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Supersymmetry. Theory, Experiment, and Cosmology

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Appendix B

Spinors

B.1 Spinors in four dimensions

In this appendix, we first discuss spinors in four dimensions and introduce two-component spinors, a notation that we heavily use in the superspace formulation of supersymmetry. We then review spinors in higher dimensional spacetime, which are in spinor representations of a general SO(1, D − 1) Lorentz group. This is relevant when we discuss higher dimensions, for example in the context of string theories (chapter 10).

B.1.1 Van der Waerden notation

The metric used is ηµν = (1, −1, −1, −1). Let us consider the spinor representation of the Lorentz group SO(1, 3) which decomposes into irreducible representations of given chiralities: 4 = 2L + 2R. The corresponding spinor fields are called Weyl spinors. We will denote the representation 2L (ξα, α = 1, 2) by (1/2, 0). Under a proper Lorentz transformation1

ξα = M αβ ξβ , det M = 1.

(B.1)

One can then check that, introducing a second such spinor ηα, ξ2η1 − ξ1η2 is invariant under M .

Let us note

ξα = εαβ ξβ

(B.2)

where εαβ is the antisymmetric tensor (εαβ = −εβα, we choose ε21 = 1), invariant under a Lorentz transformation:

εαβ M αγ M β δ = εγδ det M = εγδ .

(B.3)

One may write also

 

ξα = εαβ ξβ

(B.4)

where εαβ is the invariant antisymmetric tensor which is the inverse of εαβ :

εαβ εβγ = δγα

(ε12 = 1).

1Since the dimension of space time is di erent from 2 mod 8, ξα being of definite chirality cannot be chosen real (otherwise it would be a Majorana–Weyl spinor) and M SL(2, C).

420 Spinors

Then using η1 = η2 and η2 = −η1, one may write, using the Einstein convention

ξ2η1 − ξ1η2 = ξ1η1 + ξ2η2 ≡ ξαηα.

Let us note that the spinor ξα introduced in (B.2) transforms as:

ξ = εαβ ξβ

= εαβ M β δ ξδ = εγδ (M 1)γ

α

ξδ

α

 

 

 

 

 

 

 

 

= M

 

1T

γ

ξ

 

 

 

 

(B.5)

where we have used (B.3).

 

α

 

γ

 

 

 

 

One may then check that ξαηα is invariant under a Lorentz transformation:

ξ αηα = M αβ ξβ M 1T α

γ ηγ = M 1M γ β ξβ ηγ = ξβ ηβ .

We will use from now on the following notation:

 

 

 

 

ξαηα ≡ ξη,

ξξ ≡ ξ2.

 

(B.6)

Our convention is that spinors always anticommute. It follows that

ξη = ηξ.

(B.7)

The complex conjugate (ξα) transforms with the matrix M . To make the di erence explicit, one introduces a di erent notation

ξ¯α˙

 

= (M )α˙

 

˙

(B.8)

 

˙

ξ¯β .

 

 

 

β

 

¯α˙ ¯α˙

The ξ form an inequivalent spinor representation: ξ , α˙ = 1, 2 = 2R = (0, 1/2).

˙

We use the antisymmetric tensors ε ˙ and εα˙ β to raise and lower dotted indices

α˙ β

˙ ˙

(ε˙ ˙ = 1 = ε12), and we note:

21

¯

α˙

¯

¯¯

¯2

.

(B.9)

ξα˙

η¯

≡ ξ η,¯

ξξ

≡ ξ

The convention is the following: when indices are not written, undotted indices are descending and dotted indices are ascending.

We will also take as a convention to reverse the order of spinors when performing complex conjugation:

(ξη)= (ξαηα)= η¯α˙ ξ¯α˙ = η¯ξ¯ = ξη¯¯.

(B.10)

B.1.2 Relation of spinors with vectors

As we have just seen, one may form a spin-zero object ξη out of two spinors. One may also form a spin-one object. In order to do so, let us introduce the Pauli matrices σµ,

µ = 0, . . . , 3,

σ0

=

1 0

σ1

=

0 1

0 1

1 0

 

 

σ2 =

0

−i

σ3 =

1

0

(B.11)

 

 

 

 

 

i

0

 

 

0

1

 

and form the vector V

µ

≡ ξ

α

µ

¯α˙

.

