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56

Analysis and Application of Analog Electronic Circuits

and thus:

 

 

 

 

 

 

 

 

IC1

=

 

IRc

 

= IC2

(2.64)

 

 

+ 2

β

 

 

1

 

 

If β is large (≥100), IC2 is nearly equal to the reference current:

 

IC2 IRc = (VCC VBE)/RC

(2.65)

Thus RC can be manipulated to obtain the desired quiescent dc current, IC2. If VCE2 varies, there will be a small variation in the dc ICE2. ICE2 can be expressed in terms of VBE2 and Q2’s Early voltage ( Vx ), which is used to model the upward tilt of the IC2 = f (VBE2, VCE2) curves. Gray and Meyer (1984)

model IC2 by:

IC2 = ICS[exp(VBE2

VT )](1+ VCE2

 

 

Vx

 

)

(2.66)

 

 

Now,

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

IC2

= ICS[exp(VBE2 VT )](1

 

Vx

 

)

(2.67)

 

 

 

 

 

 

VCE2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

so the variation in IC2 is:

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

IC2 = ICS[exp(VBE2

VT )](1

 

Vx

 

)

VCE2

(2.68)

 

 

A very detailed treatment of the transistor current sources and active loads used in IC design beyond the scope of this text can be found in Chapter 4 of Gray and Meyer (1984). These authors show how certain active load designs can be used to reduce the overall dc temperature coefficient (tempco) of certain amplifier stages, as well as to increase gain and CMRR.

2.4Mid-Frequency Models for Field-Effect Transistors

2.4.1Introduction

The two basic types of field-effect transistor are the junction field-effect transistor (JFET), which can be further characterized as n-channel or p-channel, and the metal-oxide semiconductor FET (MOSFET), which can also be subdivided into p- and n-channel devices and is further distinguished by whether it operates by enhancement or depletion of charge carriers in the channel. Surprisingly, one mid-frequency small-signal model describes the

© 2004 by CRC Press LLC

Models for Semiconductor Devices Used in Analog Electronic Systems

57

behavior of all types of FETs, although the dc biasing varies. MFSSMs for FETs use a voltage-controlled current source (transconductance) model in parallel with an output conductance to model the drain-to-source behavior. The following sections examine the behavior of JFETs and how they work as amplifiers.

2.4.2JFETs at Mid-Frequencies

Figure 2.27 illustrates the symbols for n- and p-channel JFETs and the volt–ampere curves for an n-channel JFET. Note that the gate-to-channel pn junction is normally reverse-biased in a JFET; thus, the gate current is the reverse saturation current of this diode (Irs), which is on the order of nA. In the n-channel JFET, all the currents and voltages are positive as written, with vGS being negative. In the p-channel JFET, all the signs are reversed: iD and vDS are negative and vGS is positive. The operating region of the JFET’s (iD, vDS) curves is ohmic to the left of the IDB line and saturated to the right of the IDB line.

 

 

 

 

 

D

iD

D

 

 

iD

 

 

 

 

 

+

 

+

 

 

 

 

 

 

G

 

vDS

G

 

 

vDS

 

 

 

 

 

 

 

 

 

 

 

+

 

 

 

+

 

 

 

 

 

 

 

vGS

 

vGS

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

S

 

 

 

S

 

 

 

 

 

n-channel

 

 

p-channel

iD

 

 

 

 

vGS = 0

 

 

 

 

iD

 

 

 

 

 

 

 

 

 

 

IDSS

 

 

 

 

 

 

 

 

 

IDSS

 

 

 

 

 

IDB = IDSS (VDS /VP)2

 

 

 

 

 

 

 

 

vGS = 1 V

 

vDS > vGS + vP

 

 

 

 

 

 

 

 

 

 

 

 

vGS = 2 V

 

 

 

 

 

 

 

 

 

 

vGS = 3 V

 

 

 

 

 

 

 

