Kurs_vysshei_matematiki_UP_Berkov_N.A._2007-2
.pdf
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σ12 |
σ22 |
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n1 n2 |
x¯1, x¯2 |
σ12, σ22 |
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n = 120 |
σ = 5
x¯ = 23, 54






















H0 : a = a0 = 23 


H1 : a = 23




























H0 : p = p0 = 0, 12
H1 : p > 0, 12















α = 0, 05









α = 0, 05











ξ



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ξ(t) |
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t |
ξ(t) = ζ ·sin t 

t 0 ζ N (2; 1) 




























t
t
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ξ(t) |
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x(t) |
ξ(1) = ζ · sin 1 |
t = 1 |
ζ |
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−3 |
x1(t) = 2 sin t |
x2(t) = 3 sin t |
m(t) |
t |
mξ (t) = M ξ(t) . |
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m(t) 






















































ξ(t) 
















f (t) 



















m(t) 





















M f (t) |
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M |
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f (t) |
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ξ(t) = f (t) M ξ(t) |
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ξ1(t) |
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M ξ1(t)· |
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ξ2(t) = M· |
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M ξ2(t) |
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σ2(t) 













t 




σξ2(t) = D ξ(t) .






























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σξ (t) = D ξ(t)
























σξ2(t) 
σξ2(t) 0


D f (t) = 0
D f (t) · ξ(t) = f 2(t) · D ξ(t)
D ξ(t) ± f (t) = D ξ(t)












Kξ(t1; t2)

























ξ(t1)
ξ(t2) 
Kξ(t1; t2) = M ξ(t1) − m(t1) · ξ(t2) − m(t2) .
◦
ξ(t) = ξ(t) − m(t),
◦ ◦
Kξ(t1; t2) = M ξ(t1) · ξ(t2) .
σ2 |
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mξ (t) |
(t) Kξ(t1; t2) |
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ξ |
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ζ N (2; 1) |
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mξ (t) = M ξ(t) |
= M (ζ · sin t) = M (ζ) · sin t = 2 sin t, |
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σξ2(t) = D ξ(t) = D(ζ |
sin t) = D(ζ) sin2 t = sin2 t, |
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Kξ(t1; t2) = M (ζ |
sin t1 |
·2 sin t2) (ζ sin· t2 |
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sin t2) |
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= M (ζ |
2)2 sin |
·t1 sin t2− = D(ζ) sin· t1·sin t2 = sin t1 sin |
t2. |
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mξ (t) =−2 |
sin t |
σ2(t) = sin2 t Kξ(t1; t2) = sin t1 |
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sin t2 |
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ξ |
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Kξ(t1; t2) = Kξ(t2; t1) 




















Kξ(t; t) = σξ2(t) 





















|Kξ(t1; t2)| σξ (t1) · σξ (t2) 



Kξ(t1; t2)
ρξ (t1; t2) = σξ (t1) · σξ (t2) .
ρξ (t1; t2) = ρξ (t2; t1)
ρξ (t; t) = 1 
|ρξ (t1; t2)| 1













ξ(t)
ζ(t) 








































Rξζ (t1; t2)

































ξ(t1)
ζ(t2) 
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Rξζ (t1; t2) = M ξ(t1) |
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ζ(t2) . |
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Rξζ (t1; t2) ≡ 0 |
ξ(t) ζ(t) |
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t1, t2 |
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Rξζ (t1; t2) 



































Rξζ (t1; t2) = Rζξ (t2; t1) 
|Rξζ (t1; t2)| σξ (t1) · σζ (t2) 
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Rξξ(t1; t2) = Kξ(t1; t2) |
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Kξ(t1; t2) |
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ξ(t) = ξ1(t) + ξ2(t) |
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Kξ(t1; t2) = Kξ1 (t1; t2) + Kξ2 (t1; t2) + Rξ1ξ2 (t1; t2) + Rξ2ξ1 (t1; t2). |
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◦ |
◦ |
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◦ |
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Kξ(t1; t2) = M ξ(t1) |
ξ(t2) = M ξ (t1) + ξ (t1) |
◦ · |
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ξ (t2) + ξ2 |
(t2) = |
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◦ |
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◦ 2 |
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= M ξ1(t1) · ξ1(t2) + M ξ2(t1) · ξ2(t2) + M ξ1(t1) · ξ2(t2) + M ξ2(t1) · ξ1(t2) =
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+ R (t ; t ) + R |
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= Kξ1 (t1; t2) + Kξ2 (t1; t2) ξ1ξ2 1 2 |
ξ2ξ1 1 2 |
Kξ(t1; t2) = Kξ1 (t1; t2) + Kξ2 (t1; t2).



































ξ1(t)
ξ2(t) Rξ1ξ2 (t1; t2) ≡
≡ 0
Rξ2ξ1 (t1; t2) = Rξ1ξ2 (t2; t1) ≡ 0 

t1; t2
ζ = ξ1 + ξ2i


ξ1
ξ2 






























i
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ζ(t) |
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ζ(t) = ξ1(t) + ξ2(t)i, |
ξ1(t) ξ2(t) |
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(i2 = −1) |
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ζ(t) = ξ1 + ξ2(t)i
ξ2(t) |
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mξ |
(t) = M ξ1(t) + M ξ2(t) i. |
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≡







ξ1(t) 
◦






ζ(t) = ξ(t) − mξ (t) 
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◦ |
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σζ2 |
(t) = M |ζ (t)|2 |
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ζ2(t) ≡ 0 |
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σ2 |
(t) = σ2 |
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|ζ (t)| = "ξ1 |
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σζ |
= M |
|ζ (t)|2 |
= M ξ1 |
(t) + ξ2 |
= M ξ1 |
+ M ξ2 |
= σξ1 |
(t) + σξ2 |
(t). |
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ζ (t1) = ξ1(t1) + ξ2(t1)i ζ (t2) = ξ1(t2) − ξ2(t2)i |
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Kζ (t1; t2) = M ζ (t1) · ζ◦ (t2) . |
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Kζ (t; t) = M ζ(t) · |
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= σζ2(t). |
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= M |ζ(t)|2 |
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ζ(t) |
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Kζ (t1 |
; t2) = Kξ (t1; t2) + Kξ2 (t1 |
; t2) + Rξ2ξ1 (t1; t2) |
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Rξ1ξ2 (t1 |
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ξ1(t) ξ2(t) |
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Kζ (t1; t2) = Kξ1 (t1; t2) + Kξ2 (t1; t2).
ξ(t)







mξ (t) 


















t

Kξ(t1; t2) 














mξ (t) = m, Kξ (t1; t2) = kξ (t2 − t1).
Kξ (t1; t2) = kξ (t2 − t1) = kξ (τ ), |
τ = t2 − t1. |
kξ (−τ ) = kξ (τ ).

































Kξ (t1; t2) 











kξ (t1; t2) = kξ (t2; t1) kξ (−τ ) = kξ (t1 − t2) = Kξ (t2; t1) =
= Kξ (t1; t2) = kξ (t2 − t1) = kξ (τ ).
σξ2(t) = kξ (0) = σξ2.

































Kξ (t1; t2) 



σξ2(t) = Kξ (t; t) = kξ (t − t) = kξ (0) = 



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|kξ (τ )| kξ (0).

































Kξ (t1; t2) 


" "
|Kξ (t1; t2)| Kξ (t1; t1) · Kξ (t2; t2) |kξ (τ )| kξ (0) · kξ (0)
|kξ (τ )| kξ (0) |kξ (τ )| σξ2.



ρ



j, k
M 

j
M