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Учебное пособие 800365

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F !/ 3 2 3 / 3 5

3 x 22 = (x, x) = [x]Te [x]e# R

sup Ax 22 =

sup [x]eT [A]T [A][x]e =

sup (x, A Ax).

x E, x 2=1

x E, x 2=1

x E, x 2=1

H 3 3 3 3 5

! 3 / 33 3 ! [A]T [A] 3 3 # 5

/ 3 3 3 3 3 G 3 ! λmax# ? G 3 ! / 5

3 3 (Ax, Ax)

! 3/ 3 # H 3 3/

A 2 = λmax. (7)

F / 3 / 3 /

3 A 2 3 7

n

(8)

A 2 = ( aij2 )1/2.

 

 

i,j=1

3 / / λ1 + λ2 + ... + λn J

3 ! [A]T [A]/ ! λk, k = 1, 2, ..., n/

3 / 3 λmax# " /

A 2 A 2.

(9)

F 3 3/ 3 3 ! [A] 3 n × n

33 G 3 # 9 3 / 5

3 G ! λn−1 3 3 5

pA(λ) 3 ! / 3 3 3#

M 3 ! 3 3/ 5

3 3 3 /

3 3 3 3 3 : 3 / 3

A G / ! # " 3 3 @

3 / 3 A G 3 3 5

3 #

F 3 / 3 3

3 / 3 G

3 3 #

% 4 /- ' F 5

F / @ 3 5

G 3 A 4F : A → A6/ 3

# H x A/ F x = x#

2 G 3 3 B#O# % 5A @

#

# F /

@ E 3 3 5

#

H 3 @ 5

! 4 3# T(U/ T.U6# 23 G / 3 3 3 % !

3 3 C[a, b]#

R 3 C[a, b] 3 3 A C[a, b] 3 3

/ ! G 3 7

ε > 0 δ > 0 / |t − t | < δ/

! x(t) C[a, b] |x(t ) − x(t )| < ε#

# 1 D !

C[a, b] 3 / @ 5

/ 3

C[a, b] 4 3 6 !

C[a, b])#

$ 6-

&-.*

? A J / @ E E# H 5

n An / 4B#B6/ An A n# F 3 3/ A& 0 E E&

λ& 0

pA(λ) = det([A] − λI)& & &

A − λI # "

Sp(A)#

' r(A) = = sup{|λ|, λ Sp(A)}#

R 3 3 3 2#$# / 5

@ 3 4 3# TBU/ T(U/ T.U67

r(A) = lim

 

An

.

(10)

n

→∞

 

 

 

 

 

 

 

 

? f (x) J ! / @

H 7

f (x) = f (0) + 1!1 f (0)x + 2!1 f (0)x2 + ... + n1! f (n)(0)xn + ... = cnxn,

n=0

3 Rf # F 3 ! f A

N

 

 

f (A) =

cnAn : f (A)x = lim cnAnx,

n=0

N →∞ n=0

@ # " @ 3 @ 5

/ 3 3 4 3# TBU/ T(U/ T.U6#

,

Rf 9 7 f (x)& 7 f (A)

A #

"3 G 3 3 @ /

# 1 3 3 !

3 /

 

01

λ2 . . .

0

 

 

 

λ

0 . . .

0

 

 

.

. .

 

,

 

.

 

 

 

 

 

 

 

 

 

 

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0

0

λn

 

 

 

 

 

 

 

 

G 3 3 ! f (A) 3

f (λ1) 0 . . .

0 f (λ2) . . .

.

. .

 

.

 

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.

 

 

 

 

0

0

 

 

 

.

f (λn)

2 G 3

 

0

cn(λ1)n

0

. . .

0

 

 

 

N

 

 

 

 

 

 

N

 

0

N cn(λ2)n . . .

0

 

 

 

 

0

.

 

 

 

cnAn =

.

 

 

 

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.

 

 

 

0

.

