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Yuriy Kruglyak. Quantum Chemistry_Kiev_1963-1991

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on the basis vectors with definite N . For this reason we fix a number of particles N in our system and will construct corresponding eigenvectors.

The expansion coefficients of the eigenvectors of Hˆ over the basis vectors are usually determined as solutions of the eigenvalue problem for a matrix with the

elements p σ

H pσ . For the practical determination of approximate eigenvectors

′ ′

ˆ

 

the CI matrix is truncated before diagonalization.

The order of the CI matrix which is to be diagonalised can be decreased considerably if there are operators which commute with the Hamiltonian as well as between each other. Then using an appropriate unitary transformation one goes from the set of vectors pσ to a new set of the basis vectors which are eigenvectors of

these operators, and an initial eigenvalue problem reduces into several eigenvalue problems of a smaller order. Each of them corresponds to a definite totality of eigenvalues of the operators mentioned.

The spin-free Hamiltonian always commutes with the total spin projection operator Sˆz and with the square of the total spin operator Sˆ2 . These two operators commute with each other also. We shall first find the expressions for them both in the

second quantization representation. Expression for Sz

is obtained from the general

 

 

ˆ

 

definition of an one-particle operator

 

 

ˆ

ˆ+ ˆ

ˆ

(171)

Q Aiσ Ajσ<ψiσ |Q |ψ jσ>,

 

ijσσ

 

 

where one should place Q = Sz . Using the orthonormality of the spin-orbitals and the

ˆ

ˆ

 

 

 

 

 

 

 

 

 

definition

 

 

 

 

1

 

 

 

 

 

 

 

 

ˆ

 

σψiσ

 

 

 

 

 

Szψiσ =

2

 

 

one obtains

 

 

 

 

 

 

 

 

 

 

 

 

1

 

 

 

 

 

 

 

 

ˆ

 

 

ˆ+

ˆ

 

 

(172)

 

 

Sz =

2 iσ

σ Aσ

Aσ .

 

 

 

 

 

 

i

 

i

 

 

To construct an operator S

we begin with the well known Dirac expression [10]

 

 

ˆ2

 

 

 

 

 

 

 

 

ˆ2

=

1

N(4 N ) +

ˆσ

(173)

S

4

Pkl .

 

 

 

 

 

1k<lN

 

 

In the second quantization representation the first term has the same pattern except

that the total number of particles N must be replaced by the corresponding operator

ˆ

N

defined by (170). The operator

ˆσ

which interchanges the spin functions of two

Pkl

electrons k and l in the states ψiσ

and ψ jσcorresponds to the two-particle operator

 

110

ˆ+ ˆ+

ˆ ˆ ˆ+ ˆ+

ˆ ˆ

(174)

(Aiσ Ajσ Ajσ Aiσ + Aiσ Aj,σ Ajσ Ai,σ ).

σ

 

 

 

Thus, finally

ˆ2

 

1 ˆ

ˆ

1

ijσ

ˆ+ ˆ+ ˆ ˆ ˆ+ ˆ+

ˆ ˆ

S

=

4 N(4

N ) +

2

(Aiσ Ajσ Ajσ Aiσ + Aiσ Aj,σ Ajσ Ai,σ ).

Later we shall consider a construction of the eigenvalues of the operators

(175)

Sˆz and Sˆ2 .

2.7.3.3. Hole Formalism

 

 

 

 

 

Consider the subset of the spin-orbitals

{ψ}1 , which contains first 2nF

one-

particle states ψiσ with i nF or one can take nF pairs of arbitrary spin-orbitals

ψi,+1

and ψi,1 with subsequent renumbering of them, and form a vector

 

 

nF

ˆ+

ˆ+

 

0 .

(176)

 

 

 

Φ0 = (Ai,+1Ai,1)

 

 

i=1

 

 

 

 

 

This vector corresponds to the Slater determinant built on the spin-orbitals chosen. A determinant built from the same spin-orbitals except ψ jσ corresponds to a vector

 

 

 

 

nF

 

 

 

 

 

 

 

 

 

 

 

 

ˆ+

 

 

ˆ+

ˆ+

 

0 .

