Железобетонные и каменные конструкции. Монолитное железобетонное ребристое перекрытие с балочными плитами. Учебное пособие

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Ю. И. Кононов М. Ю. Кононова

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o>%“*, ! K!,“2/ › > ƒ%K 2%……/ C ! *!/2, …=.% 2 H,!%*% C!,A … …, " C!%A/H> ……/., +!=› =…“*,. ƒ =…, . , “%%!3› …, .. n…, A%+32 K/2@ "/C%>… …/ " A%…%>,2…%A, “K%!- …%A ,>, “K%!…%-A%…%>,2…%A › > ƒ%K 2%… . b …=“2% ? "! A 2%…*%“2 ……/ *%…“2!3* ,, C ! *!/2,L ƒ =…,L , “%%!3› …,L "/C%>… E2“ " %“…%"…%A ,ƒ “K%!…%+% › > ƒ%K 2%…=.

n …=*% ƒ= C%“> …, +% / " …=H L “2!=… A%…%>,2…/L › > ƒ%K 2%… C%>3),> %“2=2%)…% H,!%*% !=“C!%“2!=… …, C!, "%ƒ" …,, +!=› =…“*,. ƒ =…,L , “%%!3› …,L, " 2%A ),“> 2=*,.

.> A …2%", *=* A › 3.2=›…/ C ! *!/2, , C%*!/2, , … “3?, “2 …/ , *%>%……/. }2% %K“2% 2 >@“2"% “" ƒ=…%, " C !"3E %) ! @,

“=>@… LH,A “%" !H …“2"%"=…, A “%“2="%" A >*%ƒ !…,“2%+% K 2%…=, A 2% %" +% 3*>= *, , 3C>%2… …, , = 2=*› ƒ…=),2 >@…%+% 3>3)H …, *=) “2"= “K%!…%-!=ƒK%!…%L %C=>3K*,, )2% C%ƒ"%>,>% “…,ƒ,2@ ƒ=2!=2/ …= 3“2=…%"*3 C!, C!%,ƒ"% “2" › > ƒ%K 2%…- …/. !=K%2.

l%…%>,2…/L › > ƒ%K 2%… " +!=› =…“*,. ƒ =…, . C!,A … 2-

““ 3) 2%A 3*!3C… ……%+% A% 3> “%+>=“…% cnqŠ 23638#89 œg =- …, C! C!, 2,L. o=!=A 2!/B, )2% = 2 "%ƒA%›…%“2@ C!,A … 2@ 3…,-, ,!%"=……3E %C=>3K*3 “ K%>@H,A ),“>%A %K%!=),"= A%“2,. b =……%A 3) K…%A C%“%K,, !=““A%2! …= C%“> %"=2 >@…%“2@ !=“) 2= , C!% *2,!%"=…, A%…%>,2…%+% ! K!,“2%+% A ›.2=›…%+% C ! *!/2, “ K=>%)…/A, C>,2=A,, =!A,!%"=……%+% “"=!…/A, ,>, " ƒ=…/A, =!A=23!…/A, “ 2*=A, , *=!*=“=A,, = 2=*› C! “2="- > … !=“) 2 , =!A,!%"=…, *%>%…… , -3… =A …2= ,ƒ A%…%>,2…%+%

› > ƒ%K 2%…= (!,“. 1).

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p,“.1.Š,C/ C>%“*,. › > ƒ%K 2%……/. C ! *!/2,L

=O “K%!…% ; K O A%…%>,2…% ! K!,“2% “ K=>%)…/A, C>,2=A,;

"O 2% › “ C>,2=A,, %C !2/A, C% *%…23!3; O K ƒK=>%)…% ;

1 O *%>%……/; 2 O !,+ >@; 3 O C=… >, C ! *!/2,L; 4 O “2 …/; 5 O +>="…= K=>*=; 6 O "2%!%“2 C ……/ K=>*,; 7 O C>,2=; 8 O *=C,2 >@

q> 3 2 %2A 2,2@, )2% 2=*%L *%…“2!3*2,"…/L .> A …2, *=* K=>%)…= C>,2=, ".% ?= " “%“2=" A%…%>,2…/.! K!,“2/.› > - ƒ%K 2%……/. C ! *!/2,L, )=“2% "“2! )= 2“ " >%A ! +, !%- 2 .…,) “*,. “%%!3› …,L: …=C!,A !, " *%…2!-%!“…/. C>%2,…=., C% C%!…/. “2 …=., =*" 3*=., = 2=*› !=ƒ>,)…/. *%!%K)=2/. *%…“2!3* , . “%%!3› …,L +%!% “*%L ,…-!=“2!3*23!/.