 

vGS = VP = 4 V

 

vDS

 

 

vGS

0

2

4

6

8 10 12 14

 

4

3

2

0

 

 

1

 

 

 

 

 

 

 

BVGD

 

 

 

FIGURE 2.27

Top: symbols for n- and p-channel JFETs. Bottom left: iD vs. vDS curves for an n-channel JFET. Area to left of IDB parabola has ohmic FET operation; area to right of IDB line has saturated (channel) operation. Bottom right: the iD vs. vGS curve for saturated operation [vDS > vGS + VP]. The pinch-off voltage VP = 4 V in this example.

© 2004 by CRC Press LLC

58

 

 

Analysis and Application of Analog Electronic Circuits

 

 

D

 

 

 

 

 

 

D

 

 

 

 

 

 

 

 

 

 

iD

+

G

D

 

G

 

id

 

 

 

 

 

+

 

 

 

 

 

 

 

 

rd

 

 

 

 

 

 

 

 

 

G

 

 

+ gmvgs

id

+

+

 

 

 

 

vDS

 

 

 

 

vds

 

 

 

 

 

 

 

+

 

 

vgs

gd vds

vgs µvgs

 

 

vGS

 

+

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

S

S

S

 

S

 

 

S

FIGURE 2.28

Left: symbol for n-channel JFET. Center: Norton MFSSM for p- and n-channel JFETs. Right: Thevenin MFSSM for JFETs.

Just as there is a mathematical model for pn junction diode current, there is also a mathematical approximation to JFET behavior in the saturation region. This is:

ID = IDSS (1− VGS VP )2 for VDS >

 

VGS + Vp

 

and

 

VGS

 

<

 

VP

 

(2.69)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

In the ohmic region, ID is modeled by:

ID = IDSS[2(1+ VGS VP )(VDS VP )(VDS VP )2 ] for 0 < VDS < VGS + Vp (2.70)

For VGS VP,

ID = IDSS[2(1+ VGS VP )(VDS VP )]

(2.71)

where IDSS is the drain current defined for VGS = 0 and VDS > VGS + VP . VP is the pinch-off voltage, i.e., VP = VGS where ID 0, given VDS > VGS + VP . In the ohmic region, the JFET behaves like a voltage-controlled conductance:

gd =

iD

 

VGS = IDSS[2(1+ (VGS VP )) VP ]

(2.72)

 

vDS

In the saturation region, n- and p-channel JFETs have the same MFSSM, shown in Figure 2.28. The transconductance of the VCCS is defined by:

g

 

=

iD

 

Q,V = const.

(2.73)

m

vDS

 

 

GS

 

 

 

 

 

 

By differentiating Equation 2.69, an algebraic expression is found for gm:

gm =

2

IDSS

(1− VGS VP )

(2.74)

 

V

 

 

 

P

 

 

© 2004 by CRC Press LLC

Models for Semiconductor Devices Used in Analog Electronic Systems

59

Note from Equation 2.69 that

ID can be written as:

 

ID =

IDSS (1− VGS VP )

(2.75)

Now Equation 2.75 can be substituted into Equation 2.74 to find:

gm =

2IDSS

 

IDQ

= gmo

IDQ

for VDS >

 

VGS + VP

 

(2.76)

 

 

 

 

V

 

 

I

DSS

I

DSS

 

 

 

 

 

 

 

 

 

 

P

 

 

 

 

 

 

 

 

 

 

Equation 2.76 gives an algebraic means of estimating a JFET’s gm in terms of its quiescent drain current (IDQ) and the manufacturer-specified parameters, IDSS and VP. gmo is the JFET’s (maximum) transconductance at VGS = 0

and VDS > VGS + VP .

The MFSSM for a saturated-channel JFET is also characterized by an output conductance in parallel with the VCCS. This small-signal conductance is due in part to the upward slope of the iD = f(vGS, vDS) curve family :

gd =

∂iD

 

 

=

ID

 

 

Siemens

(2.77)

∂vDS

 

VGS

VDS

 

Q,VGS = const.

