Контрольные работы / 4
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Контрольная работа № 4
Задачи линейного программирования
Задание 1
Решить задачу линейного программирования графическим методом.
Задание 2
Решить задачу линейного программирования симплексным методом. Если это необходимо, применить метод искусственного базиса.
Задание 3
Составить по общему правилу двойственную задачу к исходной задаче линейного программирования.
Решить исходную задачу графическим методом. Найти оптимальное решение двойственной задачи с помощью теоремы равновесия.
Задание 4
Составить по общему правилу двойственную задачу к исходной задаче линейного программирования.
Решить исходную задачу симплексным методом.
Найти оптимальное решение двойственной задачи из первой и последней симплексных таблиц исходной задачи (с помощью векторной и матричной формул).
Примечание: во всех вариантах считать x ≥ 0.
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Вариант 1 |
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1. z = 6x1 + x2 +4x3 −5x4 |
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3x |
+ x |
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− x |
+ x |
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= 4, |
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→ max при |
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2 |
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4 |
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2. z = x1 +3x2 − x4 −8 → max при |
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5x1 + x2 + x3 − x4 = 4. |
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3x2 |
+ x3 |
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+ x5 |
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=18, |
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+ x2 |
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+ x4 |
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+x5 |
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= 25, |
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3x1 |
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2x |
− x |
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+ x |
4 |
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=10. |
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x |
− x |
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≤ |
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1, |
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3. z = x1 +3x2 → min при 6x1 + x2 ≥ 6, |
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x |
+ x |
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≥ |
5. |
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1 |
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при |
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4. z = 2x1 +3x2 + x3 −2x5 + 2 → max |
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x |
− x |
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+ x |
+3x |
4 |
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= 7, |
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2x1 |
+3x2 |
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− x4 |
+ x5 |
=3. |
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Вариант 2 |
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1. |
z = 5x1 + 2x2 − x3 → max при |
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2x |
+ x |
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− x |
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= 4, |
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3 |
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4x1 |
−5x2 |
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+ x4 |
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=10, |
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+ x |
2 |
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+ x |
= 7. |
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2. |
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при |
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z = x1 + x2 + x3 + x4 |
→ max |
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x |
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+3x |
2 |
+ x |
+2x |
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=5, |
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1 |
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3 |
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2x1 |
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− x3 |
+ x4 |
=1. |
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5x1 + 2x2 ≤ 20, |
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3. |
z = x1 + x2 → max |
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x1 − x2 ≤ 2, |
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4. |
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3x1 −2x2 ≥ −4. |
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z = −3x1 + 4x2 + x3 + 2x4 − x5 +7 → max |
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− x |
+2x |
2 |
+3x |
+ x |
4 |
=1, |
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2x1 |
+ x2 |
−2x3 |
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+ x5 =8. |
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Вариант 3 |
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1. z = 5x1 + 2x2 − x3 → min |
при |
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2x |
+ x |
2 |
− x |
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= 4, |
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3 |
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4x1 |
−5x2 |
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+ x4 |
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=10, |
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x |
+ x |
2 |
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+ x |
= 7. |
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при |
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2. z = x1 + x2 + x3 + x4 → min |
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x |
+3x |
2 |
+ x |
+2x |
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=5, |
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2x1 |
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− x3 |
+ x4 |
=1. |
2x1 − x2 ≤ −1, 3. z =3x1 + 2x2 → min при 3x1 + x2 ≥ 6,
3x1 − x2 ≤3.
