- •Введение
- •Unit 1.Ordinal and relation signs
- •1.1 Assignments
- •Unit 2.Operation signs and terms
- •2.1 Assignments
- •Unit 3.Operating with fractions
- •3.1Assignments
- •Unit 4.Decimal fractions
- •4.1 TEXT (Read the text and do the tasks that follow.)
- •4.2 Assignments
- •Unit 5.Roots
- •5.1 Assignments
- •Unit 6.Powers.
- •6.1 Assignments
- •Unit 7.Logarithms
- •7.1 Assignments
- •Unit 8.Some algebraic expressions and formulas
- •8.1 Assignments
- •Unit 9.Fundamental symbols and expressions concerning the theory of sets
- •9.1 Assignments
- •Unit 10.Classification of the elementary functions
- •10.1 Assignments
- •Unit 11.Expressions concerning intervals and limits
- •Tasks.
- •1. Analyse and memorize
- •2. Practice reading the following expressions by yourself, check your answer using the keys
- •APPENDIX.
- •KEYS.
- •Список использованной литературы.
- •Приложение Б
- •Приложение В
- •Приложение Г
- •Приложение Д
delta x taken from x sub k equal to a to x sub k equal to b minus delta x equals the integral from a to b of small f of xdx equals capital F of x between limits a and b equals capital F of minus capital F of a equals capital A
•x approaches x nought; or x tends to x nought
•the logarithm of c to the base b is equal to n
•the limit of f of x tends to x nought is not equal to f of x nought
11.1.5.Insert a proper word
1.Open interval can be shown by . . . .
a)parentheses
b)brace
c)point
2.Closed interval can be shown by . . . .
a)square brackets
b)brace
c)round brackets
3.Half open interval can be shown by . . . .
a)brackets
b)round brackets on the left and square brackets on the right
a)infinity
Tasks.
1. Analyse and memorize
|
|
|
|
|
|
m /(m−1) |
|
|
|
|
z |
|
|
ϕ |
(z)= b |
2 |
+ |
|
|
|
|
|
|||||
|
|
|
|
|
|
|
|
|
|
|
cm |
|
|
|
|
|
|
|
|
|
−1
a)ϕ of z is equal to b, square brackets, parenthesis, z divided by c sub m plus two, close parenthesis, to the power of m over m minus 1, minus 1, close square brackets.
b)ϕ оf z is equal to b, multiplied by the whole quantity: the quantity two plus z over c sub m, to the power m over minus 1, minus 1.
|
(t |
)−ϕ |
(t |
|
) |
|
|
|
|
β |
|
|
|
β |
||
ϕ |
|
≤ |
t |
− |
|
|
− Μt |
|
− |
|
|
|||||
|
|
|
|
|||||||||||||
i |
1 |
i |
|
2 |
|
|
|
1 |
|
|
|
|
2 |
|
|
|
|
|
|
|
|
|
|
|
|
|
j |
|
|
|
j |
The absolute value of the quantity ϕ subj of t sub one, minus ϕ sub j of t sub two is less than or equal to the absolute value of the quantity M of t sub one minus β over j, minus M of t sub two minus β over j
|
n |
k = max ∑aij (t); t [a,b]; j =1,2....n |
|
j |
i=1 |
|
27
K is equal to the maximum over j of the sum from i equals one to i equals n of the modulus of a sub i j of t, where t lies in the closed interval a, b and where j from one to n.
limn→∞ |
∫t {f [sϕn (s)]+ ∆n (s)} |
ds = ∫t |
f [sϕ (s)] ds |
|
τ |
τ |
|
The limit as n tends to infinite of the integral of f of s and ϕn of s plus delta sub n of s, with respect to s, from τ to,is equal to the integral of f of s and ϕ of s, with respect to s, from τ to.
Ψn − rs+1 (t)= etλq+s pn−rs +1
Ψ subn minus r sub s plus one of t is equal to p sub n minus r sub s plus 1 times e to the power t times λ sub q plus s.
