- •Qfr £t¶qpht0i 3hpqiptii'ip£khj
- •9Fipbpaoh dH '9b6ndm79f6q ’ ’q :I›‹asxonaj
- •0 Point seven
- •It}]obo1)hhx h85h8'4ohHt
- •If a resistor has a resistance of only 2 ohms but its current-carrying
- •I . A resistor is used a) to measure the resistance.
- •Voltage source is applied b) to the insulator.
- •Current passes through conductor a) easily.
- •Trensformem
- •In a circuit.
- •Incandescence ljnken'desnsl «a×m, «×mוa«×«
- •Incandescent lamp [,inken'desnt lamp] nauna iiaxaniiaaiiii×
- •Translate into Russtsn:
- •Components of Electric Circuits
- •In case the motor, when starte d • ºR³
- •In case the curvature winding is overheated.
- •In case of abnormal motor speed.-
- •In case rotor brushes against Stator.-
- •Protection Against Environmental Pollution
- •2. Grammar Revision
- •20 Twcaty ['twenti]
- •7HB Uarb
- •It was b. Pascal that invented the mechanical computer.
- •Punniuatinn iTlarha
- •3. Materials for Reading and Discussing MaTepnansi gnR vt Hne n o6cyx‹qéHnr LlJorh uiith a Oictionarg
- •3Eyxu azrenudcxoco saszxc
- •2. Civc the title to the text.
- •Voltage Velues
- •Reed tbe text and find in it tbe answers to the questions tbat fotlow iL
- •WJtat is the above article about?
- •Read the text and find in it the answcm to the questions that follow iL
- •Generators and underground transmission lincs can be supcrcoolcd.
- •W’hat ¶as is the space filled with?
- •W’hy should the system be protected?
- •4. What arc the advantages of the device?
- •Contectom Type 370
- •2. W'hIch arc the functions of cach of these parts?
- •2. What did the emission result in?
- •Raaignmenta in lLlriting
- •I) Titles.- Two-phase System; Single-phase System, Three-phase Sys-
- •1. An a.C. Distributing system employing a single
- •2. The transmission of heat from places of higher
- •Direction.
- •4. A device for producing an elecnomotive force
- •Irregular Uarba
- •Ahf'jihhckhii r3hIk
- •Y•ie6niiicii II y•ie6HhIe noco6iiR
- •JlyroBaii a.Ji. AhFaiiiiciciiii r3hIk j(jir ct(tDhTéJIhHhIx cIféttHtt-
- •JlyroBau a.Ji. Coapexieuilhlé c(téJ(ctBlt cBiiiH. Vuc6iioe noco-
0 Point seven
0.7 nought point seven zero point seven
0.002 — zero point two zeros two
1.I — one point one
three
and
a
half 5.36
—
five
point
three
six
fwd fiJld B SGVéR 65.57 — sixty-five point five scvun 7
6— — six and five sevenths
Re«d iscse common ×nd declmel fractions:
-
1/3
2/5
5/8
7 1/2
9 5/8
15 8/9
0.23
0.009
10.01
205.35
79.31
0.0003
1. a) Cover the right column end read the Englhh words. Trensletc them into Russian and check your translation.
b) Cover the left column and trenslete the Russian words back into
currant [1‹arant]
to
suppose lsa uzl
R = Resistance equals voltage divided by current.
equals
voltage
divided
by
resistance.
V
=
IR
Voltage
equals
current
times
resistance.
R=? How much is the resistance?
2. Solve the following problems end read them.
Model.-- How much is 10 times 4?
- 10 times 4 equals 40.
I)
7
x
7
-
5)
350
x
2
=
9)
49
:
7
- 13)20.25
x
30
2)
2.5
x
3
=
6)
3.5
x
10
-
10)
75
:
25
-
14)
7.5
:
5
-
3)
10,050
x
2
= 4)
100
×
0.5
-
7)
2,000
x
5
- 8)
0.
12
×
2
-
11)
3,500
:
35
- 12)
10.25
:
10
-
IS)
40.8
:
4
= 16)
15.5
:
3-
Solve the following problems using the formulas of Ohm's Lew.
Model.-- Current equals 5 amp; resistance equals 10 ohms. How much is the voltage?
— Voltage equals current times resistance. 5 x 10 -50 V
-
I) R = 80 ohms
2) R - 10.25 ohms
3) V = 50.05 V
V -55 V
I = 35 amp
I - 120 amp
I = ?
V - ?
R = ?
4) I = 10,500 amp V -2,000 V
R = 2
5) V -20.05 V
R -0.015 ohm I = ?
6) I = 0.24 amp
R = 1.36 ohms V = ?
Peir work. Meke up similar problems of your own. Ask your group- mate to solve them.
e) Cover the right column end read the English words. Tmnslete
them into Russten end check your trensletion.
Cover the left column end trenslete the Russian words beck into English.
circuit conductor function difference
short trouble no
to reduce
to supply to connect
to compare (with) to pass through
to result in
to result from
['sa:kit] [kan'dxkta] [1xgkjn] ['difrans]
[’trxbl] [nou] [ri'dju:sJ lsa'plail [ka'nekt]