 

 

 

 

 

 

σαα˙

ξ

 

 

 

 

Spinors in four dimensions 421

The matrices σµ, being hermitian, satisfy:

(σµ ˙ ) = (σµ )αβ˙ = (σµ†)βα˙ = (σµ)βα˙ .

αβ

 

 

 

 

 

 

One introduces also the matrices σ¯µ defined by:

 

 

σ¯µ αα˙

˙

 

 

 

 

= εα˙ β εαβ σµ ˙

 

 

 

 

 

 

ββ

 

σ0 = σ0, σ¯i = −σi). They have the property

 

 

 

 

σαµα˙ σ¯ναβ˙ + σαν α˙ σ¯µαβ˙

= 2ηµν δαβ

 

σ¯µαα˙ σν ˙ + σ¯ναα˙ σµ

˙

= 2ηµν δα˙˙

,

αβ

 

αβ

 

β

 

from which one deduces

 

 

 

 

 

 

Tr (σµσ¯ν ) = 2 ηµν .

 

One may then show using (B.61) and (B.15) that

 

 

V

µ

Vµ = 2 ξ

2

¯2

.

 

 

 

ξ

 

(B.12)

(B.13)

(B.14)

(B.15)

Hence V µVµ is invariant under the transformations (B.1) and (B.8) and V µ → V µ =

µ

α ¯ α˙

ξ σαα˙ ξ is a Lorentz transformation. The vector representation may thus be referred to as (1/2, 1/2).

B.1.3 Dirac spinors

 

A four-component Dirac spinor describes two Weyl spinors:

 

χα

 

Ψ = ξ¯α˙ .

(B.16)

One may introduce the following basis for gamma matrices, called the Weyl basis:

γµ =

0

σαβµ ˙

, γ5 = γ5 = 0γ1γ2γ3 =

i

µνρσγµγν γργσ =

 

−I 0

(B.17)

 

 

 

σ¯µαβ˙ 0

 

4!

0 I

 

where µνρσ is the fully antisymmetric tensor with the convention:

 

 

 

 

 

 

 

0123 = 1 = 0123.

 

 

(B.18)

Indeed one checks, using (B.14), that

 

 

 

 

 

 

 

 

 

 

µ, γν } = 2ηµν .

 

 

(B.19)

If we define

 

 

 

 

 

 

 

 

 

γ[µγν γρ] =

1

(γµγν γρ + γργµγν + γν γργµ − γν γµγρ − γµγργν − γργν γµ) ,

(B.20)

 

3!

antisymmetric in µνρ, it must necessarily be of the form µνρσAσ where Aσ can be determined by taking specific values of µ, ν, ρ:

γ[µγν γρ] = −i µνρσγ5γσ .

(B.21)

422 Spinors

Similarly, with obvious notation,

γ[µγν γργσ] = −i µνρσγ5.

We will also use

 

1

 

σµν β

0

 

σµν =

 

[γµ, γν ] =

0α

σ¯µνα˙ β˙

,

4

where

 

 

 

 

 

 

 

σµν αβ

=

1

σαµα˙ σ¯ναβ˙

− σαν α˙ σ¯µαβ˙

 

 

 

4

 

σ¯µνα˙ β˙

=

1

σ¯µαα˙ σαβν ˙

− σ¯ναα˙ σαβµ ˙ .

 

 

 

4

 

We have

σµν = 4i µνρσγ5γργσ .

(B.22)

(B.23)

(B.24)

(B.25)

The chirality eigenstates are:

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Ψ

=

1 − γ5

Ψ =

 

χα

and Ψ

=

1 + γ5

Ψ =

0 .

2

0

 

 

L

 

 

 

 

 

 

 

 

R

 

 

 

 

2

 

 

ξ¯α˙

Since we have Ψ¯ = ΨA where2 A =

0 δα˙˙

 

 

 

 

 

 

 

 

 

 

 

β

,

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

δαβ

0

 

 

 

 

 

 

 

 

 

 

 

 

¯

 

 

 

 

 

α

 

0

δα˙˙

 

 

β

 

 

 

 

 

 

 

Ψ = (χ¯α˙

ξ )

δαβ

0

= (ξ

 

 

χ¯

˙ ).

