Метод хорд:

#include <cstdlib>

#include <iostream>

using namespace std;

int main(int argc, char *argv[])

{

double x,fa,fb,b,e,r;

e=0.001;

b=-2;

fb=4*b*b*b-3,5*b*b-3,5*b-0,5;

//cout <<"fb="<<fb<<\n;

x=2;

ssulka1:

fa=4*x*x*x-3,5*x*x-3,5*x-0,5;

//cout <<"fa="<<fa<<\n;

r=(x-(fa*(b-x)/(fb-fa)));

//cout <<"r="<<r<<\n;

if(((x-r)>0&&(x-r)>e)||((x-r)<0&&-1*(x-r)>e))

{

x=r;

goto ssulka1;

}

else

{

//fa=4*r*r*r-3,5*r*r-3,5*r-0,5;

//cout <<"fa="<<fa<<\n;

cout <<"x="<<r<<endl;

}

system("PAUSE");

return EXIT_SUCCESS;

}

Метод дотичних:

#include <cstdlib>

#include <iostream>

using namespace std;

int main(int argc, char *argv[])

{

double f,fcx,x,e,r ;

e=0.001;

x=-2;

ssulka:

fcx=12*x*x-7*x-3.5;

// cout<<"fcx="<<fcx<<endl;

f= 4*x*x*x-3.5*x*x-3.5*x-0.5;

// cout<<"f="<<f<<endl;

r=x-(f/fcx);

// cout<<"r="<<r<<endl;

if(((x-r)>0&&(x-r)>e)||((x-r)<0&&-1*(x-r)>e))

{

x=r;

goto ssulka;

}

else

cout<<"x="<<r<<endl;

system("PAUSE");

return EXIT_SUCCESS;

}

Метод січних:

#include <cstdlib>

#include <iostream>

using namespace std;

int main(int argc, char *argv[])

{

double f,fc,fx,x,e,r,c ;

e=0.001;

x=-2;

ssulka:

c=x-0.1;

fc= 4*c*c*c-3.5*c*c-3.5*c-0.5;

//cout<<"fd="<<fd<<\n;

f= 4*x*x*x-3.5*x*x-3.5*x-0.5;

//cout<<"f="<<f<<\n;

fx=(f-fc)/0.1;

//cout<<"fx="<<fx<<\n;

r=x-(f/fx);

//cout<<"r="<<r<<\n;

if(((x-r)>0&&(x-r)>e)||((x-r)<0&&-1*(x-r)>e))

{

x=r;

goto ssulka;

}

else

cout<<"x="<<r<<endl;

system("PAUSE");

return EXIT_SUCCESS;

}

Висновок

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Люда:

Половинне ділення

#include <cstdlib>

#include <iostream>

#include <math.h>

using namespace std;

int main(int argc, char *argv[])

{

double a,b,c,p,fa,fb,fc,e;

a=-2;

b=2;

e=0.001;

ssulka1:

c=(a+b)/2;

fa=4*a*a*a-3,5*a*a-3,5*a-0,5;

fb=4*b*b*b-3,5*b*b-3,5*b-0,5;

fc=4*c*c*c-3,5*c*c-3,5*c-0,5;

cout<<"pohidni v tochkah nakinciah vidrizkiv"<<endl;

cout <<"fa="<<fa<< endl;

cout <<"fb="<<fb<< endl<<endl;

cout<<"pohidni v novi tochci dlia toho shob provirutu ii znak toist f(x)<0 to - chu f(x)>0 to +"<<endl;

cout <<"fc="<<fc<< endl<<endl;

if (fa<0&&fc>0)

b=c;

else

a=c;

p=b-a;

cout<<"novi vidrizku vuburaish toi de e zmina znakiv [p;a] chu [b;c]"<<endl;

cout <<"p ="<<p<<endl;

cout <<"a="<<a<<endl;

cout <<"b="<<b<<endl;

cout <<"c="<<c<<endl<<endl<<endl<<endl;

if (p>e)

goto ssulka1;

c=(a+b)/2;

cout <<"x="<<c<< endl;

system("PAUSE");

return EXIT_SUCCESS;

}

Метод хорд

#include <cstdlib>

#include <iostream>

using namespace std;

int main(int argc, char *argv[])

{

double x,fa,fb,b,e,r;

e=0.001;

b=-2;

fb=4*b*b*b-3,5*b*b-3,5*b-0,5;

cout <<"fb="<<fb<<endl;

x=2;

ssulka1:

fa=4*x*x*x-3,5*x*x-3,5*x-0,5;

cout <<"fa="<<fa<<endl;

r=(x-(fa*(b-x)/(fb-fa)));

cout <<"r="<<r<<endl<<endl<<endl;

if(((x-r)>0&&(x-r)>e)||((x-r)<0&&-1*(x-r)>e))

{

x=r;

goto ssulka1;

}

else

{

fa=4*r*r*r-3,5*r*r-3,5*r-0,5;

cout <<"fa="<<fa<<endl;

cout <<"x="<<r<<endl;

}

system("PAUSE");

return EXIT_SUCCESS;

}

Січних

#include <cstdlib>

#include <iostream>

using namespace std;

int main(int argc, char *argv[])

{

double f,fc,fx,x,e,r,c ;

e=0.001;

x=-2;

ssulka:

c=x-0.1;

fc= 4*c*c*c-3.5*c*c-3.5*c-0.5;

cout<<"fd="<<fd<<endl;

f= 4*x*x*x-3.5*x*x-3.5*x-0.5;

cout<<"f="<<f<<endl;

fx=(f-fc)/0.1;

cout<<"fx="<<fx<<endl;

r=x-(f/fx);

cout<<"r="<<r<<endl<<endl<<endl;

if(((x-r)>0&&(x-r)>e)||((x-r)<0&&-1*(x-r)>e))

{

x=r;

goto ssulka;

}

else

cout<<"x="<<r<<endl;

system("PAUSE");

return EXIT_SUCCESS;

}

Дотичних

#include <cstdlib>

#include <iostream>

using namespace std;

int main(int argc, char *argv[])

{

double f,fcx,x,e,r ;

e=0.001;

x=-2;

ssulka:

fcx=12*x*x-7*x-3.5;

cout<<"fcx="<<fcx<<endl;

f= 4*x*x*x-3.5*x*x-3.5*x-0.5;

cout<<"f="<<f<<endl;

r=x-(f/fcx);

cout<<"r="<<r<<endl<<endl<<endl;

if(((x-r)>0&&(x-r)>e)||((x-r)<0&&-1*(x-r)>e))

{

x=r;

goto ssulka;

}

else

cout<<"x="<<r<<endl;

system("PAUSE");

return EXIT_SUCCESS;

}