 

 

(177)

 

 

 

 

 

 

 

 

 

Φ′ = Aj,σ

(Ai,+1Ai,1)

 

 

 

 

 

 

 

i=1(ij)

 

 

 

 

 

 

 

 

Acting on

 

Φ′ by a unit operator

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

ˆ+ ˆ

 

ˆ

ˆ+

 

 

 

 

 

 

 

 

 

 

Ajσ Ajσ

+ Ajσ Ajσ

 

and using relations (161) and (165) one obtains

 

 

 

 

 

 

 

 

 

 

ˆ

 

 

Φ0

.

( j nF )

(178)

 

 

 

 

 

 

 

 

 

Φ′ =σ Ajσ

 

 

This means that action of an operator

ˆ

with

j nF on the vector

 

Φ0

leads to the

 

Ajσ

 

annihilation of a particle in an occupied state ψ jσ , i.e. to the creation of a hole in this

state. Thus the operators

ˆ

and

ˆ+

with i nF can be interpreted as creation and

Aiσ

Aiσ

annihilation respectively of the holes in the states of the subset {ψ}1 . It can be shown

that the Slater determinant with u rows changed by other v rows in the second quantization representation corresponds to a vector obtained from Φ0 by action of u

hole creation and v particle creation operators in the corresponding states. All basis vectors for the CI method can be presented in this way and we shall now describe the corresponding formalism.

Using the anticommutation relations (161) and a definition of the vacuum state (165) it is easy to see that

111

ˆ+

 

Φ0

= 0,

Φ0

 

ˆ

(i nF ),

(179a)

 

 

Aiσ

 

 

Aiσ = 0,

ˆ

 

Φ0

= 0,

Φ0

 

ˆ+

(i > nF ),

(179b)

 

 

Aiσ

 

 

Aiσ = 0,

i.e. Φ0 is a vacuum state with respect to the creation and annihilation operators of the holes and particles. In the following discussion under the vacuum state we always

imply the state

 

Φ0

and not the initial state

 

0 .

 

 

We shall now introduce the important concept of a N-product (normal product)

of the operators F1

, F2

, F3,... denoted as

N (F1F2F3 ) . In order to go from the usual

 

 

ˆ

ˆ

ˆ

ˆ ˆ ˆ

product to a normal one we must transpose the operators in such a way that all the hole and particle creation operators are placed to the left of the annihilation operators, and each transposition of a pair of the operators must be followed by change of a sign. Under the sign of a N-product the operators can be arbitrary transposed. The sign depends only on the parity of transposition. An important property of the N-product, a consequence of (161), is that its average value over the vacuum state is equal to zero

Φ0

 

N( )

 

Φ0 = 0.

(180a)

 

 

An obvious exception is the case when under the sign of a N-product there is a constant or an expression not having creation or annihilation operators (c-numbers).

Then its average over the vacuum state is equal to itself

 

Φ0 N(c) Φ0 = c .

(180b)

A reduction of operator products to a sum of the N-products is extremely useful as shown in calculating the vacuum average of the operator products by expression

(180). This reduction

can be easily performed for a product of two operators using

the N-products and the anticommutation relations (161):

 

 

ˆ ˆ

ˆ ˆ

 

 

 

ˆ ˆ

(181)

 

AB = N(AB) + AB .

 

 

 

 

 

ˆ ˆ

denotes a c-number called a convolution of the operators

ˆ

The symbol AB

A and

B . Only the following convolutions of the particle and hole operators are not equal to

ˆ

 

 

 

zero:

 

 

 

 

 

 

 

ˆ ˆ+

=1,

(i > nF ),

(182a)

Aiσ Aiσ

 

 

 

ˆ+ ˆ

=1,

(i nF ).