4. z = x1 −2x2 −3x3 − x4 + x5 +3 → max при |
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x |
+ x |
2 |
− x |
+ x |
=3, |
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3 |
5 |
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3x1 |
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2x3 |
+ x4 −2x5 |
= 4. |
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Вариант 4 |
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1. z = 9x2 +3x3 + 2x5 −4 → min |
при |
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x |
− x |
2 |
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+ x |
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=1, |
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3 |
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x1 |
+ x2 |
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− x4 |
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=3, |
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2x |
− x |
2 |
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− x |
= −2. |
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при |
5 |
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2. z = 2x1 + x2 +3x3 + x4 → max |
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x |
+2x |
2 |
+5x |
− x |
4 |
= 4, |
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x1 |
− x2 |
− x3 |
+2x4 |
=1. |
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− x1 |
+ x2 |
≥1, |
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3. |
z = 3x1 + x2 |
→ max |
при |
x1 |
+3x2 ≤15, |
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−2x + x |
2 |
≤ 4. |
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1 |
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4. |
z = −2x1 + x2 + x3 +3x4 − x5 −8 → max при |
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x |
+2x |
2 |
− x |
4 |
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+3x |
= 6, |
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3x2 |
+ x3 |
+2x4 |
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− x5 |
=13. |
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Вариант 5 |
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1. |
z = 2x1 + x2 +3x3 + x4 |
→ max |
при |
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x +2x |
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+5x |
− x |
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= 4, |
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2. |
z = x2 − x4 − x5 +8 → max при |
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x1 − x2 − x3 +2x4 =1. |
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3x |
+4x |
2 |
+ x |
+ x |
4 |
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+2x |
= 43, |
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3 |
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5 |
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3x1 |
+ x2 |
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+ x4 |
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+x5 |
= 25, |
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x |
+2x |
2 |
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+ x |
=15. |
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x −2x |
5 |
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≤ −4, |
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3. |
z = 2x1 +3x2 |
→ min |
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при 3x1 + x2 ≥9, |
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3x1 −2x2 ≤12. |
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4. |
z = 2x1 − x2 + 2x3 + 4x5 −7 → max |
при |
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− |
3x |
+ x |
2 |
+2x |
4 |
+ x |
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= 4, |
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5 |
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5x1 |
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+ x3 |
−3x4 |
+2x5 |
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=1. |
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Вариант 6
1. z = 9x2 +3x3 + 2x5 −4 → max при
x |
− x |
2 |
+ x |
=1, |
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3 |
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x1 |
+ x2 |
− x4 |
=3, |
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2x |
− x |
2 |
− x |
= −2. |
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1 |
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5 |
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2. z = 2x1 + x2 +3x3 + x4 → min при |
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x |
+2x |
2 |
+5x |
− x |
4 |
= 4, |
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3 |
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x1 |
− x2 |
− x3 |
+2x4 |
=1. |
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x |
− x |
≥ −1, |
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3. z = x1 + 2x2 → max при |
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2 |
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3x1 + x2 ≤9, |
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x |
−2x |
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≤ 2. |
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1 |
2 |
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4. z = 2x1 + x2 +5x3 + x4 + 4 → max |
при |
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x |
+3x |
2 |
+2x |
+ x |
4 |
= 4, |
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−2x1 |
+ x2 |
−3x3 |
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+ x5 |
=3. |
Вариант 7
1. |
z = 3x1 −3x2 − x3 + x4 +14 → max |
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−2x |
+ x |
2 |
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+ x |
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= 2, |
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4x1 |
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+3x2 |
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− x4 |
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=16, |
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8x |
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− x |
2 |
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+ x |
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=16. |
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2. |
z = x1 + x2 + x3 + x4 |
→ max |
при |
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x |
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+3x |
2 |
+7x |
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− x |
4 |
= 6, |
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x1 |
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− x2 |
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− x3 |
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+3x4 |
= 2. |
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2x1 − x2 ≤ 2, |
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3. |
z = x1 +3x2 |
→ min |
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при |
2x1 + x2 |
≥ 4, |
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x − x |
2 |
≤ −1. |
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4. |
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при |
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z = x1 +6x2 +3x3 + 4x5 −8 → max |
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+2x |
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− x |
4 |
+3x |
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=12, |
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x2 |
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+ x3 |
+2x4 |
− x5 |
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=1. |
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Вариант 8
1. |
