Kurs_vysshei_matematiki_UP_Berkov_N.A._2007-2
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n1
n2 






























































S12
S22 





S12 


























































α 





















H0 
































H0 : σ12 = σ22.
S12
S22
H0 : M (S12 ) = M (S22 ).
S 2 F = S12 .
2







F
k1 = n1 − 1, k2 = n2 − 1
• H0 : σ12 = σ22, H1 : σ12 > σ22
H0 (σ12 = σ22)














F 



P {F > t2(α; k1; k2)} = α. 













t2(α; k1; k2) 




















































F 



































F


> t2(α; k1; k2) 







H0 























α
• H0 : σ12 = σ22, H2 : σ12 = σ22 |
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α/2 |
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P #F < t1 α/2; k1; k2 $ |
= P #F > t2 α/2; k1; k2 $ = |
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t2(α/2; k1; k2) |
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F > t2(α/2; k1; k2) |
H0 |
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α |
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• H0 : σ12 = σ22, 2 |
H3 :2 σ12 < σ22 |
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S1 |
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H3 |
H0 |
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n1 = 12
n2 = 15








S12 = 10, S22 = 5, 5
α = 0, 05
H0 : σ12 = σ22 



















H1 : σ12 > σ22
k1 = 12 − 1 = 11
k2 = 15 − 1 = 14 
S 2
F


= 12 = 1, 82
S2





F 




















t2(0, 05; 11; 14) = 2, 56 




F


< < t2(α; k1; k2) 
















































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H0 : M (ξ1) = . . . = M (ξk) 























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x
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x 



















k
= n (x
j − x)2.
j=1









xij






x
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H0 : M (ξ1) = . . . = M (ξk) 


















































H0






H0 














• S 2 |
< S 2 |
H0 |
• |
S 2 |
> S 2 |
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S 2
F


= S 2 ,
= k − 1 k2 = k(n − 1) |
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t2(α; k1; k2) |
k1 = |
F |
> t2(α; k1; k2) |
H0 |
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α |
F < t2(α; k1; k2) |
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H0 |
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α = 0, 1
x
j




S 2 







S 2 









S 2 























n = 20 k = 4 x¯ = −13, 655
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2 |
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= 61138, 08, |
S 2 |
= 733, 8998, |
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= 27789, 12, |
S 2 |
= 9263, 041, |
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= 33348, 96, |
S |
= 438, 8021. |
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= 27789, 12 + 33348, 96 = 61138, 08. |
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F = |
S 2 |
= |
9263, 04 |
= 21, 11. |
S 2 |
438, 80 |



















k1 =
=k − 1 = 3 






































k2 = k(n − 1) =
=76 
















α = 0, 01 




























F 

















F
F
(0, 1; 3; 76) = 2, 105.

F
> F
α = 0, 1
n = 20











(ξ, ζ)













rxy = 0, 15.
H0
rξζ=0







H1 : rξζ = 0
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T = 0, 15 |
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20 − 2 |
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0, 64. |
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· 1 − 0, 152 |
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H |
1 |
: r |
= 0 |
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xy |
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k = 20 − 2 = 18 |
α = 0, 05 |
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t (0, 05; 18) = 2, 10 |
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T |
< T |
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ξ |
ζ |
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n = |
60 |
m = 50 |
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x¯ = 25 |
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y¯ = 23 |
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σ12 = 5, σ22 = 4 |
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H0 : M (ξ) = M (ζ) |
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H1 : M (ξ) = M (ζ) |
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Z = |
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25 − 23 |
≈ |
4, 95. |
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60 + 4/50 |
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5/ M (ξ) = M (ζ) |
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Φ(Z ) = (1 − α)/2 = (1 − 0, 01)/2 = 0, 495. |
|Z | > Z |
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Z |
= 2, 58 |
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σ2 = 16 


















n = 80






x¯ = 13, 12




















H0 : a = a0 = 12 H1 : a = 12
U = 13, 12 − 12 · √80 ≈ 2, 50. 4


























a = a0 
Φ(Z ) = (1 − α)/2 = (1 − 0, 05)/2 = 0, 475.
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1/2 |
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1/3 |
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1/6 |
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0 |
69,2 |
71,0 |
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72,8 |
74,6 x j |
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(j = 1, 2, ..., s) |
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ui = (xj−1 + xj )/2 |
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s |
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s |
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x¯ = |
miui/n, |
S2 = |
=1 |
miui2/n − x¯2. |
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i=1 |
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= nS2/(n |
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S 2 |
− |
1) |
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x¯ = 71, 876, S = 0, 8982. |
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ξ (xj−1, xj) 




















P = P (x |
j−1 |
< ξ < x |
) = Φ( |
xj − x¯ |
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− |
Φ( |
xj−1 − x¯ |
). |
j |
j |
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S |
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S |
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mj = Pj ·n
























mi 
mj
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m |
m |
(m m )2 |
(mi |
mi)2/m |
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i− i |
i− i |
2− |
i |
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χ |
= 0, 332. |
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s = 9 |
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k |
k = |
9 − 1 − 2 = 6 |
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α = 0, 05






























χ2
χ2 (α, k) = χ2 (0, 05; 6) = 12, 6.




χ2 < χ2














ξ




















n = 30 







rxy = 0, 35 









rξζ = 0.



n = 100
ζ\ξ
rξζ = 0























n = 100 





















x¯ = 210 








































m = 90


y¯ = 208








σ12 = 80, σ22 = 70
















ξ
ζ 









































































H0 : M (ξ) = M (ζ) 














M (ξ) = M (ζ)



p > p






m













ξ




























H



