- •Lecture 5.
- •Example
- •Examples for your home work. Initial conditions equal zero
- •Case for the simple roots and real coefficients, figuring in polynomials
- •Response for rectangle impulse
- •Application of the L-transform to solution of the system of linear equations with
- •Find the solution of the following system
- •The second example
- •Find the solution of the following system of equations
- •Is it possible to apply the L-approach to the solution of the system
- •Estimation of electric circuits
- •Important corrections
- •The third example
- •The last example. Filter.
- •Mathematical Appendix: How to solve the difference equations?
- •**Let us come back to “our” Filter. In this case it is convenient
- •In order to obtain the partial solution of the general formula we consider
- •The basic home work: try to reproduce all my Math!
Estimation of electric circuits
Successive combination (impedances), current is the same
U=summation of voltages
Parallel connection of the impedances, the applied voltage is the same
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Important corrections
Operator equations for each closed circuit
How to close this system of operator equations?
For any branching point
And usage of the second Kirhhoff’s law
The role of the Duhamel integral
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Z(L)
Z(C) |
Z(R) |
U0
The first example and its solution.
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i1 |
Find i1(t)-? |
Z(R)
Z(R2)
Z(R1)
U0 |
Z(L) |
Z(C) |
|
i2 |
The second example and its solution
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The third example
The electromotive force (e.m.f) is acting on RLC circuit on the time segment 0<t< / and equals U0sin t.
Then it equals to zero. Find the current after the time t > / . For this case it is necessary to use the H-function
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The last example. Filter. |
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||
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0.5Z’ |
Z’ |
|
0.5Z’ |
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|
I1 |
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|
I0 |
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e.m.f |
Z |
Z |
Z |
Z” |
I -I |
1 |
I1 –I2 |
In-1 –In |
0 |
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|
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Mathematical Appendix: How to solve the difference equations?
Example – Fibonacci numbers
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**Let us come back to “our” Filter. In this case it is convenient to find a solution of difference equation in the form
The constants are obtained from the first and the last difference equations:
After some algebraic manipulations we obtain finally
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In order to obtain the partial solution of the general formula we consider choke output filter
(дроссельный фильтр):
For it we have Z’=R+Ls, Z=1/Cs, U=U0
We find the original with the help of expressions given in pages 3 and 4.
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