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  1. (3) Force due to internal pressure at reducer

  2. for the pipe on upstream P3 = HT(AX-A^

  3. for the pipe on downstream P3' =HT’ (Ax' — A2')

  4. where, HTt HT' : Internal pressure at the center of the reducer (tf/m2), design pressure for normal condi­tion and the static pressure for- seismic con­dition

  5. Ax, Ax' : Sectional area of the upstream pipe of the reducer (m2)

  6. >42, /12' : Sectional area of the downstream pipe of the reducer (m2)

  7. 4

  8. where k: Stress of concrete (kgf/cm2)

  9. P: Load per wheel (kgf)

  10. bf. Bottom width of wheel rail (cm)

  11. Em: Concrete modulus of elasticity = 1.4 x 105 (kgf/cm2)

  12. E: Steel)irfbdulus of elasticity =’2.1 x 106 (kgf/cm2)

  13. I: Geometrical moment of inertia of wheel rail (cm4)

  14. 2a: Stress distribution length of concrete at the bottom of the wheel rail (cm)

  15. M: Bending moment of the wheel rail (kgf-cm)

  16. * = 2.34 *= 1.77 *=1.60 *=1.73

  17. Fig. 2.71-1 Shapes & Factors of the Trash Rack

1

where <jf: Yield point of material (kgf/cm2)

g= 1.5 —0.5- ——

(1 + 0.002—

ko = 0 by grouting, etc., and when the initial compressive stress av is acting on pipe — should be applied in place of — in the fTf' first term of the equation.

2. , H n2/2 \2 + 12r0'2 (n2-l) 14—7-77

\ ro 2 /

This formula;is the one for buckling of a cylinder when the dis­placement is zero due to restraint at both ends. But Nagashima and Kozuki analyzed based on the following concepts:

3 Pipes between tstiifgiiers are also restrained from their displace­ment by co^pr.eteand bedrock like the case without stiffeners.

4A pipe’s displacement at both ends, i.e. a stiffener’s portion, is not zero.

*

According to their analysis, critical buckling pressure of the pipe with stiffeners can be obtained by applying the following T instead of actual stiffener’s interval / to the Timoshenko’s formula.

5 With water fully filled in the pipe

6If reacting forces act as illustrated in Figure 1.29-1, circumferential cross jection forces of a ring girder can be given from the following formulae: T=Q(K\ + BKz)

M^QtRKi+XKJ

S=Q(Ki + CK6')

7Centrifugal foce Pe and unbalanced force Pn, which act at bends can be determined from the following formulae: