- •Міністерство освіти і науки україни донецький національний технічний університет
- •Integral calculus (інтеґральне числення)
- •Донецьк 2005
- •Integral calculus lecture no. 19. Primitive and indefinite integral
- •Point 1. Primitive
- •Properties of primitives
- •Point 2. Indefinite integral and its properties
- •Point 3. Integration by substitution (change of variable)
- •Point 4. Integration by parts
- •Lecture no.20. Classes of integrable functions
- •Point 1. Rational functions (rational fractions)
- •Point 2. Trigonometric functions
- •Universal trigonometrical substitution
- •Other substitutions
- •Point 3. Irrational functions
- •Quadratic irrationalities. Trigonometric substitutions
- •Quadratic irrationalities (general case)
- •Indefinite integral: Basic Terminology
- •Lecture no. 21. Definite integral
- •Point 1. Problems leading to the concept ofa definite integral
- •Point 2. Definite integral
- •Point 3. Properties of a definite integral
- •I ntegration of inequalities
- •Point 4. Definite integral as a function of its upper variable limit
- •Point 5. Newton-leibniz formula
- •Point 6. Main methods of evaluation a definite integral Change of a variable (substitution method)
- •Integration by parts
- •Lecture no.22. Applications of definite integral
- •Point 1. Problem – solving schemes. Areas
- •Additional remarks about the areas of plane figures
- •Point 3. Volumes
- •Volume of a body with known areas of its parallel cross-sections
- •Volume of a body of rotation
- •Point 4. Economic applications
- •Lecture no. 23. Definite integral: additional questions
- •Point 1. Approximate integration
- •Rectangular Formulas
- •Trapezium Formula
- •Simpson’s formula (parabolic formula)
- •Point 2. Improper integrals
- •Improper integrals of the first kind
- •Improper integrals of the second kind
- •Convergence tests
- •Point 3. Euler г- function
- •Definite integral: Basic Terminology
- •Lecture no. 24. Double integral
- •Point 1. Double integral
- •Point 2. Evaluation of a double integral in cartesian coordinates
- •Point 3. Improper double integrals. Poisson formula
- •Point 4. Double integral in polar coordinates
- •Double integral: Basic Terminology
- •Contents
- •Integral calculus 3
- •Integral calculus (Інтеґральне числення): Методичний посібник по вивченню розділу курсу ”Математичний аналіз” для студентів ДонНту (англійською мовою)
Point 3. Volumes
Volume of a body with known areas of its parallel cross-sections
Let some body is situated between the planes , , and for any the area of its cross-se-ction by a plane perpendicular to Ox-axis is known (see fig. 16). The volume of the body equals the integral Fig. 16 . ( 22 )
■ An element of the volume is the volume of a right circular cylinder with the base and the altitude ,
.
Adding all these elements we get the required volume represented by the formula (22).■
Ex. 15. Find the volume of the triaxial ellipsoid
(fig. 17)
For any the plane section of the body per- Fig. 17 pendicular to the Ox-axis is ellipse with the semi-axes
and the area
.
Therefore the volume of the ellipsoid by the formula (22) equals
.
Volume of a body of rotation
A curvilinear trapezium (see fig. 1) rotates about -axis. Prove that the volume of the corresponding body (body of rotation, fig 18) equals the definite integral
. ( 23 )
■ For any a cross-section of the body of ro- Fig. 18 tation by a plane perpendicular to Ox-axis is a circle of radius (fig. 18). Therefore its area , and by the formula (22) the vo-lume of the body in question is given by the formula (23).
Let the same curvilinear trapezium (fig. 1) rotates about -axis and or . Prove that the volume of the corresponding body of rotation is represented by the integral
. ( 24 )
Ex. 16. Let the arc of a sinusoid rotates about the Ox-, Oy-axes. Calculate the volumes of corresponding bodies of rotation.
With the help of the formulas (23), (24) we get
.
.
A curvilinear trapezium (fig. 6) rotates about -axis. Prove that the volume of the corresponding body of rotation is represented by the integral
. ( 25 )
Ex. 17. An ellipse rotates about the Ox-, Oy-axes. Calculate the volumes of corresponding bodies of rotation.
From the equation of the ellipse
,
and by the formulas (24), (25) we have
;
.
Point 4. Economic applications
Problem 1 (produced quantity). Let the labour productivity of a some factory at a time moment t equals . It is known (see the formula (11) of the point 2 of prce-ding lecture) that its produced quantity U during the time interval [0, T] equals
.
Ex. 18. Let the labour productivity of a factory is . Then its produced quantity
.
Problem 2 (costs of conservation of goods). Let is the quantity of goods in the storage at a time moment t, and a quantity h represents the costs of conservation of unit of goods per unit of time. Then the costs of conservation of goods during a time interval (or an element of the costs of conservation) equals
.
Adding all these elements from to we get the costs of conservation of goods during the time interval , that is
.
Let, for example, we study the case of uniform consumption of all goods from at a time to at a time . In this case the quantity of goods at a time mo-ment t is
,
and the costs of conservation of goods equals
.