Individual tasks for problem 2.4. The law of electromagnetic induction

In accordance with your variant to solve one of the following problems listed below (The number of problem statement and all necessary input data are reduced in the table 2.4. ):

1 Coil of area of S has N loops of wire with resistance of R and is situated in the homogeneous magnetic field with induction of B. The loop’s plane makes the angle of  with magnetic induction lines. Within the changing of magnetic field direction on the opposite one, the charge of Q runs over the coil. With the values of magnitudes, set in the table 2.4, find the magnitude, which is set in the last column of the table.

2 On the iron core solenoid with inductance of L and area of cross-section of S is put on the wire ring. The winding of solenoid has loops of N. When the circuit is closed, through the solenoid the current I is been settled during the time interval t. The average EMF of _AVE is induced in the wire ring. The magnetic permeability of iron is  within these conditions. With the values of magnitudes, set in the table 2.4, find the magnitude, which is set in the last column of the table.

3 In the homogeneous magnetic field with induction of B rotating the short coil, which has N loops of diameter of D. The axis of rotation lies in the plane of loops of the coil and is perpendicular to the lines of magnetic field induction. Angular velocity of rotation is  (frequency of rotation of , period of Т). The maximal value of EMF of induction, which appears in the coil is _MAX. With the values of magnitudes, set in the table 2.4, find the magnitude, which is set in the last column of the table.

Tables of task variants

Table 2.4

Variant

Statement

N

S , cm2

D, сm

L , сm

R , Ω

В , Т

β

Q , mC

I , A

μ

AVE, V

Δt, ms

εМАX, V

ω , rad/s

ν , 1/s

Т , ms

Find

1

3

–

–

12

–

–

0,4

–

–

–

–

–

–

30

60

–

–

N

2

1

100

80

–

–

20

0,2

30о

-

–

–

–

–

–

–

–

–

Q

3

3

100

–

10

–

–

–

–

–

–

–

–

–

15

90

–

–

В

4

2

500

4

–

30

–

–

–

–

2

–

0,4

2

–

–

–

–

μ

5

1

300

40

–

–

–

0,2

60о

4

–

–

–

–

–

–

–

–

R

6

3

500

–

20

–

–

0,3

–

–

–

–

–

–

90

–

–

–

ω

7

1

400

50

–

–

40

0,1

–

5

–

–

–

–

–

–

–

–

β

8

2

600

4

–

25

–

–

–

–

0,8

400

–

3

–

–

–

–

εave

9

3

300

–

5

–

–

–

–

–

–

–

–

–

50

–

25

–

В

10

1

100

40

–

–

15

–

40о

6

–

–

–

–

–

–

–

–

В

11

3

–

–

18

–

–

0,2

–

–

–

–

–

–

60

–

15

–

N

12

1

200

50

–

–

10

0,3

60о

–

–

–

–

–

–

–

–

–

Q

13

3

100

–

8

–

–

–

–

–

–

–

–

–

80

–

–

20

В

14

2

800

3

–

20

–

–

–

–

0,5

–

0,3

1

–

–

–

–

μ

15

1

–

20

–

–

30

0,3

30о

2

–

–

–

–

–

–

–

–

N

16

3

100

–

8

–

–

0,4

–

–

–

–

–

–

50

–

–

–

Т

17

1

200

20

–

–

5

0,3

–

48

–

–

–

–

–

–

–

–

β

18

3

200

–

20

–

–

0,1

–

–

–

–

–

–

–

–

20

–

εmaz

19

2

700

8

–

40

–

–

–

–

0,6

600

–

2

–

–

–

–

εave

20

3

–

–

15

–

–

0,1

–

–

–

–

–

–

40

–

–

30

N

21

1

500

10

–

–

25

–

20о

4

–

–

–

–

–

–

–

–

В

22

3

200

–

10

–

–

0,2

–

–

–

–

–

–

70

–

–

–

ν

23

2

900

6

–

35

–

–

–

–

–

800

0,6

4

–

–

–

–

I

24

3

400

–

15

–

–

0,3

–

–

–

–

–

–

–

50

–

–

εmaz

25

2

–

5

–

25

–

–

–

–

1

200

0,5

1

–

–

–

–

N

26

2

650

-

–

10

–

–

–

–

0,2

300

0,1

5

–

–

–

–

S

27

3

450

–

–

–

–

0,4

–

–

–

–

–

–

80

–

–

25

D

28

2

150

7

–

15

–

–

–

–

5

200

0,7

-

–

–

–

–

t

29

1

400

-

–

–

5

0,15

70о

6

–

–

–

–

–

–

–

–

S

30

2

900

3

–

-

–

–

–

–

0,4

500

0,2

6

–

–

–

–

L