Solutions manual for mechanics and thermodynamics
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2.If the number of molecules in an ideal gas is doubled and the volume is doubled, by how much does the pressure change if the temperature is held constant ?
SOLUTION
The ideal gas law is
P V = NkT
If T is constant then
P / NV
If N is doubled and V is doubled then P does not change.
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CHAPTER 16. KINETIC THEORY OF GASES |
3.If the number of molecules in an ideal gas is doubled, and the absolute temperature is doubled and the pressure is halved, by how much does the volume change ?
(Absolute temperature is simply the temperature measured in Kelvin.)
SOLUTION
Chapter 17
Review of Calculus
103
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CHAPTER 17. REVIEW OF CALCULUS |
1. Calculate the derivative of y(x) = 5x + 2.
SOLUTION
y(x) = 5x + 2
y(x + ¢x) = 5(x + ¢x) + 2 = 5x + 5¢x + 2
dxdy =
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lim y(x + ¢x) ° y(x) ¢x
lim 5x + 5¢x + 2 ° (5x + 2) ¢x
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2.Calculate the slope of the curve y(x) = 3x2 + 1 at the points x = °1, x = 0 and x = 2.
SOLUTION
y(x) = 3x2 + 1
y(x + ¢x) = 3(x + ¢x)2 + 1
=3(x2 + 2x¢x + ¢x2) + 1
=3x2 + 6x¢x + 3(¢x)2 + 1
dy dx
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lim |
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lim |
3x2 + 6x¢x + 3(¢x)2 + 1 ° (3x2 + 1) |
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lim (6x + 3¢x) |
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CHAPTER 17. REVIEW OF CALCULUS |
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3. |
Calculate the derivative of x4 using the formula |
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your answer by calculating the derivative from dy |
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y(x+¢x)°y(x) |
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SOLUTION
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Now let's verify this.
y(x) = x4
y(x + ¢x) = (x + ¢x)4
= x4 + 4x3¢x + 6x2(¢x)2 + 4x(¢x)3 + (¢x)4
dy |
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y(x + ¢x) ° y(x) |
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dx |
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x4 + 4x3¢x + 6x2(¢x)2 + 4x(¢x)3 + (¢x)4 ° x4 |
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¢x!0 |
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¢x |
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lim [4x3 + 6x2¢x + 4x(¢x)2 + (¢x)3] |
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which agrees with above |
107
4. Prove that dxd (3x2) = 3dxdx2 .
SOLUTION
y(x) = 3x2
y(x + ¢x) = 3(x + ¢x)2 = 3x2 + 6x¢x + 3(¢x)2
dy |
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(3x2) = |
lim |
y(x + ¢x) ° y(x) |
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¢x |
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¢x!0 |
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¢x!0 |
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lim 6x + 3¢x |
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¢x!0 |
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Now take
y(x) = x2 ) dxdy = 2x
Thus
dxd (3x2) = 6x
= 3dxd x2
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CHAPTER 17. REVIEW OF CALCULUS |
5.Prove that dxd (x + x2) = dxdx + dxdx2 .
SOLUTION
Take y(x) = x + x2
y(x + ¢x) = x + ¢x + (x + ¢x)2
=x + ¢x + x2 + 2x¢x + (¢x)2
dy |
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(x + x2) = lim |
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y(x + ¢x) ° y(x) |
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dx |
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lim |
x + ¢x + x2 + 2x¢x + (¢x)2 ° (x + x2) |
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¢x!0 |
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lim (1 + 2x + ¢x) |
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::: d |
(x + x2) = dx |
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dx dx2
dx
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6.Verify the chain rule and product rule using some examples of your own.
SOLUTION
your own examples
110 |
CHAPTER 17. REVIEW OF CALCULUS |
7.Where do the extremum values of y(x) = x2 ° 4 occur? Verify your answer by plotting a graph.
SOLUTION
y(x) = x2 ° 4
0 = dxdy = 2x
::: x = 0
y(0) = 0 ° 4 = °4
::: extreme occurs at (x; y) = (0; °4)
The graph below shows this is a minimum.