 

 

 

 

 

 

 

 

 

 

 

 

To model the upward slope of the iD = f(vGS, vDS) curve family, we choose a voltage Vx such that:

ID IDSS (1− VGS VP )2 (1− VDS Vx ) for VDS > VGS + VP and VGS < VP (2.78)

Note that the intercept voltage, Vx, is typically 25 to 50 V in magnitude. Vx is negative and VDS is positive for n-channel JFETs and Vx is positive and VDS is negative for p-channel JFETs. An algebraic expression for gd can be found by differentiating Equation 2.78.

 

 

∂ID

 

 

2

(1 Vx ) = −(IDQ

Vx )> 0

 

gd

=

 

 

 

= IDSS (1− VGS VP )

(2.79)

∂VDS

 

Q

 

 

 

 

 

 

 

An estimate of Vx can be found by extrapolating the iD = f(vGS, vDS) curves in the saturation region back to the negative VSD axis, as shown in Figure 2.29.

The Norton drain–source model shown in Figure 2.28 can be made into a Thevenin model in which the series Thevenin resistance is just rd = 1/gd and the open-circuit voltage is given by a VCVS, μvGS. (Note the sign of the VCVS; it is the same for n- and p-channel JFETs.

The voltage gain, μ, is easily seen to be given by:

© 2004 by CRC Press LLC

60

Analysis and Application of Analog Electronic Circuits

iD

vGS = 0

vGS = 1

vGS = 2

vGS = 3

vGS = 4 = VP

Vx

0

iD

gm

IDSS

gmo

vGS

vGS

0

0

VP

VP

vDS

gd

IDSS /Vx

 

 

iDQ

0

IDSS

 

FIGURE 2.29

Top: large-signal iD vs. vDS curves for an n-channel JFET showing the geometry of the FET equivalent of the BJT Early voltage, Vx. Bottom, left to right: small-signal iD vs. vGS for a saturated channel. Small-signal gm vs. vGS for a saturated channel. Small-signal Norton drain conductance, gd vs. iD for a saturated channel.

μ = gm gd = gmo

(IDQ

IDSS )(

 

Vx

IDQ

 

)=

gmo

Vx

 

(2.80)

 

 

 

 

 

I

DQ

I

DSS

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

In the saturation region of operation, μ varies inversely with IDQ. Either the Norton or Thevenin model is valid. Most engineers use the Norton model because manufacturers generally provide VP, IDSS, and gmo for a given JFET.

2.4.3MOSFET Behavior at Mid-Frequencies

MOSFETS are also known as insulated gate field-effect transistors (IgFETS). The gate electrode is insulated from the channel, thus gate leakage current is on the order of picoamperes or less. Symbols for n-channel, p-channel, and the iD = f(vGS, vDS) curves for an n-channel depletion MOSFET are shown

© 2004 by CRC Press LLC

Models for Semiconductor Devices Used in Analog Electronic Systems

61

 

 

 

D

 

D

 

 

 

 

 

 

+

 

 

 

+

 

 

G

 

 

G

 

 

 

 

 

 

 

vDS

 

 

 

vDS

 

 

+

 

 

+

 

 

 

 

 

vGS

vGS

 

 

 

 

 

 

 

 

A

S

B

 

S

 

 

 

 

 

 

 

 

 

 

 

 

 

iD

 

VGS = +1

 

 

 

iD

 

 

 

 

 

 

 

 

 

VDS > VGS + VP

 

 

 

 

 

IDSS

 

 

VGS = 0

 

 

 

IDSS

 

 

 

 

 

 

 

 

 

 

 

VGS = 1

 

 

 

 

 

 

 

 

VGS = 2

 

 

 

 

 

 

 

 

VGS = VP = 3 V

vDS

 