(B.27)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

β

 

One then easily proves that, for two Dirac spinors Ψ1 and Ψ2:

 

 

 

¯

 

Ψ2 = ξ1 χ2

 

 

¯

 

 

 

 

 

 

 

 

 

 

 

Ψ1

+ χ¯1 ξ2

¯

 

 

 

 

 

 

 

 

 

¯

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Ψ1

γ5 Ψ2 = −ξ1 χ2 + χ¯1 ξ2

 

 

 

 

 

 

 

 

 

¯

 

γ

µ

Ψ2 = ξ1

σ

µ

¯

 

 

 

µ

χ¯1

 

 

 

Ψ1

 

 

ξ2 − χ2 σ

 

 

 

 

 

¯

 

γ

µ

γ

5

Ψ2 = ξ1σ

µ ¯

+ χ2 σ

µ

χ¯1.

(B.28)

 

 

Ψ1

 

 

ξ2

 

The completeness of the 16 Dirac matrices can be used to derive the Fierz rearrangement formula for two anticommuting spinors

Ψ2Ψ¯ 1 =

1

1 Ψ¯

1Ψ2

1

γµ

Ψ¯ 1

γµΨ2

1

σµν

Ψ¯ 1

σµν Ψ2

4

4

8

+

1

γµγ5

Ψ¯ 1γµγ5Ψ2

1

γ5

Ψ¯ 1γ5Ψ2

.

(B.29)

 

 

4

4

2A is the matrix that intertwines the representation γµ with the equivalent representation γµ:

µA1 = γµ

(B.26)

(C plays a similar rˆole between γµ and −γµT , as seen from (B.31)). As is well known, A coincides

numerically with γ0. We refrain from using the same notation because the two-component indices do not match as can be seen by comparing the explicit form of A with (B.17).

Spinors in four dimensions 423

The charge conjugation matrix C reads, in this notation,

C =

ε

0

 

 

 

C1 =

εαβ 0

 

0αβ

εα˙ β˙

,

 

 

0 εα˙ β˙

and satisfies

 

 

 

 

C1

=

 

 

 

 

 

 

 

 

 

 

 

C γT

 

 

γ

.

 

 

 

 

 

 

 

 

µ

 

 

 

 

µ

 

 

 

 

 

The charge conjugate spinor Ψc is thus simply:

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

ξα

 

 

 

 

 

 

 

 

Ψc = CΨ¯ T

= χ¯α˙ .

 

 

 

 

Thus a Majorana mass term reads:

 

 

 

 

 

 

 

 

 

 

 

 

 

¯ c

 

α

 

¯

¯α˙

 

 

 

 

c

 

 

 

 

c

 

 

 

= Ψ

 

 

 

ΨR .

Ψ

Ψ = χ

χα + ξα˙ ξ

 

R ΨL + Ψ L

The following properties may be checked from (B.28) and (B.64):

¯ c

c

¯

Ψ1,

 

Ψ1

Ψ2

= Ψ2

 

¯ c

γ5

c

¯

γ5Ψ1,

 

Ψ1

Ψ2

= Ψ2

 

¯ c

 

c

¯

,

Ψ1γµ

Ψ2

= Ψ2γµΨ1

¯ c

γ5

c

¯

γµγ5Ψ1,

Ψ1γµ

Ψ2

= Ψ2

and more generally

¯ c

 

 

c

n ¯

· · · γµ1 Ψ1,

Ψ1

γµ1 · · · γµn Ψ2

= () Ψ2γµn

¯ c

 

 

c

¯

 

Ψ1γµ1

· · · γµn γ5Ψ2

= Ψ2γµn · · · γµ1 γ5Ψ1,

and

 

 

 

 

 

¯

 

· · · γµn Ψ2

 

n ¯ c

c

Ψ1γµ1

 

= () Ψ1γµ1 · · · γµn Ψ2,

Ψ¯ 1γµ1 · · · γµn γ5Ψ2

= ()n+1Ψ¯ 1c γµ1 · · · γµn γ5Ψ2c .

The Majorana condition

 

 

 

 

 

 

 

 

 

 

¯ T Ψ = CΨ

reads simply

(B.30)

(B.31)

(B.32)

(B.33)

(B.34)

(B.35)

(B.36)

(B.37)

χα = ξα.

(B.38)

Thus a Majorana spinor ΨM is expressed in terms of a single two-dimensional spinor as

χα

 

ΨM = χ¯α˙ .

