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Сборник задач по высшей математике. Тестовые методы контроля знаний. В 3 томах. Т.3

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l
π
 – * $".    ,   ,   )%.
%  3&  &   
(
)   (  ),
  &  :
1
+" ()   
′′
2
uau′′=
,
xxtt
,x
) (, #):
1
,
( ) ( ) ( )( ) ( )
2
2
) $"   :
′′
txu
):
2
uau′′=
,
xxtt
0,
,
0==x
( )
lx ,0
,
txu
=lx
=
,
,
t
=0
atxatxtxu
2
0
t
=
0,
.
atxu
k
π
l
xtxu
,
1
atx
ξψ++ϕ+ϕ= d
,
tt
=0
ξ
xtxu
a
)(,
xtxu
,
,
tt
=0
atk
b
+
sincos,
k
π
xtxu
,
π
atk
sin
l
xk
,
l
π
2
l
( )
x
ψ
0
ak
sin
xk
dx
l
l
2
( )
a
k
x
ϕ=
0
sin
xk
b
dx
,
=
k
% &    &  
(
)   ( 
)  :
) $"   :
2
uau′′=
,
xxt
lx ,0
,
0
t
=
)(,
xtxu
,
txu
0,
,
0==x
txu
=lx
):
2
ak
π
( )
=
k
  
eCtxu
k
=
1
t
 
l
sin,
π
xk
,
C
k
2
l
x
( )
ϕ=
0
sin
xk
dx
0,
.
127
 1. '  & !! 
2
)(x
ϕ
(
)
)(x
ϕ
642
(
)
=
(
)
=
′′
yy
2
xyyxu
+=
3
.
. 6 &  ,  -      . %   ­  , 
32
yxydyxyyxu
)(
x
ϕ++=+=
.
$
( )
y
3
 !,  - ,  -
2
xy
      ,          ­ .
%        -
yxu ,
 !
),(
 
:
xy
3
yxyyxu ψ+ϕ++=
2
)(
ϕ++=
dyx
 
3422
xyyxy
)()(
xxy
,
642

–    !.
*,  & !!   
342
),(
yxu ψ+ϕ++=
xyyxy
)()(
xxy
.
 2. ),    ! -
 & !! 

u
,)
0)
)
/)
21,1
:
22432
yxyxyx ++
;
24223
yxyxyx ++
;
24223
2
yxyxyx +
;
22432
yxyxyx ++
;
xx
′′
122 yxyu
=
223
,
#)
3 yxyxyx +
32432
.
. % ,  ! 

u
21,1
:
128
,)
(
)
(
)
(
)
=
(
)
(
)
=′′+′′−′′
=′−′′+′′−′′
Cxy
=
+
Cxy
=
+
14
x
y
+=ξ
xy14
+=η
=
′+′
′−′
=
ξ
η=ξ′′=′
η
ξ
21,1=u
; 0)
21,1=u
; )
u
11,1
; /)
*,     ,); 0); /); #).
21,1=u
; #)
21,1=u
.
'
,)
0)
/)
#)
x
x
x
x
u
  !:
xx
233
+=
yxxyu
422
+=
xyyxu
233
+=
233
+=
yxxyu
′′
142
,
xx
′′
123
,
xx
xyxxyu
242
,
342
,
xx
42
;
223
;
223
2122
+=
yxyu
223
.
;
122 yxyu
=
26 yxyu
=
′′
xx
′′
122 yxyu
=
 , & !!  ­ !
,)
yxyxyx ++
22432
 #)
3 yxyxyx +
32432
.
 3. '  & !! 
uuu
01415
yyxyxx
.
.   2, 3 § 11  
uuuu
021415
yyyxyxx
.
%        !!   ,    –  –  (.  2)    (.  3):
    
.
, !! 
01415
yyxyxx
)(
,
  
u
0
ξη
(.   § 11). "& 
. %  
ξηη
uuu
,   &
fduu
1

f
 !,  - ,  -
1
)(
      ,  
 
    η. *-
129
   η (    
ξ
ξ+η=ηη=
η′=
)(),
(
ξ
η
g
f
)()
(
ξ+η
=
gfu
)()14(xygxyf
u
+++
=
1
+
x
)1,1(
u
+
at
x
1
+
x
1,1
=
=
t
x
4
17
):
)()()(
gfdfduu
η
1
,

–   !.
*,
,
,    ,    & !! 
.
 4. "&  3&   
5
′′
=
 
2
′′
),(),,(,
txuxuau
=+∞−∞
.
x
txxtt
4
00
==
tt
1,2cos)0,(,
==
axxu
. + ! #
1
,
( ) ( ) ( )( ) ( )
atxatxtxu
2
1
a
2
atx
ξ
ξψ++ϕ+ϕ= d
,

 

=
%
),()(==ϕ
txux
txu 2cos
=
1
2
,
0
t
=
),(
txu
1
=
),(
2
1
2
)(5
tx
− +
)(1
tx
+
,   &
=ψ
5
x
tx
+
tx
tx
)(5
tx
)(1
+
),()(
txux
t
4
)(5
+
)(1
+
)(5
tx
+
)(1
tx
++
.
0
=
t
t
 
44
00
==
tt
+−tx
1
tx
2
1 4
2sin
+
)(5
+
tx
44
)(1
++
tx
tx
)(5
44
tx
)(1
++
1
( )
4
1,2cos)0,(,
==
axxu
,
=ξξ+
d
+−tx
=ξ+
tx
)(2sin)(2sin
txtx
++
.
5
)1,1( +=u
4sin
.
130
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