 

 

 

 

 

 

 

 

 

 

 

 

 

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0

 

0

N

n

 

 

 

 

cn(λn)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

0

 

 

 

 

 

 

 

 

 

 

R / λi @

N

f (λi) = lim cnλni / / / i|, i = 1, 2, ..., n

N →∞ n=0

3 3 ! f (x)#

H 3 q(x) / 5

3 / / / q(A)

@ A# G 3

3 3 @ / 3 3 3 5 *G 4 3#/ 3 / TBU6#

! E0 A& 0

E&

# 9 pA(A) = O#

3 3 3/ 3 ! A 3

n×n @ 3 R(x)/ R(A) =

O#

) / 3 3 ! 3 n × n

n2# ? G 3 3 ! I, A, A2, ..., An2 3 / / / @ 5

c0, c1, ..., cn2 / c0I + c1A + c2A2 + ... + cn2 An2 = O# 3 R(x) = c0 +c1x+c2x2 +...+cn2 xn2

3 ! A#

3 3 3 !

3 !#

" 4 0 A

exp(A) = I + 1!1 A + 2!1 A2 + ... + n1! An + ...

, ?&

I + A + A2 + ... + An + ...

(I − A)1 ! & I − A#

? /

3 ! ex = exp(x) 5

#

) 3 3/

(I + A + A2 + ... + An)(I − A) = I + A + A2 + ... + An − A − A2 − ... − An − An+1 = I − An+1.

H A < 1/ An+1 0 / /

(I + A + A2 + ... + An + ...)(I − A) = nlim (I + A + A2 + ... + An)(I − A) = nlim (I − An+1) = I.

→∞

→∞

N #

" 3 @ 3 4,'6 3 5

3 / 3 A < 1 3 r(A) < 1# ?

@ 3 #

$! 0 & 7 # - &

" 3 @ 3 3 3

3 # ? G 3 3 @

3 ! 3 ! 3

3 / 3 ! / 3 43 5

] 5 3 3 3 3 @ G 3 5 6# R 3 3 3

3 / 3

3 3 # ? G 3

5 #

G 3 3 3 5

3 # M 3 3 3 &

#

? 3

a21x1

+ a22x2

+ ... + a2nxn

= b2,

a11x1

+ a12x2

+ ... + a1nxn

= b1,

. . . . . . . . .

 

 

 

 

 

 

 

 

an1x1

+ an2x2

+ ... + annxn

= bn,

 

 

 

 

3 3 3 3 @ 5

Ax = b# ? 3/ / 5

3 ] 5 -77

A 0 0 & &

- &

=

n

j

 

|aii| >

|aij |, i = 1, 2, ..., n.

 

=1,j=i

H / i5 aii xi

/ 3 3

x2

= c21x1

+ c22x2

+ ...

+ c2nxn

+ d2

,

 

x1

= c11x1

+ c12x2

+ ...

+ c1nxn

+ d1

,

 

. . . . . . . . . . .

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

xn

= cn1x1

+ cn2x2

+ ...

+ cnnxn

+ dn,

 

 

 

 

n

 

 

 

 

 

 

 

 

 

 

 

 

 

 

di = bi/aii, cii = 0, cij = −aij /aii,

j=1 |cij | < 1, i = 1, 2, ..., n# 3

3 G 3 x = Cx

+

d/ 3

C

 

< #

 

 

 

 

 

1

 

 

 

 

 

 

 

) / 3 3 x0 = d/

3 3 x1 = Cx0 + d/ @ 3 /

k5 xk/ k + 15 3 3

xk+1 = Cxk + d, k = 1, 2, ...

(11)

, C = q < 1&

0

5 6 x = Cx + d & & 0

Ax = b# -

0 x0#

? 3 x2

x1/ 3 x2 = C(Cx0 + d) + d = C2x0 + (Cd + d) = C2x0 + (C + I)d# % 3/ x3 = C3x0 + (C2 + C + I)d# @ 3

xk+1 = Ck+1x0 + (Ck + Ck−1 + ... + I)d, k = 1, 2, ... .

 

(12)

" 3 3 B#-/ k → ∞

 

 

/

 

3 ! 4 6 (Ck + Ck−1 + ... + I) 3 (I − C)1

 

Ck+1

# ? G 3 3 3 4,&6

3 # R 3 G x # H /

4,&6 / 3 3

x = θ + (I − C)1d = (I − C)1d. ? x

x = Cx + d / 3 / (I − C)x = d/ 3

(I − C)x = (I − C)(I − C)1d = d.