 

 

vGS

 

 

 

 

 

 

 

 

0

 

 

0

 

VP 2 1

 

+1

 

 

 

 

 

 

 

 

 

C

 

 

D

 

 

 

 

FIGURE 2.30

(A) Symbol for an n-channel MOSFET. (B) Symbol for a p-channel MOSFET. (C) The iD = f(vGS, vDS) curves for an n-channel depletion MOSFET. (D) The iD = f(vGS) curve for a saturated-channel, n-channel depletion MOSFET.

in Figure 2.30. In the depletion device, a lightly doped p-substrate underlies a lightly doped n-channel connecting two heavily doped n-regions for the source and drain. This device has a negative pinch-off voltage (VP); however,

ID = IDSS when VGS = 0 and the saturated channel conducts heavily for VGS > 0. Similar to the n-channel JFET, it is possible to model the iD = f(vGS, vDS)

curves of the depletion n-channel MOSFET in the saturation region by:

iD = IDSS[1(vGS VP )]2

for vDS >

 

vGS + VP

 

> 0

(2.81)

 

 

and in the ohmic region:

iD = IDSS[2(1+ vGS VP )(vDS VP )(vDS VP )2 ] for 0 < vDS < vGS + VP (2.82)

When the iD = f(vGS, vDS) curves of the enhancement n-channel MOSFET shown in Figure 2.31 are considered, it can be seen that there is no IDSS for this family of device. Channel cut-off occurs at a threshold voltage, vGS = VT,

© 2004 by CRC Press LLC

62

Analysis and Application of Analog Electronic Circuits

iD

 

 

iD

 

 

vGS = +7 V

 

 

 

Ohmic

Saturation region

 

 

 

region

 

 

 

 

 

 

 

 

vGS = +6 V

 

 

 

 

vGS = +5 V

 

 

 

 

vGS = +4 V

 

 

 

 

vGS = VT = +3 V

 

VT

vGS

 

 

 

0

v

DS

0 1 2 3 4 5 6 7

FIGURE 2.31

Left: the iD = f(vGS, vDS) curves for an n-channel enhancement MOSFET. Right: the iD = f(vGS) curve for a saturated-channel, n-channel enhancement MOSFET.

where iD reaches some defined low value, e.g., 10 μA. The mathematical model for n-channel enhancement MOSFET iD = f(vGS, vDS) in the saturation region is:

iD = K(vGS VT )2 = K VT2 (1− vGS VT )2

for 0 <

 

vGS VT

 

<

 

vDS

 

(2.83)

 

 

 

 

In the ohmic channel operating region:

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

iD = K[2(vGS VT )vDS vDS2 ] for

0 <

 

vDS

 

<

 

vGS VT

 

 

(2.84)

 

 

 

 

The line separating the saturatedand ohmic-channel regions is

 

 

IDB = K VDS2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(2.85)

p-channel MOSFETs have iD = f(vGS, vDS) curves with the signs opposite those for n-channel devices. It is easy to see from Equation 2.73, which defines the small-signal transconductance, and Equation 2.72, which defines the small-signal drain conductance, that all FETs (JFETs, MOSFETs, n-channel, p-channel, enhancement, depletion) have the same parsimonious MFSSM — a case of electronic serendipity.

2.4.4Basic Mid-Frequency Single FET Amplifiers

Just as in the case of BJTs, there are so-called grounded-source amplifiers, grounded-gate amplifiers, and source followers. In order to find the small-

© 2004 by CRC Press LLC

Models for Semiconductor Devices Used in Analog Electronic Systems

63

VDD

 

 

 

 

RD

 

 

 

D

vo

 

C1

G

 

 

 

 

 

 

 

 

 

 

+

 

 

+

 

vgs

 

S

 

 

 

 

 

 

v1

RG RS CS

A

 

G

D

vo

 

 

 

 

+

 

