- •Methodical instructions and the task for course work on discipline «data transmission systems»
- •The task for course work
- •Initial data
- •Cyclic code combination synthesis
- •7.1 Compositing of the information block
- •7.2 Choice of a generating polynomials of a cyclic code
- •7.3 Synthesis of a cyclic code combination
- •7.4 Check of correctness of reception resolved ccc
Initial data
Table 1 – Initial data for calculations on subitems 1, 4.
Parameter |
Penultimate figure of number of the record book |
||||||||||
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
0 |
||
рer |
210-3 |
510-4 |
110-3 |
710-5 |
3,710-3 |
410-4 |
210-5 |
2,510-4 |
110-4 |
3,510-4 |
|
d0 |
3 |
4 |
3 |
4 |
3 |
4 |
3 |
4 |
3 |
4 |
|
ARQ |
SW |
GBN |
SR |
SW |
GBN |
SR |
SW |
GBN |
SR |
GBN |
|
L, km |
480 |
875 |
1200 |
2500 |
5600 |
480 |
875 |
1200 |
2500 |
5600 |
|
Parameter |
Last figure of number of the record book |
||||||||||
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
0 |
||
|
0,55 |
0,6 |
0,4 |
0,65 |
0,45 |
0,7 |
0,47 |
0,62 |
0,5 |
0,52 |
|
Рun er (1*10-6) |
1,0 |
0,5 |
0,7 |
0,8 |
0,9 |
0,8 |
0,7 |
0,6 |
0,5 |
0,4 |
|
B Bit/s |
9600 |
64000 |
14400 |
28800 |
33600 |
31000 |
12200 |
9600 |
64000 |
14400 |
|
d |
1 |
2 |
3 |
1 |
2 |
3 |
1 |
2 |
3 |
1 |
Cyclic code combination synthesis
7.1 Compositing of the information block
It is necessary to make the information block consisting of three capital letters – the initials of student's surname, name and patronymic. For compositing it is necessary to use a fragment of the code table of primary code ASCII which is presented on fig. 1.
The senior bits are read out from first four lines, and younger – from first four columns corresponding to a site of the letter in drawing.
|
0 |
|
0 |
||||||||
0 |
|
1 |
|||||||||
1 |
|
0 |
|||||||||
1 |
|
0 |
|||||||||
Numbers of categories |
Letters of the English alphabet |
||||||||||
b8 |
b7 |
b6 |
b5 |
b4 |
b3 |
b2 |
b1 |
||||
8 |
7 |
6 |
5 |
4 |
3 |
2 |
1 |
||||
|
0 |
0 |
0 |
0 |
|
|
P |
||||
0 |
0 |
0 |
1 |
A |
|
Q |
|||||
0 |
0 |
1 |
0 |
B |
|
R |
|||||
0 |
0 |
1 |
1 |
C |
|
S |
|||||
0 |
1 |
0 |
0 |
D |
|
T |
|||||
0 |
1 |
0 |
1 |
E |
|
U |
|||||
0 |
1 |
1 |
0 |
F |
|
V |
|||||
0 |
1 |
1 |
1 |
G |
|
W |
|||||
1 |
0 |
0 |
0 |
H |
|
X |
|||||
1 |
0 |
0 |
1 |
I |
|
Y |
|||||
1 |
0 |
1 |
0 |
J |
|
Z |
|||||
1 |
0 |
1 |
1 |
K |
|
|
|||||
1 |
1 |
0 |
0 |
L |
|
|
|||||
1 |
1 |
0 |
1 |
M |
|
|
|||||
1 |
1 |
1 |
0 |
N |
|
|
|||||
1 |
1 |
1 |
1 |
O |
|
|
Figure 1 – ASCII Code. A fragment of the English alphabet
Let's code for an example Sidorov Ivan Petrovich's initials:
S ® 0100 0011
I ® 0011 1001
P ® 0100 0000