Aiσ Aiσ

Thus introducing the population numbers

 

1,

i n

 

 

n

 

F

 

=

 

i

0,

i > n

 

 

 

 

 

F

(182b)

(183)

112

one obtains for all convolutions

 

 

 

 

 

ˆ

ˆ

ˆ+ ˆ+

= 0

,

(184a)

Aiσ Ajσ

= Aiσ Ajσ

 

 

 

 

 

ˆ+ ˆ

 

 

 

(184b)

 

Aiσ Ajσ= niδijδσσ,

 

 

 

 

 

 

ˆ

ˆ+

= (1ni )δijδσσ.

(184c)

Aiσ Ajσ

The rules for reduction of the operator product to a sum of the N-products in a general case are given by the Wick’s theorems [11]. The theorems given in [11] have been formulated by Wick [7] for the chronological products. We give a particular formulation of these theorems for the operators with equal times.

Theorem 1. A product of the creation and annihilation operators is represented by a sum of the normal products with all possible convolutions including a N-product without convolutions. The sign of each term is determined by a number of the operator transpositions needed that the convoluting operators are grouped together:

Fˆ1Fˆ2Fˆ3 Fˆn = N(Fˆ1Fˆ2Fˆ3 Fˆn ) + Fˆ1Fˆ2 N(Fˆ3Fˆ4Fˆ5 Fˆn )

 

 

Fˆ1Fˆ3 N(Fˆ2Fˆ4Fˆ5 Fˆn ) +... + Fˆ1Fˆ2 Fˆ3Fˆ4 N(Fˆ5Fˆ6Fˆ7 Fˆn ) +...

Theorem 2. If some operators in the product to be reduced stand from the beginning under the sign of the N-product then the reduction is made in the same way except that the convolutions must be omitted for those operators which from the beginning were standing under the sign of the same N-product.

2.7.3.4. Expansion of the Physical Value Operators over the N-products

For a one-particle operator using (181) and (184) one obtains from (171)

ˆ

ˆ+ ˆ

 

ˆ

 

ψ jσ

+ni ψiσ

 

ˆ

 

ψiσ .

 

 

 

 

Q N (Aiσ Ajσ)ψiσ

 

Q

 

 

Q

 

 

ijσσ

 

 

 

 

iσ

 

 

 

 

In particular, if an operator Q does not act on the spin variables, then

ˆ

 

ˆ

ˆ+ ˆ

Q = N (Aiσ Ajσ )Qij +2niQii ,

ijσ

i

where

Qij = ϕi Qˆ ϕj .

One obtains in the same way from (172)

ˆ

1

iσ

 

(

ˆ+ ˆ

i

)

 

Sz =

2

σN

i

.

 

 

 

Aσ Aσ

 

(185)

(186)

(187)

(188)

113

The number-of-paticles operator (170) becomes

ˆ

ˆ+ ˆ

(189)

N = N (Aiσ Aiσ )+2nF .

 

iσ

 

Now we shall transform the Hamiltonian (162). The first sum in (162) is transformed according to (186) with Qˆ = hˆ . In order to transform a sum corresponding to the electron interaction we use the first Wick theorem. Its application to a product of four operators gives

ˆ+ ˆ+

ˆ

ˆ

 

ˆ+ ˆ+ ˆ

ˆ

 

ˆ+

ˆ

 

 

ˆ+ ˆ

 

 

ˆ+ ˆ

ˆ+

ˆ

N

 

Aiσ AjσAlσAkσ = N (Aiσ AjσAlσ

Akσ )+ Aiσ Akσ

N (AjσAlσ)+ AjσAlσ

(Aiσ Akσ )

 

 

 

 

 

 

 

 

(190)

 

ˆ+ ˆ

ˆ+

ˆ

 

ˆ+

ˆ

N

ˆ+ ˆ

ˆ+ ˆ

ˆ+

ˆ

ˆ+ ˆ

 

ˆ+ ˆ

,

Ajσ

Akσ

(Aiσ Alσ)AiσAlσ

N (AjσAkσ )+

Aiσ Akσ

AjσAlσAiσ Alσ

Ajσ Akσ

where only those terms are written down which can have non-zero convolutions. Putting this expansion into (162) and substituting all convolutions by their values according to (184), after the necessary summations one obtains

ˆ

 

