Методы оптимизации / Задания для самостоятельной работы 2 по курсу Методы оптимизации
.docЗадание № 4
Найти extr функции Z (X) и составить двойственную к ней задачу.
при x1 + 2 x2 + 3 x3 ≥ 1, x1 – 2 x2 + x3 ≥ 3, 4 x1 – 3 x2 + 2x3 ≥ –1, x1 + 2x2 + x3 ≥ 2, 2x1 + x2 + 3 x3 ≥ –2 |
при x1 + 2x2 – 3x3 + 1 ≥ 0, 2x1 – x2 + x3 ≥ 5, x1 + x2 ≤ 2, x2 – x3 ≥ –1 |
при 2x2 + 3x3 + x4 – 1 ≥ 0, x1 + 3 x2 + x3 – x4 ≥ 1, ( двойственную к ней задачу решить графическим методом). |
при 2x1 – 2 x2 – x3 ≤ –2, 3x1 + 2 x2 – x3 ≥ 1 (двойственную к ней задачу решить графическим методом). |
при x1 + 2 x2 + 3 x3 ≥ 1, x1 – 2 x2 + x3 ≥ 3, 4 x1 – 3 x2 + 2x3 ≥ –1, x1 + 2x2 + x3 ≥ 2, 2x1 + x2 + 3 x3 ≥ –1 |
при x1 – 2 x2 + 3 x3 ≥ –1, 2x1 – x2 – x3 ≤ –1, (двойственную к ней задачу решить графическим методом). |
при 3 x1 + 4 x3 ≥ –2, x1 – 2 x2 + 3 x3 ≤ –1, 5 x1 – 4 x2 + x3 ≤ –10, 3 x1 + x2 ≤ 4 |
при x1 – 2 x2 + x3 – x4 + x5 = 6, x1 – x3 + 2 x4 + 3 x5 = 8, x1 + x2 – 2x3 + 4 x4 – x5 ≤ 5, x2 – 3 x4 + 2 x5 ≥ 4 |
при x1 – 2 x2 + x3 – x4 + x5 = 6, x2 – 3 x4 + 2 x5 ≥ 4, x1 – x3 + 2 x4 + 3 x5 = 8, x1 + 2 x2 – 2 x3 + 4 x4 – x5 ≤ 5 |
при x1 + x4 + 6 x6 ≥ 9, 3x1 + x2 – 4 x3 + 2 x6 ≥ 2, x1 +2x3 + x5 + 2x6 ≥ 6 |
при x1 + 2 x2 – x3 + 3 x4 = 6, x2 – 2 x3 – x4 = 4, 2x1 + x3 + x4 = 8 |
при –2 x1 + 2 x3 – x4 + x5 ≥ 0, 2 x2 – x3 – x4 + x5 ≥ 0, x1 – 2 x2 – x4 + x5 ≥ 0, x1 + x2 + x3 = 1 |
при 3x1 – 2x2 + x3 ≤ 5, x1 + x2 – 3x3 ≤ 8, –2x1 + 3x2 + x3 = 2 |
при 3x1 + x2 ≥ 1, 2x1 + 3x2 + x3 ≥ 1, 2x2 + x3 + x4 ≥ 0, 2x3 + 3x4 ≥ –2, x1 + 4x2 + 3 x3 + x4 ≥ 0, x1 + 2x2 – 3 x3 – 2x4 ≥ –1, x1 + 3x2 + 3 x3 + x4 ≥ –2 |
при x1 + 2x2 – 3x3 + 1 ≥ 0, 2x1 – x2 + x3 ≥ 4, x1 + x2 ≤ 2, x2 – x3 ≥ –2
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при 2x2 + 3x3 + x4 – 1 ≥ 0, x1 + 3 x2 + x3 – x4 ≥ 1, (двойственную задачу решить графическим методом).
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при 2x1 – 2 x2 – x3 ≤ –2, 3x1 + 2 x2 – x3 ≥ 1, (двойственную задачу решить графическим методом).
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при x1 + 2 x2 + 3 x3 ≥ 1, x1 – 2 x2 + x3 ≥ 3, 4 x1 – 3 x2 + 2x3 ≥ –3, x1 + 2x2 + x3 ≥ 2, 2x1 + x2 + 3 x3 ≥ –2
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при x1 – 2 x2 + 3 x3 ≥ –1, 2x1 – x2 – x3 ≤ –1, (двойственную задачу решить графическим методом).
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при 3 x1 + 4 x3 ≥ –2, x1 – 2 x2 + 3 x3 ≤ –1, 5 x1 – 4 x2 + x3 ≤ –10, 3 x1 + x2 ≤ 4
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при x1 – 2 x2 + x3 – x4 + x5 = 6, x1 – x3 + 2 x4 + 3 x5 = 8, x1 + x2 – 2x3 + 4 x4 – x5 ≤ 5, x2 – 3 x4 + 2 x5 ≥ 4
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при x1 + x4 + 6 x6 ≥ 9, 3x1 + x2 – 4 x3 + 2 x6 ≥ 2, x1 +2x3 + x5 + 2x6 ≥ 6
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при x1 + 2 x2 – x3 + 3 x4 = 6, x2 – 2 x3 – x4 = 4, 2x1 + x3 + x4 = 8
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при –2 x1 + 2 x3 – x4 + x5 ≥ 0, 2 x2 – x3 – x4 + x5 ≥ 0, x1 – 2 x2 – x4 + x5 ≥ 0, x1 + x2 + x3 = 1
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при 3x1 + x2 ≥ 1, 2x1 + 3x2 + x3 ≥ 1, 2x2 + x3 + x4 ≥ 1, 2x3 + 3x4 ≥ –2, x1 + 4x2 + 3 x3 + x4 ≥ 0, x1 + 2x2 – 3 x3 – 2x4 ≥ –1, x1 + 3x2 + 3 x3 + x4 ≥ –1
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x1 ≥ -2 при x1 – 2 x2 + x3 – x4 + x5 = 6, x2 – 3 x4 + 2 x5 ≥ 4, x1 – x3 + 2 x4 + 3 x5 = 8, x1 + 2 x2 – 2 x3 + 4 x4 – x5 ≤ 5
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при x1 + 2 x2 + 3 x3 ≥ 1, x1 – 2 x2 + x3 ≥ 3, 4 x1 – 3 x2 + 2x3 ≥ –1, x1 + 2x2 + x3 ≥ 2, 2x1 + x2 + 3 x3 ≥ –1
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