 

v1

RG

gd

GD

 

gmvgs

 

 

S

 

 

 

 

B

FIGURE 2.32

(A) An n-channel JFET “grounded-source” amplifier. CS bypasses small ac signals at the JFET’s source to ground, making vs = 0. (B) MFSSM of the amplifier. The same MFSSM would obtain if a p-channel JFET were used.

signal voltage gain of each if these amplifiers, as well as their input and output resistances, first examine a JFET grounded-source amplifier, shown in Figure 2.32. At mid-frequencies, the external coupling and bypass capacitors are treated as short circuits. Thus, the source is at small-signal ground, so vs = 0. The amplifier’s mid-frequency gain is found from the node equation:

vo [GD + gd] = gm vgs = gm v1

(2.86)

 

 

 

 

¬

 

 

 

K

 

=

vo

=

−gmrdRD

 

(2.87)

v

v1

RD + rd

 

 

 

 

 

 

 

 

 

From inspection of the MFSSM of the circuit, Rin and Rout = RD rd/(RD + rd).

© 2004 by CRC Press LLC

64

Analysis and Application of Analog Electronic Circuits

VDD

RD

RS vs D

vo

S

+

v1

G

A

 

 

gd

 

 

gmvgs

 

RS vs

vo

 

 

+

S

D

 

 

v1

 

RD

 

 

G

B

FIGURE 2.33

(A) An n-channel MOSFET grounded-gate amplifier. (B) MFSSM of the MOSFET G-G amplifier. See text for analysis.

Next, consider an n-channel MOSFET grounded-gate amplifier at midfrequencies. The electrical circuit and its MFSSM are shown in Figure 2.33. Write two node equations, one for the vs node and the other for the drain (output) node.

vs [GS + gd + gm] − vo [gd] = v1GS

vs [gd + gm] + vo [gd + GD] = 0

Using Cramer’s rule:

= GS gd + GD [GS + gd + gm]

vs =

RD + rd

v1

 

RD + rd + RS (1+ gmrd )

(2.88A)

(2.88B)

(2.89)

(2.90)

© 2004 by CRC Press LLC

Models for Semiconductor Devices Used in Analog Electronic Systems

65

 

vo

=

RD (1+ gmrd )

= K

 

(2.91)

 

 

RD + rd + RS (1+ gmrd )

v

 

v1

 

 

 

 

 

 

The input resistance, Rin, of the MOSFET GG amplifier is found from:

 

v1

 

v1RS

 

 

 

RS

 

 

 

RD + rd

 

Rin =

 

=

v1(1− vs v1)

=

 

 

 

 

 

 

= RS +

(1+ gmrd )

(2.92)

is

1

 

 

RD

+ rd

 

 

 

 

RD

+ rd

+ RS (1+ gmrd )

 

 

 

 

 

 

 

 

 

 

 

Rout is approximately RD for the GG amplifier.

Finally, examine the MOSFET source-follower amplifier at mid-frequen- cies. The circuit and its MFSSM are shown in Figure 2.34. This an easy circuit to analyze because the drain is at SS ground. The output node equation is:

vo [GC + gd + gm] = gm v1

(2.93)

Equation 2.93 leads to the SF amplifier’s gain:

K

 

=

vo

=

RD gmrd

< 1

(2.94)

v

v1

rd + RD (1+ gmrd )

 

 

 

 

 

 

 

 

 

 

 

By inspection, Rin ; Rout can be found by voc/isc.

 

 

 

v1RD gmrd

 

 

R =

voc

=

rd + RD (1+ gmrd )

=

RD rd (1+ gmrd )

(2.95)

 

 

RD + rd (1+ gmrd )

out

isc

 

gmv1

 

 

 

 

Single FET amplifiers generally have higher Rin, about the same Rout, less gain, and more even harmonic distortion than equivalent BJT amplifiers.