H x 3 # H 3 #

R! 3 3 x − xk+1 E # ? 3 5

3 E 33 @ 3 5

/ 3 3

x − xk+1 E = (I + C + C2 + ... + Ck + Ck+1 + ...)d − Ck+1x0 (I + C + C2 + ... + Ck)d E =

= Ck+1x0 E + Ck+1d + Ck+2d + ... E Ck+1x0 E + Ck+1d E + Ck+2d E + ...

C k+1 x0 E + C k+1 d E + C k+2 d E + ... = C k+1 x0 E + C k+1 d E. 1 − C

F ! 3 3 3

3 3 xm − xm−1 E 3 (1 − q)ε/q/

q = C / ε J / /

3 / x − xm E ε#

) 3 3 3 3 3 3 5

3 ! 5

3 3 T,/ PU# ) 3

! 3 3 T(/ .U#

" @ @ G 3 3 5

! / G 3 3 !

4 ! 6#

* 8 * " ( &- $ $* +) " *. ,)& * +

( " #

R J 3 5

/ 3 / 3 3 3 5

3 # ? G 3 5

/

3 3 / 3 3 5

3 4 3 3 6# ! 5

3 5

3 3 3 3 # F 3

3 /

L L / G 3 3 5

# 3 3 3 3 5

3 / 3

#

! ! #

-

7 & 7 # ! 5

3 3 3 G 3 3 !

3 # ! 3 5

/ / ! #

% ) * ) &

,# ( ) ) ,-, F

A(x1, y1) B(x2, y2)/ x1 < x2# H / 5

@ A B/ / 3 3 #

( ) % % ? x1 < x2/ y1 > y2

! y(x) / A B7 y(x1) = = y1, y(x2) = y2# H ! y(x) / 3 5

/ @ 3 /

A B 3 3 #

O# ( ) ! ! ) 3

% # ? /

3 3

" 3 3 / 3 5 # 3 / # H / 5

/ ) 3 /

/ 5

3 * # M 3/

3 @ 3 3

@ / 3 @ 3 4 3 / OX6#

G 3 G 3 4 5 / 3 @ 6 @ 3

! # H 3 3 3 /

3 / 3/ 3 5

/

3 # * 3 / 3 J / 3

@ J ! 3 5

# H G @ G 3 3 ! / /

! ! # 9 7 7 0 7

# F 3 / @ 3 3 3 !

y(x), x1 x x2

x

2 1 + y (x)2dx,

J1(y(x)) = x1

@ G 3 3 ! @

J3(y(x)) = x2

y(x)dx,

x1

 

/ J1(y(x)) # M !

y = y(x), x1 x x2, G 4 6/

) / 3 @ [x1, x2] OX# ? G 3 y(x1) = y(x2) = 0#

* ! 3 3 / 3 3 3

#

( 3 - -

? 3 3 3/ 3

G 3 3 77 ! f (M) 5

3 # ? M0 G 3 3 # H M0

M = M0 +

M

 

f (M0,

M) = f (M) − f (M0) = df (M0, M) + αM)

(1)

/ !

#

M df (M0, M) ! / ! 5 3 3 f (M0M/ M = M − M0/ ! 3

3 3

df (M0) = grad f (M0) · M,

M M0M#

77 0 4 f (M0) = 0

gradf (M0) = 06/ ! 0 0

@

f (M0) 3 M

f (M0)#

 

H df (M0,

M)/ / 7 M/ 3 5

df(M0, − M) = −df (M0, M)/ G 3 f (M0)

M0 3 #

9 & - 7

M0& df (M0, M) 0#

? 3 / 3 5

G 3 3/ M/ f (M) = 0

gradf (M) # H 5

! / !

! - #

R / G 3 3 ! J(y) 3

3 3 # % 3 / 3 3 ! y(x)

! y(x) + δy(x)/ 3 !

δy 3 @ 3 ! ! y/ 5

@ 3 4 @ 6 ! J

3 / 3 4,67

J = J(y + δy) − J(y) = δJ(y, δy) + α(δy).

(2)

M δJ(y, δy) α(δy) 5

@ J# ? / δy, δ1y, δ2y

γ

6 δJ(y, δ1y + δ2y) = δJ(y, δ1y) + δJ(y, δ2y):