Добавил:
Upload Опубликованный материал нарушает ваши авторские права? Сообщите нам.
Вуз: Предмет: Файл:
FREGRAVOL2.pdf
Скачиваний:
71
Добавлен:
05.06.2015
Размер:
8.65 Mб
Скачать

366

9 Supergravity: An Anthology of Solutions

9.2.7.1 An Explicit Example of Exact Regular BPS Solution

This general mechanism can be illustrated with an explicit example of exact regular solution of the S3 model. The key identifier of the solution is its vector of electromagnetic charges that in our chosen example is the following one:

p2

 

 

 

p

 

 

 

p1

 

 

 

0

 

 

 

 

 

q1

 

=

 

q

 

; p, q > 0 or p, q < 0

(9.2.86)

3

q

 

 

 

0

 

 

 

 

 

 

2

 

 

 

 

 

 

 

 

 

The corresponding explicit solution is given below and depends on three parameters p, q and κ which yields the value of the imaginary part of the scalar field at radial infinity, namely at τ = 0.

The Metric

exp U (τ ) =

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

κ3/4

 

 

 

 

 

 

 

 

(9.2.87)

 

3/2 pτ )(q

 

 

τ 1)3

κ

The Scalar Field

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

4

 

 

 

(pτ

 

 

 

 

κ3/2)(q

 

τ

 

1)3

 

 

 

κ

 

 

 

 

 

 

κ

 

 

Im z(τ )

= −

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(9.2.88)

 

 

 

 

 

 

 

 

 

 

 

 

 

2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(qκτ

1)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Re z(τ ) = 0

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(9.2.89)

The Electromagnetic Fields

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Z1(τ ) = 0

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(9.2.90)

Z2(τ ) = −

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(9.2.91)

 

κ

3/2

 

 

 

3/2

pτ )

 

 

 

 

 

 

 

 

 

 

2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

qκτ

 

 

 

 

 

 

 

 

 

 

 

 

 

Z1(τ ) = −

 

23

 

 

 

 

 

 

 

 

 

 

 

 

 

q

 

τ

1

 

 

 

 

 

 

 

 

 

 

(9.2.92)

κ

 

 

 

 

 

 

 

 

 

 

Z2(τ ) = 0

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(9.2.93)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

The interested reader can verify that the expressions displayed above for all the fields fulfill the variational equations (9.2.6) of the σ -model and hence are bonafide solutions of the supergravity field theory.

The Fixed Scalars at Horizon and the Entropy

Calculating the area of the

horizon we find:

 

 

 

 

 

 

 

 

 

1

 

 

 

1

 

 

 

 

 

 

AreaH rH2

 

→−∞

 

 

 

= pq3

 

 

 

=

τ lim

 

exp

U (τ )

(9.2.94)

4π

τ 2

9.2 Black Holes Once Again

367

which makes sense only as long as pq3 > 0. Inserting (9.2.86) into (9.2.75) we see that pq3 = I4. Hence we conclude that this solution is indeed BPS as expected. The horizon area is:

1

I4

 

4π AreaH rH2 =

(9.2.95)

9.2.8The Attraction Mechanism Illustrated with an Exact Non-BPS Solution

Next we illustrate the attraction mechanism with an explicit example of exact regular non-BPS solution of the S3 model. The vector of electromagnetic charges of the considered solution differs from that of the above BPS-example only by means of a sign, namely it is:

p2

 

 

p

 

 

 

p1

 

 

0

 

 

 

 

q1

 

=

 

q

 

; p, q > 0 or p, q < 0

(9.2.96)

3

q

 

 

 

0

 

 

 

 

 

2

 

 

 

 

 

 

 

 

The corresponding explicit solution which is given below depends on four parameters p, q and κ, ξ which yield the values of both the imaginary and the real parts of the scalar field at radial infinity, namely at τ = 0.

The Metric The metric is defined by the function U for which the integration techniques of the σ -model yield the following expression:

exp U (τ ) = κ3/4/ q3κ3τ 3 q3κξ 2τ 3 + 3q2κ5/2τ 2 + 3q2κξ 2τ 2

 

 

 

 

 

+ p(q

 

τ 1)3τ 32τ 32τ + κ3/2 1/2

(9.2.97)

 

 

 

 

 

κ

The Scalar Field The complex scalar field z(τ ) has the following form:

+ p τ 2

Im z(τ ) = −κ q3κ3τ 3 q2κ qξ 2 + 3p τ 3 + 3q2κ5/2τ 2 + 3qκ qξ 2

 

4

 

 

 

 

 

 

 

 

 

 

 

 

 

 

32τ 32 + p τ + κ3/2 pq3τ 4 + 1 1/2/(q

 

τ 1)2(9.2.98)

 

κ

Re z(τ ) =

(q

 

 

ξ

 

 

 

 

 

 

 

 

 

(9.2.99)

 

τ

1)2

 

 

 

 

 

 

 

κ

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

The Electromagnetic Fields The explicit form of the two field strengths appearing in the S3 model is completely determined by (9.2.14). It suffices to know the magnetic charges (p1, p2) = (0, p), the Taub-NUT charge n = 0 and the derivatives

Соседние файлы в предмете [НЕСОРТИРОВАННОЕ]