover, 1980). EViews reports a statistic which is approximately distributed as a χ2 with G − 1 degrees of freedom under the null hypothesis. See the discussion of the Wilcoxon test for additional details on interpreting the test more generally as a test of a common subgroup distributions.

In addition to the test statistics and p-values, EViews reports values for the components of the test statistics for each subgroup of the sample. For example, the column labeled Mean Score contains the mean values of the van der Waerden scores (the smoothed ranks) for each subgroup.

Variance Equality Tests

Variance equality tests evaluate the null hypothesis that the variances in all G subgroups are equal against the alternative that at least one subgroup has a different variance. See Conover, et al. (1981) for a general discussion of variance testing.

F-test. This test statistic is reported only for tests with two subgroups ( G = 2) . First, compute the variance for each subgroup and denote the subgroup with the larger variance as L and the subgroup with the smaller variance as S . Then the F- statistic is given by:

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