L+n g = (−1)n (a0 g )(n) + (−1)(n−1)(ag n+1 +... + an g )
L sub n adjoint of g is equal to the minus one to the n, times the n-th derivative of a sub zero conjugate times g, plus, minus one to the n minus one, times the n minus first derivative of a sub one conjugate times g plus and so on to plus a sub n conjugate times g.
dF |
λi(t),t |
|
dF |
λi(t),t |
|
||||
|
|
1 |
|
|
|
1 |
|
||
|
|
|
|
λi,(t)+ |
|
|
|
|
= 0 |
|
|
dλ |
|
|
|
dt |
|
||
|
|
|
|
|
|
|
|
The partial derivative of F of lambda sub i of t and t with respect to lambda, multiplied by lambda sub i prime of t plus the partial derivative of F with arguments lambda sub i of t and t, with respect to t, is equal to zero.
dds2 2y + [1+ b(s)] y = 0
The second derivative of y with respect to s plus y times the quantity 1 plus b of s is equal to zero
f (z)=ϕ€mk + 0(z −1 );(z → ∞;arg z = γ )
f of z is equal to ϕ sub mk hat plus big O of one over the absolute value of z, as absolute z becomes infinite, with the argument of z equals gamma.
28
|
n |
(1 |
− xs2 )ε −1 |
Dn−1 |
(x)= Π |
||
|
s=0 |
|
|
D sub n minus one prime of x is equal to the product from s equal zero to n of, parenthesis, one minus x sub s squared, close parentheses, to the power epsilon minus one.
Κ(t, x)= |
1 |
|
|
∫1 |
|
|
K(t, z) |
dw |
|
2Пi |
|
w− |
|
|
w − w(k ) |
|
|||
|
|
|
|
||||||
|
|
|
|
|
=ρ |
|
|||
|
|
2 |
|
||||||
|
|
|
|
|
|
|
|
|
K of t and x is equal to one over two πi times the integral of K of t and z, over w minus w of x, with respect to w along curve of the modulus of w minus one half, is equal to rho.
d 2u + a4∆∆u = 0;(a > 0) dt 2
the second partial (derivative) of u with respect to t plus a to the fourth power, times the Laplacian of the Laplacian of u, is equal to zero, where a is positive
D (x)= |
1 |
c+i∞ |
ζ k (w) |
xn |
dw;(c >1) |
|
|
|
|||||
k |
2 |
Пi c−∫i∞ |
|
w |
|
|
|
|
|
D sub k of x is equal to one over two πι times integral from c minus ι infinity to c plus i infinity of dzeta to the k of w, x to the w over (or: divided by) w, with respect to w, where c is greater than one.
2. Practice reading the following expressions by yourself, check your answer using the keys
|
2 |
|
1 |
|
|
2 |
|
3 |
|
||
a. |
|
15 |
+ 7 |
|
+ 3(x − 2) |
= 5 |
|
+ |
|
x |
|
7 |
2 |
3 |
4 |
||||||||
|
|
|
|
|
|
|
b. |
lim f (x)= L |
|
|
|||
|
x→1 |
|
|
|||
c. |
f '(x)= lim |
f (x + S )x − f (x) |
|
|||
|
||||||
|
|
|
s→0 |
Sx |
||
d. |
S = |
ds |
|
|
|
|
dt |
|
|
||||
|
|
|
|
29
e.∫ f (x)dx = F (x)+ c
f.x = (− ∞;+∞)
g. |
|
b−x |
f (x |
k |
)Sx = a |
f (x)dx = F(x) |
|
b = F k (b)− F(a)= A |
||||
|
|
|||||||||||
|
lim ∑ |
|
|
∫ |
|
|
|
a |
||||
|
x→0 |
xk =a |
|
|
|
b |
|
|
|
|
||
h. |
lg a3n = lg x = lg |
a2 n |
|
|||||||||
c |
||||||||||||
|
|
|
|
|
|
|
||||||
i. |
M = |
p |
P, g; g ≠ 0 |
|
|
|
|
|||||
|
|
|
|
|
||||||||
|
|
g |
|
|
|
|
|
|
|
|
Check your answer
a.Two seventh times – brace open – fifteen, plus seven times – bracket open – one half plus three times – parenthesis open – x minus two parenthesis, bracket, brace closed – equals five and two thirds, plus three quarters x
b.The limit of f of x as x tends to x sub one is capital l
c.f prime (or: α as h) of x is limit of f of x plus delta x minus f of x over delta x as delta tends to zero
d.S dot equals ds by dt
e.The integral of small f of x dx equals capital F of x plus capital O if capital F prime is equal to small f of x
f.Capital X equals the open interval minus infinity; plus infinity
g.The limit for delta x tending to zero, of the sum of small f of x sub k delta x taken from x sub k equal to a to x sub k equal to b minus delta x equals the integral from a to b of small f of xdx equals capital F of x between limits a and b equals capital F of minus capital F of a equals capital A
h.The logarithm of a to the power of three n equals the logarithm of the square root of x minus logarithm of the nth power of the fraction a squared over c
i.Set of all fractions p/g where p and g are elements of the set of integers and g cannot be zero
30