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# Яблонский С1 вариант 29

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1 ( 29)

), ) ) ( .1) , –

. .

,

.

:

P = 25 , q = 1 .

.1

);

(Fi ) = 0; q ×0.5× 22 - 2q ×0.5× 22 + P sin 30 × 4 - M = 0

M = q ×0.5× 22 - 2q ×0.5× 22 + P sin 30 × 4 = 1×0.5× 22 - 2 ×0.5× 22 + 25×0.5× 4 = 48 × .

 ); X i = 0; P sin 30 - X B = 0 X B = P sin 30 = 25×0.5 = 12.5 . (Fi ) = 0; q ×0.5× 22 - 2q ×0.5× 22 + P sin 30 × 4 - × 2 - M = 0

M = q ×0.5× 22 - 2q ×0.5× 22 + P sin 30 × 4 - × 2 = 1×0.5× 22 - 2 ×0.5× 22 + 25×0.5× 4 -12.5× 2 = 23 .

 ); i = 0; P sin 30 - = 0 = P sin 30 = 25×0.5 = 12.5 . i = 0; - q × 2 - 2q × 2 - P cos30 = 0 = q × 2 + 2q × 2 + P cos30 = 1× 2 + 2 ×1×1+ 25×0.5 » 27.651 . 3 (Fi ) = 0; q ×0.5× 22 - 2q ×0.5× 22 + P sin 30 × 4 - × 2 + M = 0 M = -q ×0.5× 22 + 2q ×0.5× 22 - P sin 30 × 4 + × 2 = = -1×0.5× 22 + 2 ×0.5× 22 - 25×0.5× 4 + 27.651× 2 » 7.301 . : ): M A min = 7.301 ; R = = 12.5 ; RB = = 27.651 .