ˆ+ ˆ

 

1

ˆ+ ˆ+

ˆ

ˆ

H = E0

+Fij N (Aiσ Ajσ )+

 

(ij |kl)N (Aiσ AjσAlσ

Akσ ),

 

ijσ

 

 

2 ijklσσ

 

 

 

where

 

 

+ninj 2(ij |ij)(ij | ji)

 

 

 

E0

= 2nihii

 

 

 

 

i

ij

 

 

 

 

 

and

Fij = hij +n 2(ik | jk )(ik |kj) .

k k

(191)

(192)

(193)

Expression (192) is the well known equation for the energy in the Hartree – Fock approximation and Fij are the matrix elements

Fij = ϕi Fˆ ϕj

of the Fock operator built on the orbitals ϕ1,ϕ2 ,ϕ3,...,ϕnF . If these eigenfunctions of the SCF Fock operator with eigenvalues εi then

Fij =εiδij

and the Hamiltonian (191) becomes

ˆ

ˆ+ ˆ

1

ˆ+ ˆ+ ˆ

ˆ

H = E0

+εi N (Aiσ Aiσ )+

 

(ij |kl)N (Aiσ AjσAlσ

Akσ ).

 

iσ

2 ijklσσ

 

 

orbitals are

(194)

114

This particular expression for the Hamiltonian is applicable only under the conditions mentioned. The general expression (191), however, is valid for an arbitrary orthonormal set of orbitals.

Following the same procedure one can obtain an expression for the operator Sˆ2 given by (175). We present the final result

ˆ2

 

3

(1

i

ˆ+ ˆ

i

1

N

(

ˆ+ ˆ+ ˆ

j

ˆ

i

)

 

1

N

(

ˆ+ ˆ+

ˆ

j,

ˆ

i

)

S =

4

iσ

2n )N(Aσ Aσ ) +

4 ijσ

Aσ A σ A σ Aσ

 

4 ijσ (ij)

 

Aσ A

σ A

σ Aσ

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(195)

 

3

N

ˆ+ ˆ+

ˆ

ˆ

+

1

ˆ+

ˆ+

 

 

ˆ

 

ˆ

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(Aiσ Ai,σ Ai,σ

Aiσ )

 

N (Aiσ

Aj,σ

Ajσ Ai,σ ).

 

 

 

 

 

 

 

 

 

 

 

4 iσ

 

 

 

 

 

2 ijσ (ij)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

The fourth sum in (195) contains terms with i = j from the third and fifth sums. Having derived expressions for the operators Sˆz and Sˆ2 in an appropriate form

we can construct the basis vectors for the CI method which are eigenfunctions of these operators. First we note that any vector obtained as a result of the action of N p

particle and Nh hole creation operators on the vacuum state Φ0 is an eigenvector of the operator Nˆ with an eigenvalue N p Nh + 2nF which is equal to the total number of

particles. By fixing this number we need consider only vectors with a definite value of the difference N p Nh . In most cases the vacuum state can be chosen in such a way

that N p

is equal to Nh

(the ground state of a molecule with closed shell) or differs

from Nh

by one (a radical).

Next we choose

the electronic configuration. Let us set up the electronic

configuration by selecting the orbitals corresponding to N p particles and Nh holes irrespective of their spins. We shall denote it as (k1k2k3...kNh ,m1m2m3...mN p ) where ki corresponds to the hole orbitals, and mi numerate the particle orbitals. These numbers are supposed to be arranged in a non-decreasing order (naturally kNh < nF , m1 > nF ).

Furthermore, according to the Pauli principle each number cannot occur more than once.

Now for the configuration above

(k1k2...,m1m2...)

we

construct all possible

vectors as

 

 

 

 

 

 

 

 

 

 

 

 

ˆ

 

ˆ

 

ˆ+

 

ˆ+

 

 

 

Φ0

,

(196)

 

 

 

 

 

Ak σ

Ak σ

 

Am σ

Am σ

 

1

1

2

2

1

1

2

2

 

 

 

 

 

which in the following discussion are called the primitive vectors. Each of the spin indices σ1,σ2 ,...,σ1,σ2,... independently assumes values +1 and –1 except those

cases when ki = ki +1 andmi = mi+1 for which necessary σi = −σi+1 =1 and σi′ = −σi+1 =1.

