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dt

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0 ( ( (" 0 f

S \

( " 0 f ( 3 3 ( 5

ddt2 x(t) + 0.7α dtd x(t) + x(t)3 + q(t) 1 x(t) = 0 .

dtd q(t) = α −0.16q(t) + x(t)2 .

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%

. ( ( ( + / 0 R3

dx1

= −βx1 + x2x3,

dx2

= −σx2 + σx3,

dx3

= −x1x2 + ρx2 − x1.

dt

dt

dt

3 (0 x1(t) 0 / 5 ( 0 " 3

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x t

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x2

ρ

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! ""#; ; "

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x˙ 1 = (x2 + x3), x˙ 2 = x1 + ax2, x˙ 3 = b + x1x3 − cx3

a = 0.17 b = 0.4 c = 8.5

, 8 '

S . 4 (

 

3x˙ + y˙ + x = 1

x(0) = 0, y(0) = 0

 

 

 

x˙ + 4y˙ + 3x = 0

. 4 (

x˙ − x − 2y = t

x(0) = 2, y(0) = 4

y˙ 2x − y = t

W . 4 (

 

 

 

 

 

x − x˙ + 9x − y¨ − y˙ 3y = 0,

x(0) = 1,

x˙ (0) = 1

 

x + x˙ + 7x

y¨ + y˙

5y = 0,

y(0) = 0,

y˙(0) = 0

 

 

 

 

 

 

R

. 4

 

 

 

 

 

y¨ + y˙ 2y = et,

y(0) = 1,

y˙(0) = 0

 

. 4 (

 

 

 

x¨ − x + y + z = 0,

x(0) = 1,

x˙ (0) = 0

 

y¨

y + x + z = 0,

y(0) = 0,

y˙(0) = 0

 

 

 

 

 

 

 

 

 

 

 

 

z¨ − z + x + y = 0,

z(0) = 0,

z˙(0) = 0

 

 

 

 

 

 

 

 

 

 

 

 

[

. 4

 

 

 

 

 

y(4) + y(3) = cos t, y(0) = 0,

y˙(0) = 0,

y¨(0) = 0, y(3)(0) = 2

SW[

X ' 5Z 5 ( 4 3 y˙ + y2 = x2

Y . 4

y(4) + 4y = t2, y(0) = 0, y˙(0) = 1, y¨(0) = 2, y(3)(0) = 3

\ . 4

4y(3) 8y(2) 2y˙ = 8et, y(0) = 1, y˙(0) = 1, y¨(0) = 1

S . 4

y(3) 6y(2) + 11y˙ 6y = 0, y(0) = 0, y˙(0) = 0, y¨(0) = 10

SS . 4

y(4) + 2y(2) = t sin t, y(0) = 0, y˙(0) = 10, y¨(0) = 0.1, y(3)(0) = 0.01

S . 4 (

x¨ − x + 2y = 0,

x(0) = 0, x˙ (0) = 1

x¨

2y = 0,

y(0) = 1/2

 

 

 

SW 3 4 % ( 0 5 0

T U ( 4 3 0 ( " ( 4

3 5Z ( 4 (

b ( 3 U ( ( 3"

(

(1 + 2λ(P ))

^

λ(P ) =

PH −P

V (P ) = V0

 

PH −Patm % 3

H = 500m PH H Patm (

" 0 ( 3 3 T/ (3 0 3 3 4 ( ((

3 3 " % (

0 3 0 3

f = ρv22 S" ρ 0 " v 3 4 " S 0 Z 0 0 3

SWX

SR 3

b 3 q(t) 3 5

 

d2q

 

dq

q

L

 

+ R

 

+

 

= V (t)

2

 

 

 

dt

 

dt

C

0 T(

V (t) = LdIdt + RI + Cq

( 0 I = dqdt

f 0 % 3% 0 ( "

( 0 V (t) = 3 ( 0 ( 3

V (t) = 3 − a exp(t)" a ( f /

S

45 ( Y (( 0 X (

 

45 3 t0 = 10 0 0 2

 

3 (

 

 

 

 

y¨ = −g +

α(t)

y(0) = 700,

y˙(0) = 0 .

 

 

 

,

 

 

m

 

b g

= 9.81 m/s2

0 3" α(t) f

 

/

3" (

α(t)

= k1y˙(t)2 0 t < t0

 

α(t) = k2y˙(t)2 T/ (3 0 0 45

 

( 5 0 k1 = 1/150 k2 = 4/150

 

S[

2 3 S ( c d

 

/ 4 ( S ( 0 ( (

 

T/ (3" 4 0

SWY