11_-_chislennye_metody
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Используем средство «Поиск решения»:
Индивидуальные задания
2.3.1 |
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sin(x |
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1,2; |
tg(xy |
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0,4) |
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x 2 |
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1) |
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2) |
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+ 2 y 2 |
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x > 0, y > 0. |
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2x + cos y = 2. |
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0,6x 2 |
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2.3.2 |
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− |
1) |
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y |
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0,5; |
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+ y) −1,6x = 0; |
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cos(x |
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sin(x |
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− cos y = 3. |
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2) |
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+ y |
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x > 0, y > 0. |
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2.3.3 |
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sin x + 2 y = 2; |
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1) |
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cos(y −1) + x = 0,7. |
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2.3.4 |
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cos x + y =1,5; |
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1) |
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=1. |
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2x − sin( y − 0,5) |
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2.3.5
sin(x + 0.5) − y =1; |
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+ x = 0. |
cos(y − 2) |
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2.3.6
cos(x + 0,5) + y = 0,8;
1) − =sin y 2x 1,6.
2.3.7
sin(x −1) =1,3 − y;
1) x −sin( y +1) = 0,8.
tg(xy + 0,1) = x 2 |
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2) |
+ 2 y 2 |
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x 2 |
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sin(x + y) −1,2x = 0,2;
2) 2 + 2 =x y 1.
tg(xy + 0,3) = x2 |
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2) |
+ 2 y 2 |
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0,9x 2 |
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sin(x + y) −1,3x = 0;
2) 2 + 2 =x y 1.
tg xy = x 2 ; |
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+ 2 y |
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0,8x2 |
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2.3.8
2 y − cos(x + 1) = 0;
1) x + sin y = −0,4.
2.3.9
cos(x + 0,5) − y = 2;
1) − =sin y 2x 1.
2.3.10
sin(x + 2) − y = 1,5;
1) x + cos(y − 2) = 0,5.
2.3.11
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sin( y + 1) − x = 1,2; |
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2 y + cos x = 2. |
2.3.12 |
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cos(y −1) + x = 0,5; |
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y − cos x = 3. |
2.3.13
sin y + 2x = 2;
1) cos(x −1) + y = 0,7.
2.3.14
cos y + x = 1,5; |
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= 1. |
2 y − sin(x − 0,5) |
2.3.15
sin( y + 0.5) − x = 1;
1) cos(x − 2) + y = 0.
sin(x + y) −1,5x = 0,1; |
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+ y 2 |
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x 2 |
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tg xy = x 2 ;
2)
2 + 2 =0,7x 2 y 1.
sin(x + y) −1,2x = 0,1; |
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+ y 2 |
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x2 |
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tg(xy + 0,2) = x 2 |
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2) |
+ 2 y 2 |
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0,6x 2 |
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sin(x + y) = 1,5x − 0,1; |
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+ y 2 |
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x 2 |
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tg(xy + 0,4) = x 2 |
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2) |
+ 2 y 2 |
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0,8x 2 |
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sin(x + y) = 1,2x − 0,1; |
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+ y 2 |
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x2 |
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tg(xy + 0,1) = x2 ;
2)
2 + 2 =0,9x 2 y 1.
2.3.16
cos(y + 0,5) + x = 0,8;
1) − =sin x 2 y 1,6.
2.3.17
sin( y −1) + x = 1,3;
1) y − sin(x + 1) = 0,8.
2.3.18
2x − cos( y + 1) = 0;
1) y + sin x = −0,4.
2.3.19
cos(y + 0,5) − x = 2;
1) − =sin x 2 y 1.
2.3.20
sin( y + 2) − x = 1,5;
1) y + cos(x − 2) = 0,5.
2.3.21
sin(x + 1) − y = 1;
1) + =2x cos y 2.
2.3.22
cos(x −1) + y = 0,8;
1) − =
x cos y 2.
sin(x + y) −1,4x = 0; |
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+ y 2 |
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x 2 |
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tg (xy + 0,1) = x2 |
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2) |
+ 2 y 2 |
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0,5x2 |
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sin(x + y) = 1,1x − 0,1; |
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+ y 2 |
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x 2 |
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tg (x − y) − xy = 0; |
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+ 2 y 2 |
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x 2 |
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sin(x + y) − xy = −1; |
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2) |
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+ y2 |
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tg(xy + 0,2) = x 2 |
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2) |
+ 2 y 2 |
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x 2 |
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sin(x + y) − 1,5x = 0;
2) 2 + 2 =
x y 1.
2.3.23
sin x + 2 y = 1,6;
1) cos(y −1) + x = 1.
2.3.24
cos x + y = 1,2; |
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= 2. |
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2x − sin( y − 0,5) |
2.3.25
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sin(x + 0.5) − y = 1,2; |
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+ x = 0. |
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cos(y − 2) |
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2.3.26 |
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cos(x + 0,5) + y = 1; |
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= 2. |
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sin y − 2x |
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2.3.27
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sin(x − 1) + y = 1,5; |
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x − sin( y + 1) = 1. |
2.3.28 |
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cos(y + 0,5) − x = 2; |
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2 y + cos x = 2. |
2.3.29
cos(y − 0,5) + x = 0,8;
1) − =
y cos x 2.
2.3.30
cos(x −1) + y = 1;
1) + =sin y 2x 1,6.
tg xy = x 2 ;
2)
2 + 2 =0,5x 2 y 1.
sin(x + y) = 1,2x − 0,2; |
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+ y 2 |
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x 2 |
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tg(xy + 0,1) = x2 |
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2) |
+ 2 y 2 |
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0,7x 2 |
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sin(x + y) −1,5x = 0,2; |
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+ y 2 |
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x 2 |
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tg xy = x 2 ;
2)
2 + 2 =0,6x 2 y 1.
sin(x + y) −1,2x = 0; |
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+ y 2 |
= 1. |
x 2 |
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tg(xy + 0,3) = x2 |
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2) |
+ 2 y 2 |
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0,5x 2 |
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sin(x + y) −1,1x = 0,1;
2) 2 + 2 =
x y 1.