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1. jnlonmnbj` a`kn)mncn oepejp{Šh“

h m`gm`)emhe nqmnbm{u p`glepnb }kelemŠnb

l%…%>,2…% ! K!,“2% C ! *!/2, “%“2%,2 ,ƒ › > ƒ%K 2%…- …%L C>,2/, *%2%!= %C,!= 2“ …= K=>%)…3E *> 2*3, “%“2% ?3E ,ƒ “,“2 A/ +>="…/., "2%!%“2 C ……/."ƒ=,A…% C !C … ,*3> !…/. K=>%* (!,“. 2). o>,2= C ! *!/2, , K=>*, A%…%>,2…% “" ƒ=…/ A › 3 “%K%L, )2% %“2,+= 2“ C32 A % …%"! A ……%+% K 2%…,!%- "=…, "“ . .> A …2%" C ! *!/2, " “C ,=>@…% ,ƒ+%2%"> ……%L> .2%+% %C=>3K* .

b … H,!%*,. C%A ? …, . ( % 6#9 A) %+!=…,),"=E2“ C%- “2=…%"*%L K=>%* " % …%A …=C!="> …,,. m= .2, % …%C!%> 2…/ K=>*, %C,!= 2“ C>,2= C ! *!/2, .o!, ƒ…=),2 >@…/. C>=…%"/. !=ƒA !=.C ! *!/"= A%+% C%A ? …, K=>*, !=“C%>=+=E2“ " "3. …=C!="> …, ., %C,!=E2“ …= C!%A ›32%)…/ %C%!/O *%>%……/

5

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p,“.2.t!=+A …2/ *%…“2!3* ,L A%…%>,2…/. C>%“*,. C ! *!/2,L

=O ! K!,“2% “ K=>%)…/A, C>,2=A,; K O K ƒK=>%)…% (", “…,ƒ3); 1 O C>,2=; 2 O "2%!%“2 C ……= K=>*=;

3 O +>="…= K=>*=; 4 O *%>%……=; 5 O *=C,2 >@

6

"2%!%“2 C ……%L K=>*, (l > = l"2),

!=ƒA ! *%!%2*%L “2%!%…/O !=“-

“2% …,E A › 3 "2%!%“2 C ……/A,

K=>*=A, (l*%! = 1,5#2,2A).

p=“) 2=A, 3“2=…%"> …%, )2% “>, “%%2…%H …, “2%!%… C>,2/ l >/l*%!≥ 2, 2% 2=*= C>,2= !=K%2= 2 +>="…/A %K!=ƒ%A " *%!%2*%A …=C!="> …,,.

Š=*, C>,2/ C%>3),>, …=ƒ"=…, K=>%)…/., 2=* *=* ,.!=“) 2

“%“2=2%)…%L “2 C …@E 2%)…%“2, A%›…% “" “2, * !=“) 23 K=>*,

“C!%> 2%A l*%!, )2% "> 2“ C!%> 2%A K=>%)…%L C>,2/ lC>. m=,K%>@H,L !=“.% › > ƒ%K 2%…= ( % 65 %) C= = 2 …= C>,23,

C%.2%A3 C!, !=ƒK,"* K=>%)…%L *> 2*, … “> 3 2 C!,…,A=2@ K%>@H, C!%> 2/ C>,2/, 2=* *=* " C!%2,"…%A “>3)= " C>,2 K3 32 K%>@H, ,ƒ+,K=E?, A%A …2/ ,, “> %"=2 >@…%, C%>3- ),2“ K%>@H= 2%>?,…= C>,2/.

