- •Interval estimation
- •6.1. Introduction
- •6.2. Confidence interval and confidence level
- •6.3. Confidence intervals for the mean of population that is
- •6.4. Confidence intervals for the mean of population that is
- •6.5. Confidence intervals for the mean of a normal distribution:
- •6.5.1. Student’s t distribution
- •6.5.2. Confidence interval for : small samples
- •6.6. Confidence intervals for population proportion: Large samples
- •6.7. Confidence intervals for the difference between
- •6.7.1. Confidence intervals for the difference between
- •6.7.2. Confidence intervals for the difference between
- •6. 8. Confidence interval for the difference between the population means: unknown population variances that are assumed to be equal
- •6. 9. Confidence interval for the difference between the
- •6. 10. Confidence interval for the variance of a normal
- •6.11. Sample size determination
- •6.11.1. Sample size determination for the estimation of mean
- •6.11.2. Sample size determination for the estimation of proportion
6. 8. Confidence interval for the difference between the population means: unknown population variances that are assumed to be equal
Let
us consider the
confidence interval estimation procedure for the difference between
the means of the populations when the population have normal
distributions with equal variances, i.e.,
.
We will again be assuming that independent random samples are
selected from the populations. In this case the sampling distribution
of
is
normal regardless of the sample sizes involved. The mean of the
sampling distribution is
.
Because
of the equal variances
,
we can write
If
the variance
is
known, then confidence interval population means can be found easily.
However, if
is
unknown, the two samples variances,
and
,
can be combined to compute the following estimate of
:
The
process of combining the results of the two independent samples to
provide an estimate of the population variance is referred to as
polling,
and
is
referred to as polled
estimator of
.
Definition:
Suppose
that two samples of sizes
and
are
selected from normally distributed population with means
and
,
and a common, but unknown variance
.
If sample means are
and
,
sample variances are
and
,
then
confidence
interval for
is
given by
were S is given by
and
is
the number for which
.
The
random variable t
follows to the Student’s t
distribution with
degrees
of freedom.
Example:
Independent random samples of checking account balances for customers at two branches of National Bank show the following results:
Bank branches |
Number of checking accounts |
Sample mean balance |
Sample standard deviation |
Bank B |
12
10 |
|
|
Find a 90 % confidence interval estimate for the difference between the mean checking account balances of the two branches.
Solution:
confidence interval is
.
Thus, the interval estimation becomes
At
a 90 % level of confidence the interval estimate for the difference
in mean account balances of two branches of Bank is
to
.
The fact that the interval includes a negative range of values indicates that the actual difference in the two means may be negative.
Thus could be actually be larger than .
Exercises
1. The following information was obtained from two independent samples selected from two normally distributed populations with unknown but equal variances.
;
;
;
;
Construct a 99 % confidence interval for .
2. The National Bank is interested in estimating the difference between the mean credit card balances of its two branches. Independent random samples of credit card customers provide the following results:
Branch A Branch B
Construct an interval estimate of the difference between mean balances. Use a confidence coefficient of 0.99.
3. Production quantities of two workers are shown below. Each data value indicates the amount of items produced during a randomly selected 1 day period
Worker 1: 20; 18; 21; 22; 20
Worker 2: 22; 18; 20; 23; 24
Develop a 90 % confidence interval estimate for the difference between the mean production rates of the two workers.
4. The mean salary of male professors at the universities was 54 340 tg and that of female professors was 48 080 tg. For convenience, assume that these two means are based on random samples of 28 male and 26 female professors. Assume that the standard deviations of the two samples are
3 100 tg and 2 800 tg, respectively.
Construct a 90 % confidence interval for the difference between the two population means.
5. The following summary statistics are recorded for independent random samples from two populations:
Sample 1 Sample 2
Stating any assumptions that you need, determine a 98 % confidence interval for .
6. A company is interested in buying one of two different kinds of machines. Company tested the two machines for production purposes. The first machine was run for 8 hours and produced an average 123 items per hour with a standard deviation of 9 items. The second machine was run for 10 hours and produced an average of 114 items per hour with a standard deviation of 6 items. Assume that the production per hour for each machines approximately normally distributed. Also assume that the standard deviation of the hourly production of the two populations is equal.
Then find a 95 % confidence interval for the difference between the two population means.
Answers
1. (2.21; 9.29); 2. ($37.57; $212.43); 3. (Worker 2- Worker 1): 0.87; units to 3.27 units); 4. (4909.87; to 7610.13); 5. (-2.84; 25.84); 6. (1.50 to 16.50 items).
