шпора по физике за первый семестр / Следствия из преобразований Лоренца

яю!;54AB28O 87 ?@5>1@07>20=89 >@5=F0:

1. !>:@0I5=85 4;8==K 4286CI8EAO >1J5:B>2:

l = x2  x1 = (x2  vt  x1  vt ) / (:>@5=L 1  v(cn/2) / A (AB.2)) ;

l = l * :>@5=L 1  v (AB2) / A (AB.2) ; арl < l

BAN40 284=>, GB> 2 42865=88 A8AB5<K >BAG5B0 ?@>8AE>48B A>:@0I5=85, ?>?5@5G=K5 @07<5@K B5;0 =5 87<5=ONBAO.

2. 0<54;5=85 4286CI8EAO G0A>2:

delta t = t2  t1 = (t2 + v x / c (AB.2)  t  v x / c (AB.2)) / (:>@5=L 1  v (cn/2) / c (AB.2)) = t2  t1 / :>@5=L & = delta t / :>@5=L& ар delta t < delta t

3. 0:>= A;>65=8O A:>@>AB59:

Vx = dx / dt ; dx = dx + vdt / :>@5=L& = dt (v + v) / :>@5=L& ;

dt = (dt + dx v / c (AB.2)) / :>@5=L& = dt (1 + [v/c (AB.2)] *dx /dt ) / :>@5=L&

vx =(vx + v) (:>@5=L 1 + v vx / c (AB.2))

vy = vy (:>@5=L& ) / 1 + v vx / c (AB.2) ;vz=0=0;>38G=> vy; x, y, z -8=45:AK

7 MB8E A>>B=>H5=89 284=>, GB> 2 >1I5< A;CG05 =0?@02;5=85 A:>@>AB59 2 k 8 k =5 A>2?040NB.