7

o!, %C! > …,, 2%>?,…/ C>,2/ !3*%"% “2"3E2“ *%…“2!3*- 2,"…/A, , .*%…%A,) “*,A, “%%K!=› …, A,.

m%!A/ 3“2=…=">,"=E2 “> 3E?, A,…,A=>@…/ 2%>?,…/ A%…%>,2…/. K=>%)…/. C>,2 A › 3.2=›…/. C ! *!/2,L:

•> C!%,ƒ"% “2" ……/. ƒ =…,LO 60 AA,

•> ›,>/. , +!=› =…“*,. ƒ =…,LO 50 AA.

Š A … A … , 2%>?,…= A%…%>,2…/. … !=ƒ! ƒ…/. K=>%)…/. C>,2 … %>›…= K/2@ A … 1/30 C!%> 2= C>,2/.

8

2.p`q)eŠ a`kn)mni okhŠ{

2.1.q2=2, “*,L !=“ 2 K= % …%L C ,2/

q2=2,) “*,L !=“) 2 C>,2/, *=* "“ *%L ,…› … !…%L *%…- “2!3* ,,, …=),…= 2“ “ 3“2=…%"> …, !=“) 2…%L “. A/ , C% - “) 2= …=+!3ƒ%*.o!, !=“) 2 ,ƒ C ! *!/2, A/“> ……% "/! ƒ= 2“ (C !C … ,*3> !…% "2%!%“2 C ……/A K=>*=A) C%>%“= H,!,…%L % ,… A 2!, *%2%!= , !=““A=2!,"= 2“ *=* A…%+%C!%> 2…= … - !=ƒ! ƒ…= K=>*= 1, … “3?= C%“2% ……3E , "! A ……3E …=+!3ƒ*, (!,“.4).

o%“2% ……= …=+!3ƒ*= " K%>@H,…“2" “>3)= " K/"= 2 !="…%- A !…% !=“C! > ……%L, = "! A ……= (C%> ƒ…= ) " %K? A “>3)= A%› 2 K/2@ !=“C! > ……%L (C% %C! > ……%A3 ƒ=*%…3) ,>, “%“! %2%) ……%L.b*3!“%"%A C!% *2 K3 A C!,…,A=2@ 2=*› !="…%A !…% !=“C! > ……%L, )2% “%%2" 2“2"3 2 ! *%A … = , A qm,o 2.01.07#85* œm=+!3ƒ*, , "%ƒ L“2", B.

o%“2% ……= …=+!3ƒ*= "*>E)= 2 " “ K “%K“2" ……/L " “ C>,2/ , " “ C%>=.o!," A … *%2%!/ 2,C/ C%>%" , ,. " “%"/ .=!=*- 2 !,“2,*, …= ,…, 3 C>%?= ,.

1.o%> ,ƒ * !=A,) “*,.C>,2 C% H>=*%K 2%……%A3 %2 C>,2 >E:

9

2.),“2/L A …2…/L C%> C% › > ƒ%K 2%……%L C>,2 :

o!, C% “) 2 “%K“2" ……%+% " “= C>,2/ C>%2…%“2@ › > ƒ%K - 2%…= “> 3 2 C!,…,A=2@ ρ›/K = 2500 *+/A3.

g…=) …, …%!A=2,"…%L œC%> ƒ…%LB "! A ……%L …=+!3ƒ*, !…, m/A2 > A › 3.2=›…/. C ! *!/2,L 3“2=…=">,"= 2“ " ƒ=",“,- A%“2, %2 …=ƒ…=) …, C%A ? …,L.

p,“.4.a=>%)…= *> 2*= A%…%>,2…%+% ! K!,“2%+% C ! *!/2, “ K=>%)…/A, C>,2=A,:

1; 2; 3; 4 O +!3ƒ%"/ C>%?= ,: …= C>,23; "2%!%“2 C ……3E K=>*3;

+>="…3E K=>*3 , *%>%……3; 5O “2 …=

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