3. Порядок выполнения работы
1. Составить карту Карно.
В соответствии с комбинационной таблицей логической функции от 4-x переменных представить соответствующую карту Карно. Вариант комбинационной таблицы выбирается преподавателем из указанных в табл. 7.
В представленной карте Карно выбрать группы, содержащие логическую “1” или логический “0”.
Определить выражение, описывающее соответствующую логическую функцию.
Таблица 7
|
Х1 |
Х2 |
Х3 |
Х4 |
Номера вариантов | |||||||||||||||||
|
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
12 |
13 |
14 |
15 |
16 |
17 |
18 | ||||
|
0 |
0 |
0 |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
1 |
0 |
1 |
0 |
0 |
0 |
0 |
|
0 |
0 |
0 |
1 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
|
0 |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
1 |
0 |
1 |
0 |
0 |
0 |
0 |
|
0 |
0 |
1 |
1 |
0 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
0 |
0 |
0 |
1 |
|
0 |
1 |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
|
0 |
1 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
0 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
1 |
|
0 |
1 |
1 |
0 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
|
0 |
1 |
1 |
1 |
0 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
|
1 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
0 |
|
1 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
0 |
1 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
|
1 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
0 |
|
1 |
0 |
1 |
1 |
0 |
0 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
0 |
0 |
0 |
0 |
1 |
|
1 |
1 |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
|
1 |
1 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
1 |
|
1 |
1 |
1 |
0 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
|
1 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
|
0 |
0 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
|
0 |
0 |
0 |
1 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
|
0 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
0 |
0 |
0 |
1 |
|
0 |
0 |
1 |
1 |
0 |
0 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
|
0 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
0 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
|
0 |
1 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
0 |
0 |
|
0 |
1 |
1 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
1 |
0 |
0 |
|
0 |
1 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
0 |
0 |
|
1 |
0 |
0 |
0 |
0 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
|
1 |
0 |
0 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
|
1 |
0 |
1 |
0 |
0 |
0 |
0 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
1 |
0 |
0 |
0 |
1 |
|
1 |
0 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
1 |
0 |
0 |
1 |
0 |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
|
1 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
|
1 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
0 |
1 |
0 |
1 |
0 |
0 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
0 |
|
1 |
1 |
1 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
0 |
|
1 |
1 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
1 |
0 |
1 |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
0 |
1 |
0 |
Преобразовать его с помощью теорем (2) с целью использования в нем как можно большего числа функций
,
.
В соответствии с выражением логической функции определить реализующую его комбинационную схему.