2.4.5Simple Amplifiers Using Two FETs at Mid-Frequencies

As in the case of BJTs, certain basic building blocks for analog ICs can be made from two transistors. Figure 2.35 illustrates four such circuits using field-effect transistors. Notably absent is the difference amplifier; because of its great importance in analog electronic circuits, the DA is treated separately in Chapter 3 of this text. Figure 2.35(A) illustrates a Darlington amplifier in which the input transistor is an n-channel MOSFET acting as a voltage control-led current source driving the base of a power npn BJT. Figure 2.35(B) shows the FET–BJT equivalent for the “feedback pair” power amplifier. In Figure 2.35(C), a source-follower/grounded-gate high-frequency amplifier can be seen and an FET–FET cascode amplifier is shown in Figure 2.35(D).

© 2004 by CRC Press LLC

66

Analysis and Application of Analog Electronic Circuits

VDD

 

 

D

 

G

 

 

+

 

+

vgs S

 

 

 

+

v1

RG

RS vo

 

 

 

 

A

 

 

D

 

gmvgs

 

G

+

gd

 

 

+

vgs

vo

S

 

v1

RG

 

 

RS

 

 

B

FIGURE 2.34

(A) A p-channel MOSFET source follower. (B) MFSSM for the MOSFET S-F.

It is necessary first to examine the gain of the FET–BJT Darlington connected as an emitter follower. This circuit and its MFSSM are shown in Figure

2.36. Analysis begins by writing the node equations for the vs and vo nodes;

note that ib = gie (vs vo); vgs = v1 vs; μ = gm rd; and gie = 1/hie.

 

vs [gd + gie + gm] − vo gie = v1 gm

(2.96A)

vs [gie (1 + hfe)] + vo [gie (1 + hfe) + GE] = 0

(2.96B)

Using Cramer’s rule,

 

= (gd + gm)gie (1 + hfe) + GE (gd + gie + gm)

(2.97)

vo = v1 gm gie (1 + hfe)

(2.98)

© 2004 by CRC Press LLC

Models for Semiconductor Devices Used in Analog Electronic Systems

67

Q1

D

Q2

 

 

 

Q1 S

Q2

 

 

 

 

 

 

G

 

G

 

 

V1

 

 

 

V1

vs

 

 

 

vd

 

 

 

S

 

 

 

 

D

 

 

 

A

 

 

 

B

 

 

 

 

 

 

 

 

 

 

VDD

 

 

 

VDD

 

 

 

 

 

 

 

 

 

 

 

 

 

Rd

 

 

 

 

 

 

 

D

 

Vo

 

 

 

 

 

 

 

 

 

 

Rd

 

 

 

 

 

(0)

 

 

 

 

 

 

 

 

 

Q1

 

Vo

 

 

S

 

 

 

 

 

 

vs

Q2

 

 

 

 

 

 

 

 

G

D

D

(0)

 

 

Q1

D

 

 

 

 

 

 

V1

 

vs

 

 

V1

 

 

 

 

 

 

 

 

 

 

S

 

 

S

S Q2

 

 

 

Rg

 

 

Rg

Rs

 

Rg

 

 

 

 

 

 

 

 

 

Rs

 

 

 

 

 

 

 

 

 

 

 

 

 

 

C D

FIGURE 2.35

(A) An n-channel MOSFET/npn BJT Darlington configuration. (B) A p-channel MOSFET/npn BJT feedback pair configuration. (C) An n-channel MOSFET source-follower–grounded-gate amplifier. (D) An n-channel JFET cascode amplifier.

Solving for vo/v1 yields:

vo

=

RE (1+ hfe )μ

 

 

RE (1+ hfe )(1+ μ) + hie (1+ μ) + rd

(2.99)

v1

As expected, this voltage gain is <1. The amplifier’s input resistance is extremely high and the output resistance can be found by the open-circuit output voltage, given by Equation 2.99, divided by the short-circuit output

current, which is simply ib(1 + hfe) for vo = 0, (Rout = OCV/SCC). Rout is on the order of single ohms.