z = 3x1 −3x2 − x3 + x4 +14 → min |
при |
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−2x |
+ x |
2 |
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+ x |
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= 2, |
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3 |
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4x1 |
+3x2 |
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− x4 |
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=16, |
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8x |
− x |
2 |
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+ x |
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=16. |
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2. |
z = x1 + x2 + x3 + x4 |
→ min |
при |
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x |
+3x |
2 |
+7x |
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− x |
4 |
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= 6, |
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x1 |
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− x2 |
− x3 |
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+3x4 |
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= 2. |
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x1 − x2 ≤1, |
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3. |
z = x1 + 2x2 |
→ max |
при |
4x1 − x2 ≥ 2, |
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x − |
3x ≥ −3. |
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4. |
z = x1 + 2x3 − x4 + x5 −2 → max |
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при |
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x |
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−2x |
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+ x |
4 |
+4x |
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= 2, |
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+ x3 |
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+3x4 |
− x5 |
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=3. |
Вариант 9
1. |
z = x1 −3x2 −5x3 − x4 +6 → max при |
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x |
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+4x |
2 |
+4x + x |
4 |
=5, |
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x1 +7x2 +8x3 +2x4 =9. |
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2. |
z = 4x1 + x2 − x3 −11 → max |
при |
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− x |
+7x |
2 |
+3x |
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+2x |
=39, |
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x1 |
+5x2 |
+ x3 |
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+2x5 |
=33, |
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2x |
− x |
2 |
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+ x |
4 |
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=10. |
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x1 −2x2 ≤1, |
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3. |
z = x1 +5x2 → min |
при |
2x1 +3x2 |
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≥9, |
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−2x + x |
2 |
≤ 2. |
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1 |
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4. z = 3x1 − x2 + 2x3 − x4 −3 → max при |
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x |
+2x |
2 |
+ x |
− x |
=1, |
1 |
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3 |
5 |
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2x1 |
− x2 |
+ x4 |
+ x5 |
=5. |
Вариант 10
1. |
z = x1 + 2x2 + x4 + x5 +3 → min |
при |
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3x |
+2x |
2 |
− x |
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=12, |
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x1 |
−2x2 |
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+ x4 |
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= −4, |
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− x |
+ x |
2 |
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+ x |
=3. |
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5 |
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2. |
z = 6x1 + x2 +4x3 −5x4 → max |
при |
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3x |
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+ x |
2 |
− x |
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+ x |
4 |
= 4, |
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3 |
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5x1 |
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+ x2 |
+ x3 |
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− x4 |
= 4. |
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4x1 − x2 ≥ 4, |
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3. |
z = x1 + x2 → max |
при |
2x1 −3x2 ≤ 6, |
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2x + x |
2 |
≤8. |
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4. |
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при |
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z = 3x1 − x2 −2x3 +6x4 − x5 −3 → max |
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x |
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−2x |
+3x |
4 |
− x |
= 2, |
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1 |
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3 |
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5 |
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x2 |
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+ x3 |
− x4 |
+2x5 |
=3. |
Вариант 11
1. z = x1 + 2x2 + x4 + x5 +3 → max при |
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3x |
+2x |
2 |
− x |
=12, |
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1 |
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3 |
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x1 |
−2x2 |
+ x4 |
= −4, |
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− x |
+ x |
2 |
+ x |
=3. |
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5 |
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56
2. z = 6x1 + x2 + 4x3 −5x4 → min |
при |
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3x |
+ x |
2 |
− x |
+ x |
4 |
= 4, |
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1 |
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3 |
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5x1 |
+ x2 |
+ x3 |
− x4 |
= 4. |
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3x1 +4x2 ≥16, |
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3. |
z = x1 |
+5x2 |
→ min |
при |
x1 −2x2 ≤ 2, |
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−3x + x |
≤3. |
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1 |
2 |
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4. |
z = x1 |
−2x2 |
+ x3 + 2x4 +3 → max |
при |
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x |
+3x |
2 |
+2x |
4 |
+ x |
= 2, |
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1 |
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5 |
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x2 |
+ x3 |
−3x4 |
−2x5 |
= 4. |
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Вариант 12 |
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1. |
z = x1 + x2 + x3 + x4 → max |
при |
x |
+3x |
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+7x − x |
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= 6 |
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2 |
3 |
4 |
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2. |
z = x1 +3x2 − x4 −6 → max |
при |
x1 − x2 − x3 +3x4 = 2. |
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x |
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+2x |
2 |
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+ x |
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=15, |