(B.39)

Majorana spinors have the following properties, as can be checked from (B.35) and (B.36):

 

¯

 

 

 

 

n ¯

 

 

 

 

Ψ1γµ1 · · · γµn Ψ2

= () Ψ2γµn · · · γµ1 Ψ1,

 

¯

 

 

· · · γµn γ5Ψ2

¯

· · · γµ1

γ5Ψ1,

(B.40)

Ψ1γµ1

= Ψ2γµn

and

 

 

 

 

 

 

 

 

 

 

¯

γµ1

 

· · γµn Ψ2

 

n ¯

 

 

 

 

Ψ1

·

 

= ( ) Ψ1γµ1 · · · γµn Ψ2,

(B.41)

Ψ¯ 1γµ1

 

γµn γ5Ψ2

= ()n+1

Ψ¯ 1γµ1

· · ·

γµn γ5Ψ2.

 

 

· · ·

 

 

 

 

 

424 Spinors

B.2 Spinors in higher dimensions

We first review the representations of the group SO(2n) before defining spinors in D dimensions.

B.2.1 Representations of SO(2n)

SO(2n) is defined as the group of 2n-dimensional orthogonal matrices Λ of determinant unity, i.e.

ΛT Λ = 1, Det Λ = 1.

(B.42)

Turning to the algebra, Λ = eJ 1 + J + · · · , these two conditions become

 

JT = −J.

(B.43)

There are 2n(2n − 1)/2 independent 2n-dimensional matrices satisfying (B.43). Hence the dimension of the SO(2n) algebra is n(2n − 1). A basis of generators is

(1 ≤ K, L ≤ 2n)

 

 

 

·

 

·

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

1

 

1 · · ·

 

 

 

 

 

· · · · · · · · ·

K

 

 

 

 

 

·

 

·

L

 

 

 

JKL =

 

 

 

 

.

(B.44)

 

 

 

 

 

 

 

 

 

 

 

 

· · ·

·

· · · · · · · · ·

 

 

 

 

 

 

 

·

 

 

 

 

 

 

 

K

 

L

 

 

 

From this one obtains the commutation relations

[JIJ , JKL] = δJK JIL − δJLJIK + δILJJK − δIK JJL ,

(B.45)

which define the SO(2n) algebra.

A maximal set of commuting generators (known as the Cartan subalgebra) is given by the n generators3 Nk ≡ J2k−1,2k, k = 1, . . . , n. The number of such generators is the rank of the algebra, hence the rank of SO(2n) is n.

The representation (B.44) is the vector representation of dimension 2n. The dimension of the algebra gives the dimension of the adjoint representation: n(2n − 1). In the following, we build the spinor representations of dimension 2n−1.

The standard procedure is to consider a set of n fermion creation and annihilation

operators ak, ak, k = 1, . . . , n:

 

&ak, al' = δkl, [ak, al] = 0 = &ak, al' .

(B.46)

One then constructs a Fock space by defining a vacuum |0 and acting on it with creation operators:

|

0

 

,

a

0

,

aa

|

0

 

, . . . ,

a

· · ·

a0

 

(B.47)

 

 

k

|

 

k l

 

 

1

n|

 

 

form a set of 2n independent states.

 

 

 

 

 

 

 

 

 

 

3Each of them is a block diagonal matrix with only nonzero block

0 1

in the (2k − 1, 2k)

1 0

entry.

Spinors in higher dimensions 425

The following 2n matrices

ΓK ≡ aK + aK , K = 1, . . . , n

ΓK

aK−n − aK

−n

, K = n + 1, . . . , 2n

(B.48)

ı

 

act on this 2n-dimensional Fock space. They satisfy the Cli ord algebra

 

 

{ΓK , ΓL} = 2δKL ,

(B.49)

and are therefore generalizations of the gamma matrices to dimensions higher than four. The point of interest to us is that the Σ matrices built out of them have precisely the commutation relations (B.45) of SO(2n):

ΣKL

1

K , ΓL]

 

 

4

 

IJ , ΣKL] =

δJK ΣIL δJLΣIK + δILΣJK δIK ΣJL .

(B.50)

Since the ΣKL matrices act on the 2n-dimensional Fock space, we have constructed a (2n)-dimensional representation known as the spinor representation.

This representation is not irreducible, however. Indeed, define

Γ(2n+1) ≡ ın(2n−1)Γ1 · · · Γ2n, Γ(2n+1) 2 = 1 . (B.51)

Let us choose a Fock vacuum of definite chirality, i.e. Γ(2n+1)|0 = +|0 . Then, since

$Γ2n+1, ak%

= 0,

 

 

 

 

Γ(2n+1)ak

1 · · · akp |0 = (1)pak

1 · · · akp |0 ,

(B.52)

and we can divide our Fock space (B.47) into states of opposite chirality. We have therefore built two (2n−1)-dimensional irreducible representations, the spinor representations of SO(2n) of opposite chirality.

