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Файл:Физика полупроводников и нанотехнологий. Учебно-методическое пособие
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Рис. 10.9. /(!#0-& 1"!(#! XFG1
.!& 3-)85"&& !:&$ / #/%&))#/-#6 " 1# ;-!" #(#9!:(/+ 3,# "+ ,!-(!&/(&- (!"'&/(#! (!&/. 10.10). )+ 2 #9/(3 !//$#(!"&+ ,!-(!&/(&-& /$<"4 3"&' " 1 .
Рис. 10.10. !-(!&/(&- n--")*"#1# .-(!"'&/(#! Q1
" ;-!" #/%&))#/-#6 XSC2
61
- 3& "# &' !//$#(!"&+ ;(#0 ,!-(!&/(&-&, "6!+:"& U0
)"&
З
U
∆
∆
1
#(/5-& (!"'&/(#! 6!&$!"# !3"# (-1,2 ), $/7(9 6# 3!(&-)*"#0 #/& /#/(3)+( 250
I
S
C
=
(6!& U0 > U > 0) – 6!&$!"# 120 $/, $/7(9"40 (#-
$
, -!2(&'" ,!-(!&/(&-&
(6!& U = 0) IS = 130 $. /((#5"40 (#- I0 (6!& U < U0) 6!&$!"#
!3" (-1,6) ".
@( : ,!-(!&/(&- / 1! 2&!#3""4$& #/+$& U & I &'#9!-
U
:" " !&/. 10.11. #- I #6! )+(/+ 6# #!$2)
IR=
C
B
, UB –
"6!+:"& " 3,# -") #/%&))#/-#6 XSC2.
Рис. 10.11. ! 2&!#3""+ ,!-(!&/(&- (!"'&/(#! Q1
Задание 10.2
1. #9!(* /,$2 )+ /"+(&+ 3,# "#0 ,!-(!&/(&-& n-
-")*"#1# .-(!"'&/(#!. !&"(4 (!"'&/(#!#3: BSS135,
BSS229, BSP149.
2. "+(* ,!-(!&/(&-2 (!"'&/(#! ")#1&5"# (#0, 5(# &'#9-
!:" " !&/. 10.10.
3. '#9!'&(* ,!-(!&/(&-2 (!"'&/(#! / 1! 2&!#3""4$&
#/+$& ")#1&5"# !&/. 10.11.
4. 6! )&(* "6!+:"& #(/5-& U0 (!"'&/(#!, -!2(&'"2 ,-
!-(!&/(&-& S, $/7(9"40 (#- I
, #/((#5"40 (#- I0.
S
62
Снятие входной характеристики p-канального
МОП-транзистора с индуцированным каналом
)+ /"+(&+ 3,# "#0 ,!-(!&/(&-& (!"'&/(#! /#9&!(/+ /,$ (!&/. 10.12).
Рис. 10.12. ,$ )+ /"+(&+ 3,# "#0 ,!-(!&/(&-&
р--")*"#1# .-(!"'&/(#! / &" 2%&!#3""4$ -")#$
)+ /"+(&+ ,!-(!&/(&-& " '(3#! (!"'&/(#! Q1 #( 1"!(#! XFG1 6# (/+ "6!+:"& (!21#)*"#0 #!$4 $6)&(2 #0 4 .
/(!#0-& 1"!(#! &'#9!:"4 " !&/. 10.13.
Рис. 10.13. /(!#0-& 1"!(#! XFG1
63
@(# : "6!+:"& 6#/(26( " 3,# #/%&))#/-#6 XSC2, "
1
)"&
З
U
∆
∆
1# 3,# 6#/(26( "6!+:"&, 6!#6#!%&#")*"# (#-2 /(#-
(!"'&/(#! Q1. .!& 3-)85"&& !:&$ / #/%&))#/-#6 " 1#
;-!" #(#9!:(/+ 3,# "+ ,!-(!&/(&- (!"'&/(#!
(!&/. 10.14). )+ 2 #9/(3 !//$#(!"&+ /&1") " -") /$<" 3"&' " # "# )"& (" 500 $).
Рис. 10.14. !-(!&/(&- (!"'&/(#! Q1
" ;-!" #/%&))#/-#6 XSC2
@(2 : ,!-(!&/(&-2 /) 2( &'#9!'&(* #( )*"#, / 1! 2&!#3""4$& #/+$& U & I (!&/. 10.15). #- I #6! )+(/+ 6# #!$2)
U
IR=
C
.!& ;(#$ $/7(9 6# 3!(&-)*"#0 #/& /#/(3)+( 100
B
, UB – "6!+:"& " 3,# -") #/%&))#/-#6 XSC2.
$
.
- 3& "# &' !//$#(!"&+ ;(#0 ,!-(!&/(&-&, "6!+:"& U0
#(/5-& (!"'&/(#! 6!&$!"# !3"# (-2,6 ), -!2(&'" ,!-(!&/(&-
I
S
-&
(6!& U
C
=
= 0) 6!&$!"# 300 $. /((#5"40 (#- I0 (6!& U > U0) 6!&-
(6!& U < U0) – 6!&$!"# 200 $/, $/7(9"40 (#- IS
$!"# !3" (-1,6) ".