115

MS = 12 (N p+ N p)(Nh+ Nh) ,
N p+ , N p, Nh+ , Nhis the number of particle and hole operators with the spin +1 and
Under these conditions the primitive vectors constructed form an orthonormal system. Each of them is an eigenvector of the operator Sˆz with the eigenvalue

where

–1 correspondingly.

To determine the necessary basis vectors one selects for each configuration all primitive vectors (196) with a given value of the difference (N p+ N p)(Nh+ Nh),

construct a matrix of the operator Sˆ2 for them, and diagonalizes it. The result of the application of the operator Sˆ2 on the primitive vector represented at first sight as a cumbersome expression (195) is obtained by the following rules.

Rule 1. The action of the first four sums in (195) on a vector (196) reduces to a multiplication of it by a constant. Its value is equal to the value of MS2 plus half the

sum of N p and Nh minus the number of orbitals occupied in pairs by particles and

holes with opposite spins. All diagonal elements of the matrix of the operator S

will

 

ˆ2

 

be equal to the constant found so far.

acts on a vector (196)

Rule 2. The remaining part of the expression for S

ˆ2

 

 

converting it to a sum of the vectors orthogonal to (196). Each of them differs from the initial vector by change on opposite the spin indices of two particle-particle or hole-hole operators with different spins or the particle-hole operators with equal spins. In the later case a vector enters a sum with a minus sign. It is necessary to consider all mentioned pairs of operators used to construct an initial vector except those operators which correspond in pairs to the same orbitals.

2.7.3.5. General Approach to Calculation of the Matrix Elements

Previous treatment shows that the basis vectors are linear combinations of the primitive vectors, and the operators of the important physical values reduce to three basic types:

 

 

 

ˆ

= N(c) ,

 

 

 

 

 

0

 

 

 

 

ˆ

 

ˆ+

ˆ

 

 

 

1

= Qij,σ N (Aiσ Ajσ ),

 

 

 

ijσ

 

 

 

ˆ

 

1

 

ˆ+ ˆ+

ˆ

ˆ

2

=

2 ijklσσ

(ij |kl)N (Aiσ AjσAlσ

Akσ ).

(197a)

(197b)

(197c)

116

Take two primitive vectors corresponding to the same or to different configurations

Φ1

ˆ

 

ˆ

 

ˆ+

 

ˆ+

 

 

 

 

Φ0 ,

(198a)

 

 

 

 

 

 

 

= Ak σ

Ak σ

 

Am σ

Am σ

 

 

1

1

 

2

2

1

1

 

2

2

 

 

 

 

 

Φ2

ˆ

 

 

ˆ

 

ˆ+

 

 

ˆ+

 

 

 

Φ0 .

(198b)

 

 

 

 

 

 

 

 

 

= Al τ

Al τ

 

An τ

An τ

 

 

 

 

1 1

2

2

1 1

 

2

2

 

 

 

 

 

We shall calculate for them the matrix elements of each of the operators (197). Denoting

ˆ

 

ˆ

 

ˆ

 

 

 

 

ˆ+

 

ˆ+

 

 

 

 

(199a)

R1

= Ak σ

Ak σ

2

Am σ

Am σ,

 

 

1

1

 

2

 

1

1

 

2

2

 

 

 

ˆ+

 

 

ˆ

 

 

 

ˆ

 

 

ˆ+

 

ˆ+

 

,

(199b)

R1

= Am σ

Am σAk σ

Ak σ

 

 

 

 

2

2

 

 

1

1

 

 

2

2

1

1

 

 

ˆ

 

= Al τ Al τ

 

 

+

 

 

+

 

,

 

(199c)

R2

2

An τ

An τ

 

 

 

 

1 1

2

 

 

1 1

 

2

2

 

 

 

 

the matrix element of an operator ˆ , any of the operators (197), may be considered as the vacuum average

Φ1

 

ˆ

 

Φ2

= Φ0

 

ˆ+ ˆ ˆ

 

Φ0 .