B.2.2 Spinors in D-dimensional spacetimes

Consider a D-dimensional Riemannian4 manifold. We need to introduce the tangent space Tp, the set of tangent vectors at point p which is generated by the infinitesimal displacements dxM , M = 1, . . . , D, at this point. The discussion will rest on the notion of tangent space group, the set of orthogonal transformations on Tp. Writing such a transformation as dxM = ΛM N dxN , the property of orthogonality is expressed as usual by (gMN is the metric of the manifold)

gM N dxM dxN = gMN ΛM P ΛN S dxP dxS = gP S dxP dxS

 

that is

 

gM N ΛM P ΛN S = gP S .

(B.53)

4A Riemannian manifold is a smooth manifold with a symmetric metric tensor gM N such that the bilinear form gM N V M W N (V, W Tp) is nondegenerate (gM N V M W N = 0 for all V i W = 0).

426 Spinors

In the case of Minkowski spacetime M4, with gµν = (+1, −1, −1, −1), this tangent space group is the proper Lorentz group SO(1, 3) (if we restrict to det Λ = +1). For a D-dimensional manifold, with metric gM N = (+1, −1, −1, . . . , −1), the tangent space group is SO(1, D − 1).

The corresponding Cli ord algebra reads

 

{ΓM , ΓN } = 2gM N ,

(B.54)

where the gamma matrices have dimension 2[D/2], with [D/2] the integral part of D/2. As in the previous section, the generators of SO(1, 9) are the ΣM N = 1/4[ΓM , ΓN ].

Just as before, one may introduce for even spacetime dimension D, the matrix Γ(D+1) which anticommutes with all gamma matrices5:

Γ(D+1) ≡ ı(D−2)/2Γ0Γ1 · · · ΓD−1 .

(B.55)

We note that γ5 defined in (B.17) is precisely Γ(5) for D = 4. One then defines the chirality eigenstates by the condition:

Γ(D+1)ΨL,R = ΨL,R .

(B.56)

Thus, a Dirac spinor has 2D/2 degrees of freedom whereas a Weyl6

fermion has

2(D−2)/2.

 

Can we always define a Majorana spinor? In order to answer this question, let us define the matrix B which intertwines the representation ΓM with the equivalent

representation ΓM :

 

BΓM B1 = ΓM .

(B.57)

We have BB = ηI with η = ±1. Clearly, B = CΓ0 where C is defined as in (B.31) by

C1ΓM C = ΓM T .

(B.58)

If a spinor field Ψ of charge q satisfies the Dirac equation coupled with the electromagnetic field, one easily checks that B1Ψ satisfies it with charge −q: it is associated with the antiparticle. One defines a Majorana spinor by the condition that particle and antiparticle are identical:

Ψ = BΨ .

(B.59)

This Majorana condition is easily shown (see Exercise 6) to be equivalent to the condition (B.32) given above. It obviously implies η = 1.

It turns out that η can be computed as a function of the dimension D (see [331]

for a proof):

π

(D + 1)' .

 

 

 

 

 

η = 2 cos &

(B.60)

 

4

5The di erence in the overall factor between (B.51) and (B.55) is due to the change of metric between Euclidean and Minkowski. In both cases, it is chosen in such a way that Γ(D+1) 2 = 1.

6In the case of odd dimension D , there are no Weyl spinors. If we write D = D + 1 where D is even, then Γ0, Γ1, . . . , ΓD−1 and iΓ(D+1) given in (B.55) yield a set of gamma matrices. In what follows, we only consider the case of even D.

Exercises 427

Thus η = 1 for D = 2, 4 mod 8. One can then show that there exists a representation of the gamma matrices which is purely imaginary, in which case B = 1 and C = Γ0: the Majorana condition reads Ψ = Ψ. A Weyl condition (B.56) is then only possible if Γ(D+1) in (B.42) is real i.e. for D/2 odd. Hence one can define a Majorana–Weyl spinor only in D = 2 mod. 8 dimensions.

Further reading

J. Wess and J. Bagger, Supersymmetry and Supergravity, Princeton series in physics, Appendix A (note the opposite metric signature in this reference).