Next, find the gain for the FET–BJT feedback pair amplifier shown in Figure 2.35(B). The node equations are:

© 2004 by CRC Press LLC

68

Analysis and Application of Analog Electronic Circuits

VCC

vo

v1

RE

D

gmvgs

gd

G

vs B

v1

S

ib hie hfe ib

vo

RE

FIGURE 2.36

Top: A MOSFET/BJT Darlington connected as an emitter-follower. Bottom: MFSSM of the Darlington EF. See analysis in text.

vd [gd + gie] − vo [gie] = − v1 gm

(2.100A)

vd [gie (1 + hfe)] + vo [GE + gie (1 + hfe)] = 0

(2.100B)

Using Cramer’s rule,

 

= gd [GE + gie (1 + hfe)] + gie GE

(2.101)

vo = − v1 gm gie (1 + hfe)

(2.102)

from which the mid-frequency voltage gain is found:

© 2004 by CRC Press LLC

Models for Semiconductor Devices Used in Analog Electronic Systems

69

 

RD

 

vo

D

D

gmvgs1

gmvgs2

gd

gd

G

G

 

vs

v1

 

S

S

RS

FIGURE 2.37

MFSSM for the two-MOSFET SF/GG amplifier. See text for analysis.

vo

=

−REμ(1+ hfe )

=

−μR

 

 

RE (1+ hfe )+ hie + rd

RE + (hie + rd )E (1+ hfe )

= Kv

(2.103)

v1

Again, Rin is very high because of the MOSFET and Rout can be found from

Rout = OCV/SCC. It can be shown that Rout is RE in parallel with (hie + rd)/(1 + hfe) ohms.

The MFSSM of the FET–FET SF-GG amplifier of Figure 2.35(C) is shown in Figure 2.37. Proceeding as before, write the node equations for vs and vo, then use Cramer’s rule to find the amplifier’s MFSS gain; note that vgs1 = v1 − vs and vgs2 = − vs.

vs [2(gd + gm) + GS] − vo [gd] = gm v1

(2.104A)

−vs [gd + gm] + vo [GD + gd] = 0

(2.104B)

= 2GD (gd + gm) + gd (gm + GS) + GS GD

(2.105)

vo = v1 gm (gd + gm)

(2.106)

The voltage gain is found from Equation 2.105 and Equation 2.106:

vo

=

+RDμ

 

= K

 

(2.107)

v1

RD + 2rd + rd (rd + RD ) [RS

(1+ μ)]

v

 

 

 

 

 

 

 

 

 

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70

Analysis and Application of Analog Electronic Circuits

RD

vo

D

gmvgs2

gd

G

S

vs

D

gmvgs1

gd

G

+

v1

S

FIGURE 2.38

MFSSM for the two-JFET cascode amplifier. See text for analysis.

Note that the gain is noninverting; Rin is on the order of 1013 Ω and Rout is slightly lower than RD.

The final two-FET amplifier considered is the cascode amplifier using two JFETs shown in Figure 2.35(D). The MFSSM of the cascode is shown in Figure 2.38. Note that vgs1 = v1, vgs2 = −vs, the JFETs are matched, and μ = gm rd. The node equations are:

vs [2gd + gm] − vo gd = − gmv1

(2.108A)

vs [gd + gm] + vo [GD + gd] = 0

(2.108B)

= 2gd GD + 2gd2 + gmGD + gm gd gd2 gm gd = GD(2gd + gm) + gd2 (2.109)

vo = − v1 gm [gd + gm]

(2.110)

The cascode amplifier’s mid-frequency voltage gain is found to be:

vo

=

RDμ(1+ μ)

= K

 

(2.111)

 

RD + rd (1+ μ)

v

v1

 

 

 

 

 

 

 

© 2004 by CRC Press LLC