(200)

 

 

 

 

 

 

 

R1 R2

 

To calculate (200), the product

R1 R2

 

must be reduced applying the Wick’s

 

 

 

 

 

ˆ + ˆ ˆ

 

 

 

 

 

theorems to the sum of the N-products. As a result of the averaging according to (180) only those terms remain which are c-numbers, i.e. those terms in which all operators in Rˆ1+ˆ Rˆ2 enter the convolutions.

The advantage of the presentations of the physical value operators as a sum of N-products is now evident. Since Rˆ1+ is a product of the particle and hole annihilation operators only, and Rˆ2 – of the creation operators only, then Rˆ1+ = N (Rˆ1+ ) , Rˆ2 = N (Rˆ2 ) and according to the second Wick’s theorem one must consider only the convolutions between the operators Rˆ1+ , ˆ , and Rˆ2 .

After this preliminary remark we continue the determination of the value of the matrix elements. First we find the maximum number of convolutions which can be constructed between the operators from Rˆ1+ and Rˆ2 . This number is equal to the

number of particles and hole operators in Rˆ1 which are repeated in Rˆ2 . The operators in Rˆ1 as well as in Rˆ2 may be transposed in an arbitrary way multiplying the value of the matrix element by (1)p1 , where p1 is the total number of transpositions. For this reason it is convenient to order the operators in Rˆ1 and Rˆ2 first, transposing them in such a way that the repeating operators are placed in Rˆ1 and Rˆ2 in the same order to the right of the non-repeating operators. We shall assume in the following that this ordering is performed. The total number of non-repeating operators in Rˆ1 and Rˆ2 will

117

be denoted q . Because each of these q operators may be convoluted with one of the

operators from one can state a priori that the matrix element

Φ0 R1 R2 Φ0 will

 

 

ˆ

 

 

 

 

 

ˆ + ˆ ˆ

 

not be equal to zero only for q = 0 if Ω = Ω0 , for q = 0,2 if

Ω = Ω1 , and for q = 0,2,4 if

 

 

 

ˆ

ˆ

ˆ

ˆ

 

 

 

ˆ

ˆ

. We shall consider each of these cases separately. In cases when the total

Ω = Ω2

 

 

ˆ

ˆ

is less than 2 for

ˆ

ˆ

or less than 4 for

number of the operators in R1

and R2

Ω = Ω1

ˆ

ˆ

the value of the corresponding matrix elements is obviously equal to zero.

Ω = Ω2

Case 1: ˆ = Ωˆ 0 , q = 0 . The convolution which gives a non-zero result can be done in a single way convoluting in pairs the repeating operators. When Rˆ1 and Rˆ2

are correctly ordered there is always an even number of other operators between the convoluting operators. Thus, the number of transpositions required by the first Wick theorem is also even and each convolution according to (184) is equal to unity. Finally the value of the matrix element will be equal to

 

 

 

 

 

 

Φ1

 

ˆ

 

Φ2

= (1)

p1

c .

 

 

 

(201)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

0

 

 

 

 

 

ˆ

ˆ

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Case 2: Ω = Ω1 , q = 0 . In this case the vacuum average is equal to the sum of the

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

ˆ

with two

terms each of which is the result of a convolution of two operators from 1

equal operators from

ˆ

 

ˆ

 

 

 

 

ˆ

and

ˆ

, if there

R1 and

R2 . The other operators repeating in

R1

R2

are any, convolute between them in pairs.

 

 

 

 

 

 

 

The final result is

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Φ1

 

ˆ

 

Φ2 = (1)

p1

Qii,σ

(12ni ),

 

 

 

(202)

 

 

 

 

 

 

 

 

 

 

1

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

iσ

 

ˆ

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

where a pair of indices i,σ covers the interval met in R1 .

