- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Card 19
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
- •Create the database with the following tables:
-
Relational algebra. Equi-join, natural join and semi-join operations. Example
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SQL language. CHAR и VARCHAR2 types
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By using database from labs write expression in Relational agebra and Tuple relational calculus that answer to the following query: “Output department names whose teachers have lectures in room 200 of the 6 builting on Mondau of the 2nd week
-
Create the database with the following tables:
Database of the family tree:
PERSON – info about persons and their parents
|
Table name |
Column name |
Data type |
Length (precis.) |
Scale |
Column integrity constraint |
|
PERSON |
Name |
VARCHAR2 |
25 |
|
Cannot be NULL |
|
TaxID |
NUMBER |
8 |
|
UNIQUE, cannot be NULL, default value - 0 |
|
|
Sex |
CHAR |
1 |
|
List of possible values – (‘M’, ’F’) |
|
|
BirthDate |
Date |
|
|
Must be more than 01.01.1930 |
|
|
Pas_Ser |
CHAR |
2 |
|
Default value‘XX’ |
|
|
Pas_Nom |
CHAR |
6 |
|
Default value ‘000000’ |
|
|
M_Pas_Ser |
CHAR |
2 |
|
|
|
|
M_Pas_Nom |
CHAR |
6 |
|
|
|
|
F_Pas_Ser |
CHAR |
2 |
|
|
|
|
F_Pas_Nom |
CHAR |
6 |
|
|
|
|
Table integrity constraint |
Pair of columns (Pas_Ser, Pas_Nom) is a PRIMARY KEY Pair of columns (Name, BirthDate) is unique – UNIQUE Pair of columns (M_Pas_Ser, M_Pas_Nom) is a FOREIGN KEY. It references to the pair of columns (Pas_Ser, Pas_Nom) of the same table (it references the the mother of the person). Pair of columns (F_Pas_Ser, F_Pas_Nom) is a FOREIGN KEY. It references to the pair of columns (Pas_Ser, Pas_Nom) of the same table (it references the the father of the person). When person is deleted then all references to it as a mother/father are set to NULL. |
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Card 19
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Relational algebra. Left join, right join and full join operations.
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SQL language. Purpose nad possibilities of the UPDATE statement. Examples
-
By using database from labs write expression in Relational agebra and Tuple relational calculus that answer to the following query: “Output department names whose teachers-assistants have lectures on Monday in the groups of the 6th course
-
Create the database with the following tables:
Database of agregate/parts:
AGREGATE – agregate, ASSEMBLY – agregare assembly, PART – aggregate/assembly part.
|
Table name |
Column name |
Data type |
Length (prec) |
Scale |
Column integrity constraint |
|
AGREGATE |
AGNo |
NUMBER |
3 |
|
PRIMARY KEY |
|
Ag_Name |
VARCHAR2 |
25 |
|
Cannot be NULL |
|
|
AG_Weight |
NUMBER |
6 |
3 |
Cannot be NULL |
|
|
AG_Type |
CHAR |
1 |
|
Cannot be NULL. Take values from the list (‘1‘,‘2‘,‘3‘,‘4‘,‘5‘) |
|
|
Table integrity constraint |
Pair of columns (Ag_Name, AG_Type) is unique - UNIQUE |
||||
|
ASSEMBLY |
ASNo |
NUMBER |
3 |
|
PRIMARY KEY |
|
As_Name |
VARCHAR2 |
30 |
|
Cannot be NULL |
|
|
AS_Color |
NUMBER |
3 |
|
Cannot be NULL. Cannot be less than 0 |
|
|
AG_No |
NUMBER |
3 |
|
FOREIGN KEY, references to the column AGNo of the table AGREGATE. If aggregate is delete then all its child assemples are deleted too |
|
|
RASNO |
NUMBER |
3 |
|
FOREIGN KEY, references to the column ASNo of the table ASSEMBLY. It is not possible to delete assembly if there exists at least one child assembly |
|
|
Table integrity constraint |
Pair of columns (Ag_No, Ras_No) is unique |
||||
|
PART |
|
|
|
|
|
|
Part_Name |
VARCHAR2 |
30 |
|
Cannot be NULL |
|
|
Part_Price |
NUMBER |
8 |
2 |
Cannot be NULL. Cannot be less than 0 |
|
|
Part_ discount |
NUMBER |
8 |
2 |
Cannot be less than 0 |
|
|
AGNo |
NUMBER |
3 |
|
FOREIGN KEY, references to the column AGNo of the table AGREGATE. If aggregate is delete then all its child parts are deleted too |
|
|
ASNo |
NUMBER |
3 |
|
FOREIGN KEY, references to the column ASNo of the table ASSEMBLY. If aggregate is deleted then all references to it are set to NULL |
|
|
Table integrity constraint |
Pair of columns (Com_Name, SM_BARNo) is a primary key Value of the column Part_ discount must be less than 1/3 value of the column Part_Price |
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Card 20