J. Scherk, Extended supersymmetry and supergravity theories, in Advanced Study Institute on Gravitation: Recent Developments, Carg`ese, 1978.

Exercises

Exercise 1 Prove the following relations which you will find to be very useful

ξα ξβ = 12 εαβ ξ2,

¯α˙

 

˙

1

 

α˙

˙

¯2

 

¯β

=

 

 

ε

β

,

ξ

ξ

 

2

 

 

 

ξ

Deduce that

ξα ξβ

=

1

 

εαβ ξ2,

 

2

 

 

 

 

 

 

 

 

 

¯

¯

=

1

¯2

 

ξα˙

ξβ˙

2

εα˙ β˙ ξ

.

 

 

 

 

 

1

 

 

 

θσµθ¯ θσν θ¯ =

 

ηµν θ2θ¯2.

2

Exercise 2 Prove that

 

 

 

 

 

 

 

 

 

χ σ

µ

¯

¯

 

 

µ

χ,

 

 

ψ = −ψ σ¯

 

χ σµ ψ¯ = ψ σµ χ¯.

Exercise 3 Use

 

 

 

 

 

 

 

 

 

σµ

 

σ

 

˙

= 2εαβ ε

˙

αα˙

 

µββ

 

 

α˙ β

to show the following Fierz reordering formula:

 

 

 

(ψ1ψ2) (χ¯1χ¯2) =

1

(ψ1σµ

χ¯1) (ψ2σµχ¯2) .

 

 

 

 

2

 

 

 

 

 

Exercise 4 Show the following useful relations:

(σµν )

 

β =

i

 

µνρσ (σρσ)

β

,

α

 

α

 

2

 

 

 

 

 

 

 

 

 

σµν )α˙

β˙ =

i

µνρσ σρσ)α˙

β˙ ,

 

2

(B.61)

(B.62)

(B.63)

(B.64)

(B.65)

(B.66)

(B.67)

428 Spinors

(σµν σρ)αβ˙

=

1

gνρgµλ − gµρgνλ − i µνρλ σλαβ˙

,

 

2

 

(σµσ¯νρ)αβ˙

=

1

gµν gρλ − gµρgνλ − i µνρλ σλαβ˙

,

 

 

 

2

 

σµν σ¯ρ)αβ˙

=

1

gνρgµλ − gµρgνλ + i µνρλ σ¯λαβ˙

,

 

 

 

2

 

σµσνρ)αβ˙

=

1

gµν gρλ − gµρgνλ + i µνρλ σ¯λαβ˙

.

(B.68)

 

2

Hints: To derive (B.67), use (B.25).

Exercise 5 We construct the generators of the Lorentz group in the spinor representation.

 

Let Pµ be a covariant vector. Define Pαα˙ ≡ Pµσαµα˙ or alternatively

 

 

 

 

Pµ

=

 

1

 

σ¯µαα˙ Pαα˙ .

 

 

 

(B.69)

 

 

 

2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(a)

Using (B.69), express the Lorentz transformation Lµ ν in the vector representation

 

in terms of M 1T

 

β , (M )α˙

˙

and σ matrices.

 

 

 

 

 

 

α

β

 

 

 

 

 

 

 

 

 

 

(b)

Making these transformations infinitesimal :

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Lµ ν = δµν + ωµ ν

 

 

 

 

 

M 1T

 

α

β = δβ

+ η

α

β

 

 

 

 

 

 

 

 

 

α

 

 

 

 

 

 

 

 

α˙

˙

α˙

 

α˙

 

 

 

 

 

(M )

= δ ˙

+ η¯

˙

 

 

 

 

 

 

 

 

 

 

β

β

 

 

β

 

 

 

show that

 

M 1T α

 

 

 

 

 

 

 

 

 

 

 

 

 

 

β = δαβ + ωµν (σνµ)α

β .

(B.70)

Exercise 6 Show that the Majorana condition (B.59) is equivalent to the condition (cf. (B.32) and (B.37) in four dimensions)

Ψ = Ψ

c

¯ T

(B.71)

 

CΨ ,

¯ 0 where Ψ = Ψ Γ .

Hints: Using (B.59) and C2 = 1, we have

CΨ¯ T = CΓ0T Ψ = CΓ0T BΨ = Γ0CBΨ = Γ0C2Γ0Ψ = Ψ .