
С2. МОИ. Презентации / Булевы функции 3 (v. 1.2)
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Разложение функции по переменным
Следствие 2. Разложение булевой функции по
всем переменной:
m n : f x1, x2 ,..., xn
x1 1 ... xn n f ( 1,..., n)
( 1 ,..., n)
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Разложение функции по переменным
Следствие 2. Разложение булевой функции по
СДНФ –
всем переменной: |
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совершненная |
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m n : |
f x1, x2 ,..., xn |
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дизъюнктивная |
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нормальная форма |
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Дизъюнктивные нормальные формы
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Пример. СДНФ
f (x1, x2 , x3)
x1x2 x3 x1x2 x3 x1x2 x3x1x2 x3 x1x2 x3
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Дизъюнктивные нормальные формы
x1 |
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x3 |
f |
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Пример. СДНФ
f (x1, x2 , x3)
x1x2 x3 x1x2 x3 x1x2 x3x1x2 x3 x1x2 x3
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Дизъюнктивные нормальные формы
x1 |
x2 |
x3 |
f |
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Пример. СДНФ |
f (x1, x2 , x3) |
x1x2 x3 x1x2 x3 x1x2 x3 |
x1x2 x3 x1x2 x3 |
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Дизъюнктивные нормальные формы
x1 |
x2 |
x3 |
f |
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Пример. СДНФ
f (x1, x2 , x3)
x1x2 x3 x1x2 x3 x1x2 x3
x1x2 x3 x1x2 x3
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Дизъюнктивные нормальные формы
x1 |
x2 |
x3 |
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Пример. |
СДНФ |
f (x1, x2 , x3) |
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x1x2 x3 x1x2 x3 x1x2 x3 |
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2 x3 |
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Дизъюнктивные нормальные формы
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Пример. СДНФ
f (x1, x2 , x3)
x1x2 x3 x1x2 x3 x1x2 x3
x1x2 x
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Дизъюнктивные нормальные формы
x1 |
x2 |
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Пример. СДНФ
f (x1, x2 , x3)
x1x2 x3 x1x2 x3 x1x2 x3x1x2 x3 x1x2 x3
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Дизъюнктивные нормальные формы
x1 |
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x3 |
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Пример. СДНФ
f (x1, x2 , x3)
x1x2 x3 x1x2 x3 x1x2 x3x1x2 x3 x1x2 x3
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