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9.19 Coursework Example: Subsonic Military Aircraft

303

Fuselage

fuselage wetted area = Aw f = 1,474 ft2

fuselage Re = 69 × 1.381 × 106 = 9.53 × 107 (length trimmed to what is pertinent for Re)

use Figure 9.19b to obtain basic CF f = 0.0021

Wing

wing wetted area = Aww = 1,144.08 ft2

wing Re = 15.19 × 1.381 × 106 = 2.1 × 107

use Figure 9.19b to obtain basic CFw = 0.00257

Empennage (same procedure as for the wing)

V-tail wetted area = AwVT = 235.33 ft2

V-tail Re = 8.35 × 1.381 × 106 = 1.2 × 107

use Figure 9.19b to obtain basic CF Vtail = 0.00277

H-tail wetted area = Aw HT = 388.72 ft2

H-tail Re = 9.73 × 1.381 × 106 = 1.344 × 107

use Figure 9.19b to obtain basic CFHtail = 0.002705

9.19.3 Computation of 3D and Other Effects to Estimate Component CDpmin

A component-by-component example follows.

Fuselage

From the previous section, at Mach 0.6, the basic CFf = 0.0021.

3D effects (Equations 9.9, 9.10, and 9.11):

Wrapping:

CFf = CFf × 0.025 × (length/diameter) × Re0.2

=0.025 × 0.0021 × (9.66) × (9.53 × 107)0.2

=0.000507 × 0.0254

=0.0000129 (0.6% of basic CF f )

Supervelocity:

CFf = CFf × (diameter/length)1.5 = 0.0021 × (1/9.66)1.5

= 0.0021 × 0.033 = 0.0000693 (3.3% of basic CFf )

Pressure:

CFf = CFf × 7 × (diameter/length)3 = 0.0021 × 7 × (0.1035)3

=0.0147 × 0.00111 = 0.0000163 (0.8% of basic CF f )

Other effects on the fuselage (intake included – see Section 9.18):

Reference [3] suggests applying a factor of 1.284 to include most other effects

except intake. Therefore, unlike the civil aircraft example, it is simplified to only the following:

Intake (little spillage – remainder taken in 3D effects): 2%

304

 

 

 

Aircraft Drag

 

Table 9.18. Vigilante fuselage CFf correction (3-D and

 

other shape effects)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Item

CFf

% of CFfbasic

 

Wrapping

0.000015

0.6

 

 

Supervelocity

0.000100

3.3

 

 

Pressure

0.0000274

0.8

 

 

Intake (little spillage)

 

2.0

 

 

Total CFf

0.001050

6.7

 

 

 

 

 

 

The total CFf increment is provided in Table 9.11. Table 9.18 lists the components of the Vigilante fuselage CFf.

Therefore, in terms of the equivalent flat-plate area, f, it becomes = CFf × Aw F :

f = 1.067 × 0.0021 × 1,474 = 3.3 ft2

Add the canopy drag, CDл = 0.08 (approximated from Figure 9.4).

Therefore, canopy = 0.08 × 4.5 = 0.4 ft2; f f = 3.3 + 0.36 = 3.66 ft2

Wing

From the previous section, at Mach 0.06, the basic CF = 0.00257.

3D effects (Equations 9.14, 9.15, and 9.16):

Supervelocity:

CFw = CFw × 1.4 × (aerofoil t/c ratio)

= 0.00257 × 1.4 × 0.05 = 0.00018 (7% of basic CFw )

Table 9.18 gives the components of the Vigilante fuselage CF f .Pressure:

CFw = CFw × 60 × (aerofoil t/c ratio)4 × 6 0.125 AR

=0.00257 × 60 × (0.05)4 × (6/3.73)0.125

=0.1542 × 0.00000625 × 1.06 = 0.00000102 (0.04 % of basic CFw )

Interference: Fw for a thin high wing, use 3% of CFw

Other effects:

Excrescence (nonmanufacturing; e.g., control surface gaps):

flap and slat gaps: 2%

others (increased later): 0%

total CFw increment: 12.04%

Table 9.19 lists the components of the Vigilante wing CFw .

Therefore, in terms of the equivalent flat-plate area, f, it becomes =

CFw × Aww :

f w = 1.12 × 0.00257 × 1,144.08 = 3.3 ft2

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