64
Рис. 10.15. ! 2&!#3""+ ,!-(!&/(&- (!"'&/(#! Q1
IC $
300
200
100
0
-6 -4 -2 0 2 4 U
Задание 10.3
1. #9!(* /,$2 )+ /"+(&+ 3,# "#0 ,!-(!&/(&-& р-
-")*"#1# .-(!"'&/(#!. !&"(4 (!"'&/(#!#3: BST122,
BST100, ZVP2106A, ZVP3306, ZVP2106G.
2. "+(* ,!-(!&/(&-2 (!"'&/(#! ")#1&5"# (#0, 5(# &'#9-
!:" " !&/. 10.14.
3. '#9!'&(* ,!-(!&/(&-2 (!"'&/(#! / 1! 2&!#3""4$&
#/+$& ")#1&5"# !&/. 10.15.
4. 6! )&(* "6!+:"& #(/5-& U0 (!"'&/(#!, -!2(&'"2 ,-
!-(!&/(&-& S, $/7(9"40 (#- IS, #/((#5"40 (#- I0.
Снятия выходной характеристики n-канального МОП-
транзистора с индуцированным каналом
)+ /"+(&+ 34,# "#0 ,!-(!&/(&-& n--")*"#1# .(!"'&/(#! / &" 2%&!#3""4$ -")#$ (#9#1<""#1# (&6) /#9&!(/+ /,$ (!&/. 10.16).
/"#32 /,$4 /#/(3)+( 1"!(#! /(26"5(#1# "6!+:"&+,
/#9!""40 " %&!#-")#1#3#$ 6!#9!'#3() (.) 1, " 3
/(!7&, !'!+ -#(#!#1# 6# (/+ 32,!'!+ "40 -# / 3#&5"#1#
/5(5&- U3A. /5("40 3,# /5(5&- 6# 8(/+ /5("4 &$62)*/4, #!$&!2$4 1"!(#!#$ XFG2 5/(#(#0 50 %. (26"5(#
"6!+:"& !1&/(!&!2(/+ #/%&))#/-#6#$ XSC1.
65
2
1CLR
1
1INA
74LS393D
XFG2
0
U3A
1QA
1QB
1QC
1QD
V1
8 V
3
4
5
6
1
0
4
5
D0D1D2D3D4D5D6
Vref+
Vref-
VDAC8
A1
D7
Output
XSC1
Ext Trig
+
B
A
_
+
V2
3
2 V
+
XSC2
B
A
_
+
+
_
_
Ext Trig
+
_
_
XFG1
0
2
R2
100kΩ
6
Рис. 10.16. ,$ )+ /"+(&+ 34,# "#0 ,!-(!&/(&-&
n--")*"#1# (!"'&/(#! / &" 2%&!#3""4$ -")#$
. $#:"# "0(& 3 9&9)&#(- 6# 62(&:
Place ixedAADC_DACA VDAC,
/5(5&- – 6# 62(& TTLA74LSA74LS393D (,).
9
R1
10Ω
7
Q1
BSD214
0
. 1 6# (/+ (-: #6#!"# "6!+:"& 8 #( &/(#5"&-
- V1. //) 2$40 (!"'&/(#! Q1 3-)85" 6# /,$ / #9<&$ &/(#-
-#$. 1# %6* /(#- 6# (/+ 6#)#:&()*"# "6!+:"& (!21#)*"#0 #!$4 / $6)&(2 #0 12 , #!$&!2$# 1"!(#!#$ XFG1
& /$<""# " 12 33!,.
/(!#0-& 1"!(#!#3 XFG2 & XFG1 &'#9!:"4 " !&/. 10.17.
3,# #/%&))#/-#6 XSC2 6# (/+ "6!+:"& /(#- (!"'&/(#! Q2, " 3,# – 6 "& "6!+:"&+ " !'&/(#! R1, 6!#6#!%&#")*"# (#-2 /(#- (!"'&/(#!. /%&))#/-#6 XSC2 3-)85"
3 !:&$ /.
66
&1!$$ /(26"5(#1# "6!+:"&+ " #/%&))#/-#6 XSC1
)"&
)"&
6! /(3)" " !&/. 10.18, 34,# "4 ,!-(!&/(&-& (!"'&/(#!
(" #/%&))#/-#6 XSC2) 6! /(3)"4 " !&/. 10.19. )+ 2 #9/(3
,!-(!&/(&-& /$<"4 " ;-!" 3)3# " 2 & 3"&' " 400 $.
Рис. 10.17. /(!#0-& 1"!(#!#3 XFG2 (/)3) & XFG1 (/6!3)
- 3& "# &' !//$#(!"&+ !&/. 10.18, $-/&$)*"+ 3)&5&"
/(26"5(#1# "6!+:"&+ !3" 2 .