 

 

 

 

ˆ

ˆ

q = 2 . The single term in the expansion of

ˆ + ˆ

ˆ

over the

Case 3: Ω = Ω1 ,

R1 R2

N-products the vacuum average of which may be different from zero is obtained in the following way. All operators from Rˆ1 repeating in Rˆ2 convolute with the

corresponding operators from

 

R1 . Two non-repeating operators convolute with the

 

 

 

 

ˆ +

 

 

 

 

 

 

 

 

operators from 1 . The results is

 

 

 

 

 

 

 

 

ˆ

 

 

 

 

 

 

 

 

 

 

Φ1

 

ˆ

 

Φ2 = (1)

p1

+p2

δσ σ

Qi i

,σ

,

(203)

 

 

 

1

 

 

 

 

 

 

 

 

 

 

1

2

1 2

 

1

R2 the

 

 

 

 

 

 

 

 

where p2 is the number of transpositions necessary to place in the product R1

 

 

 

 

 

 

 

 

 

 

 

ˆ

ˆ +

non-repeating operator with a cross at the left of the non-repeating operator without a cross ( p2 is equal to 1 or 0), and a pair of indices i1,σ1 runs over the indices of the

118

Rˆ1 Rˆ2+
Rˆ1+Rˆ2

non-repeating operator with a cross, and a pair i2 ,σ2 – without a cross in the product

Rˆ1 Rˆ2+ .

Case 4: ˆ = Ωˆ 2 , q = 0 . For each pair of operators from Rˆ2 in the matrix element expression for this case there are possible four terms identical in pairs obtained by

convoluting these operators and the corresponding pair of operators from

ˆ +

with

R1

 

 

 

ˆ

 

 

 

 

 

 

 

 

four operators from 2

 

 

 

 

 

 

 

 

 

ˆ

 

 

p1

 

 

 

(1

2ni )(12nj ),

 

(204)

 

 

 

 

Φ1

2

 

Φ2 = (1)

 

(ij

|ij)δσσ(ij | ji)

 

 

 

 

 

 

ijσσ

 

 

 

 

 

 

where a pair of indices i,σ runs in the interval met in the operators from Rˆ1 and a pair j,σcovers all values of indices of the operators from Rˆ1 placed to the right of the operator with indices i,σ .

Case 5: ˆ = Ωˆ 2 , q = 2 . In the expansion of each of the repeating operators in Rˆ2 four terms identical in pairs may not be equal to zero. They are obtained by the

convoluting with the operators from 2 of two non-repeating operators, and one of

the operators in

R2

repeating in R1

ˆ

 

R1 . The

, and the corresponding operator from

 

 

ˆ

 

 

ˆ

 

 

ˆ +

final result is

 

 

 

 

 

 

 

 

ˆ

 

= (1)

p1+p2

 

 

 

(205)

 

 

 

Φ1

2

Φ2

 

δσ1σ

2 (12ni ) (ii1 |ii2 )δσσ1

(ii1 |i2i) ,

 

 

 

 

 

 

iσ

 

 

where a pair of indices i,σ

covers all values met in the repeating operators, and a

value of p2 and indices i1,i2 ,σ1,σ2 are defined as in case 3.

 

 

Case 6: ˆ = Ωˆ 2 , q = 4 . In this last case there may not be equal to zero the four in pairs identical terms obtained by convoluting four non-repeating operators from with four operators from ˆ 2 . The result can be obtained in the following way. Let us write all non-repeating operators in the same order as they are placed in the product

and order them in such a way that the cross operators stand to the left of the non-cross operators. Let p3 be the number of transpositions made in order to obtain standard order

Aˆi+1σ1 Aˆi+2σ2 Aˆi3σ3 Aˆi4σ4 .

Then the value of the matrix element is

Φ1

 

ˆ

 

Φ2

= (1)

p1

+p2

 

 

δσ σ

 

(i1i2

|i4i3 )δσ σ δσ σ

 

(i1i2 |i3i4 )

 

.

(206)

 

 

 

 

 

 

 

2

 

 

δσ σ

 

 

 

 

 

 

 

 

 

 

 

1

4

2

3

 

1

3

2

4

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

119

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