3.3. Варианты задания
Таблица 3-1
-
№
Подынтегральная функция
a
b
t
m
1
f(x) = 8 e-x sin(-2x)
2
3
1
3
0.25
2
f(x) = e-x sin(2x)
0
2
2
1
0.5
3
f(x) = x3/2 – 2 x sin(x)
3
4
3
2
0.25
4
f(x) = e-xcos(-2x)
2
4
1
3
0.5
5
f(x) = cos(2x) + 2 sin(x)
1
3
2
1
0.5
6
f(x) = 8 sin(2x) – x
0.2
1.2
3
2
0.25
7
f(x) = 5 cos(-2x) e-x
-0.5
0.5
2
3
0.25
8
f(x) = x sin(x + 1) – cos(x – 5)
1
2
1
2
0.25
9
f(x) = 0,25 x3 + cos(x/4)
1
3
1
3
0,5
10
f(x) = sin(2x) – 2 sin(x)
3.5
5
1
3
0.5
11
f(x) = sin(ex) – e-x +1
0
1
2
1
0.25
12
f(x) = 5 x sin(x + 1) + 2 cos(x)
1
2
1
2
0.25
13
f(x) = 5 e-x + 4 x + x3/3
-1
1
1
2
0.5
14
f(x) = -2 sin(4x) ln(-x) + 5
-2.5
-1.5
1
3
0.25
15
f(x) = sin(x – 1) – x cos(x + 3)
-4
-2
3
1
0.5
16
f(x) = 4 sin (x) – x1/2
1
2
2
3
0.25
17
f(x) = 5 sin3(x) + cos3(x)
1
2
2
1
0.25
18
f(x) = cos(2x + 1) ln (2 / x) + 3
1
3
3
2
0.5
19
f(x) = 3 cos(x2) / ln(x + 5)
-1
1
1
3
0.5
20
f(x) = sin(x2) + 1 / (2 – x)
-1.5
0.5
2
1
0.5
21
f(x) = x sin(x) + cos(x) + 5
0
2
1
2
0.5
22
f(x) = – cos(x) – cos(2x) – x + 5
1
3
3
1
0.5
23
f(x) = 1 + sin(4x) / ln(x)
1.5
2.5
1
3
0.25
24
f(x) = (1 + x2)1/2 + e-x
-1
2
2
1
0.75
25
f(x) = sin(x + 1) e2 / x
1
2
3
2
0.25
26
f(x) = 2 (1 + x) e-x – 2 cos(x)
1
4
2
3
0.75
27
f(x) = – 8 sin(– x3) e-x
0.4
1.4
1
3
0.25
28
f(x) = – 10 sin(x3) cos(– x)
-1.4
-0.4
2
1
0.25
29
f(x) = x2cos(x + 3) – 4
3
4
3
1
0.25
30
f(x) = – cos(x – 5) e2x / 3
1
3
1
3
0.5