. "& "6!+:"&+ " !'&/(#! R1, -- 3& "# &' !//$#(!"&+
!&/. 10.19, !1&/(!&!2(/+ / $/7(9#$ 500
$/7(9 6# 3!(&-)*"#0 #/& ,!-(!&/(&- /#/(3)+( 50
$
. /3+'& / ;(&$
$
.
Рис. 10.18. &1!$$ /(26"5(#1# "6!+:"&+, 6# 3$#1#
" '(3#! &//) 2$#1# (!"'&/(#!
67
Рис. 10.19. $0/(3# 34,# "4, 3#)*(-$6!"4, ,!-(!&/(&-
0 2 4 6 8 10
UC
0
U=0
-
0,5
-
1,0
-
1,5
(!"'&/(#! 2N3458 " ;-!" #/%&))#/-#6 XSC2
! 2&!#3""# /$0/(3# ,!-(!&/(&- &//) 2$#1# (!"'&/(#! 6! /(3)"# " !&/. 10.20.
IC $
8
6
4
2
Рис. 10.20. ! 2&!#3""# /$0/(3# ,!-(!&/(&-
&//) 2$#1# (!"'&/(#!
68
Задание 10.4
.
U
+
.
U
−
1. #9!(* /,$2 (/$. !&/. 10.16) )+ /"+(&+ 34,# "#0 ,!-(!&-
/(&-& n--")*"#1# .-(!"'&/(#!. !&"(4 (!"'&/(#!#3:
BSD215, ZVN0124A, ZVN2106A, ZVN3306A.
2. "+(* ,!-(!&/(&-2 (!"'&/(#! ")#1&5"# (#0, -#(#!+
&'#9!:" " !&/. 10.19.
3. '#9!'&(* ,!-(!&/(&-2 (!"'&/(#! / 1! 2&!#3""4$&
#/+$& ")#1&5"# !&/. 10.20.
Практическое занятие № 11
ИССЛЕДОВАНИЕ ХАРАКТЕРИСТИК ДИФФЕРЕНЦИАЛЬНОГО
УСИЛИТЕЛЯ НА БИПОЛЯРНЫХ ТРАНЗИСТОРАХ.
ОПРЕДЕЛЕНИЕ ОСНОВНЫХ ПАРАМЕТРОВ УСИЛИТЕЛЯ
Общие сведения
,$ &!"%&)*"#1# 2/&)&()+ () 6! /(3)" "
!&/. 11.1.
U
R
R
2
2
I
2
I
2
VT2
I@2
U
=U
2
Э
2
U
1
=U
R
U
1
1
I
1
I
1
VT1
IЭ1
1
U@
Рис. 11.1. 9<+ /,$
/,$ /#6!#(&3)"& R@ #/((#5"# 3)&-#, 3 1# -5/(3 5/(# &/6#)*'2(/+ &/(#5"&- 6#/(#+""#1# (#-.
/6#)*'28(/+ /) 28<& #6! )"&+ 3,# "4, /&1")#3:
69
&!"%&)*"40 3,# "#0 /&1")
1 2 1 2
;
U U U U U
= − = −
1 2 1 2
.
U U U U U
= = = =
.
I I I const
+ = ≈
.
2
Э
I
@
.
2
I
0
= =
1 2
.
U U U
1 2
,
.
2
U
∆
0.
∆ = ∆ + ∆ =
K1 K1 K1
1 @1
,
U U r
∆ ∆
/&"'"40 3,# "#0 /&1")
.!& &!"%&)*"#$ 3,# "#$ /&1"), (.. 6!& 6!#(&3#'"4, 3,# "4, /&1"), U
1, U2
, 6!&!<"&+ (#-#3 BI@1 & BI
@2
!3-
"4 & 6!#(&3#6#)#:"4 6# '"-$, 6#;(#$2 &$( $/(# /##("#7"&
@1 @2 @
.!& #(/2(/(3&& 3,# "4, /&1")#3
I I+ =
1 2
Э Э
I I= ≈
K1 K2
&$$
U U
1 2
Б Б
.!& 6# 5 &!"%&)*"#1# /&1") U
= ∆ − ∆
&$$
.!& # &"-#34, &'$""&+, "6!+:"&0 " 9', (!"'&/(#!#3
346#)"+(/+
U U∆ = −∆
(#1 6!&!<"& "6!+:"&+ " 9' !3"#
U U
∆ = −∆ =
1 2
.!& ;(#$ (#- 5!' !'&/(#! RЭ " &'$"&(/+:
I I I
@ @1 @2
) #3()*"#, #9 (!"'&/(#! 3 ;(#$ /)25 #-'438(/+
3-)85""4$& 3 /,$2 / @, & -#;&%&"( 2/&)"&+ (!"'&/(#!#$
VT1 &!"%&)*"#1# /&1") !3"
U U R
K
= = ≈ −
1
∆ ∆
2 2
(11.1)
")#1&5"40 -#;&%&"( 2/&)"&+ (!"'&/(#!#$ VT2 !3"
70
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