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ex + ey + ez 2π |
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eiϑ2/2 ◦ eiϑ1/2 = |
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(1 + iex + iey − ey ◦ ex) = |
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{1 + i(ex + ey − ez )} = |
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ex + ey − ez |
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ex2 + ey2 + ez2 2 |
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> . . / 3
/ ! / / !
/ @ .3 90◦
x .3 90◦ y 0 120◦
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= (1 + εiex/2) ◦ (1 − iez )/ |
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= |
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εiex/2 |
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iπez /4 |
√ |
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7
1 / ! .3
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+ sh |
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sh |
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