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1 |
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5 |
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5x1 |
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+2x4 |
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=35, |
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− x |
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+ x |
2 |
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+ x |
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=3. |
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3 |
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x1 −2x2 ≤ −2, |
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3. |
z = 2x1 − x2 → max при −3x1 + x2 ≤3, |
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x +4x |
≤16. |
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4. |
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1 |
2 |
при |
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z = 2x1 + x2 +3x3 + x4 + x5 −9 → max |
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2x |
+ x |
2 |
+ x |
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− x |
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=3, |
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1 |
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3 |
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5 |
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x1 |
+2x2 |
+ x4 |
+ x5 |
= 2. |
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57
Вариант 13
1. z = 2x1 −2x2 + 2x3 − x4 +3 → max |
при |
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x |
−2x |
2 |
+ x |
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=1, |
1 |
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3 |
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2x1 |
+ x2 |
− x4 |
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= 4, |
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x |
+2x |
2 |
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+ x |
=5. |
1 |
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5 |
2. z = x1 + 2x2 +3x3 − x4 +3 → max |
при |
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− x |
+3x |
2 |
+ x |
+2x |
4 |
= 4, |
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1 |
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3 |
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x1 |
− x2 |
+ x3 |
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= 0. |
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x |
−2x |
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≤ 2 |
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3. z = 2x1 + x2 → max при |
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2 |
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3x1 −2x2 ≥ −2, |
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4x |
+ x |
2 |
≤12. |
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1 |
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4. z = 2x1 + x2 + x3 + x4 + 4x5 −1 → max |
при |
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2x |
+ x |
2 |
+ x |
4 |
+ x |
= 2, |
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1 |
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5 |
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x1 |
−2x2 |
+ x3 |
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+2x5 |
= 4. |
Вариант 14
1. z = 2x1 −2x2 + 2x3 − x4 +3 → min при |
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x |
−2x |
2 |
+ x |
=1, |
1 |
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3 |
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2x1 |
+ x2 |
− x4 |
= 4, |
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x |
+2x |
2 |
+ x |
=5. |
1 |
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5 |
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2. z = x1 + 2x2 +3x3 − x4 +3 → min |
при |
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− x |
+3x |
2 |
+ x |
+2x |
4 |
= 4, |
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1 |
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3 |
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x1 |
− x2 |
+ x3 |
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= 0. |
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4x |
− x ≥ −1, |
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3. z = −x1 + 2x2 → max при |
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2 |
≤15, |
5x1 +2x2 |
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x |
−2x |
≤ 2. |
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1 |
2 |
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4. z = x1 − x2 −2x3 − x4 + x5 +8 → max |
при |
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x |
+3x |
2 |
− x |
4 |
+2x |
=1, |
1 |
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5 |
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x2 |
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+ x3 +2x4 |
+ x5 |
= 2. |
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Вариант 15 |
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1. |
z = x1 + 2x2 − x3 + x4 |
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→ max |
при |
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x |
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+ x |
−2x +3x |
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=1, |
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1 |
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2 |
3 |
4 |
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2. |
z = 2x1 − x5 → max |
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при |
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2x1 − x2 − x3 +3x4 = 2. |
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x |
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+8x |
2 |
+2x |
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+3x |
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=51, |
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1 |
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3 |
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5 |
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3x1 |
+ x2 |
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+ x4 |
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+ x5 |
= 25, |
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2x |
− x |
2 |
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+ x |
4 |
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=10. |
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1 |
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3x1 + 2x2 ≥ 9, |
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3. |
z = −x1 + 2x2 |
→ min |
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при |
−6x1 + x2 |
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≤ 6, |
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2x − x |
≤ −1. |
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1 |
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2 |
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4. |
z = −x1 + 2x2 + x3 + 2x5 −5 → max |
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при |
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x |
+3x |
2 |
− x |
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+ x |
= 2, |
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1 |
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3 |
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5 |
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x2 |
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+2x3 |
+ x4 |
− x5 |
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= 4. |
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