- •For course design
- •3 Selection of route, type of cable and transmission systems
- •3.1 Short characteristic of terminal points
- •3.2 The choice of fiber optic transmission lines route
- •3.3 Selection and justification of optic fiber type
- •3.4 Selection and justification the construction and type of optical cable
- •3.5 Selection and justification of fiber optic transmission system
- •3.6 Control questions
- •4.2 Choice and substantiation of the type of optical fibers
- •4.3 Choice and substantiation of the optical cable
- •4.2 Choice and substantiation of the Fiber optic transmission system (fots)
- •5 Calculation of optical properties of fibers and parameters of cable transfer
- •5.1 Determination of optical fiber parameters
- •5.2 Determination of losses in optical fiber
- •5.3 Calculation of running dispersion of the signal in single mode optical fiber
- •6 Calculation of regeneration length of optical fiber transmission lines, chart of energy levels
- •6.1 Calculation of the length of the regeneration section by attenuation
- •6.2 Calculate the length of the regeneration section by dispersion
- •6.3 Placement regeneration points along the route of focl
- •6.4 Constructing a chart levels of energy potential fots at the length of one area of regeneration
- •7 Protection of optical cable from the influence of external electromagnetic fields
- •Protection of optical cables from lightning strikes
- •Calculation of the dangerous effects of magnetic influences
- •Calculation of reliability of linear structures fots
- •9 Organization of works on construction and installation project lines. Budget and financial calculation of linear structures of focl
- •9.1 Organization of construction works
- •9.2 Budget and financial calculations
6.2 Calculate the length of the regeneration section by dispersion
Together with the mentioned above conditions EKD length must satisfy the requirements for dispersion [6].
, (6.4)
where В – transfer rate on the optical interface, bit / s;
– rms
linear dispersion of
OF,
s / km.
Value
is chosen as the lowest calculated by formulas (6.2) and (6.4).
Transfer rate on the optical interface is determined according to Table. 4.5 or from the ratio
, (6.5)
6.3 Placement regeneration points along the route of focl
Considerable length of EKD FOCL allows you to place regenerators in localities where there are at least two independent power sources. Placing regenerators made based on budget performance and acceptable dispersion on EKD.
Given
the power budget between regenerators FOCK
must
lie within.
.
Placing regenerators on the route considering the above conditions, it is necessary to determine the length of each EKD. Calculate the margin and dispersion for each EKD on formulas.
. (6.6)
. (6.7)
, (6.8)
.
(6.9)
This
value
should
be compared with the accepted value
,
and
-
with the value
[10].
As a result of calculation of lengths EKD a block diagram of FOCL is made up, which indicates non serviced regenerative stations, EKD length, cable type and numbering NRS (Figure 4.1).
6.4 Constructing a chart levels of energy potential fots at the length of one area of regeneration
Energy potential of FOTS determines energy opportunities of the used equipment for covering the losses in a linear path. The higher the value of EP, the greater the distance on which you can transmit information. Size of EP depends primarily on the radiation power of transmitting optical module (TOM) and sensitivity of optical receiver module (ORM).One can increase the value of EP in the following ways:
1) use TOM laser diodes (LD) instead super fluorescent diodes;
2) apply ORM with better sensitivity (e.g., replace p-i-n photodiode (PD) on the avalanche photodiode );
3) to reduce energy losses when entering it in OF (using microlenses, etc.).
Visual
representation of the EP and distribution losses of power radiation
in a linear path gives a diagram of the energy levels of the
potential FOTS. Chart built for areas of regeneration (Fig. 6.1) in
the coordinates: the level of optical power P
(dBm), the distance Lp
(km). Vertical axis A and B are power level TOM (at point A) and
sensitivity ORM (in b), respectively. An A axis contains segments
(Рпер
+
),
and
the axis B - (Pпр+рз+2αвп).
Along
the X axis attenuation of OF is shown as a line with a slope
lбуд
(dB) for each building length lбуд,,
at the junction of building lengths plotted segments, level of
attenuation in detachable
joints ОК
–
н.
You can consider, that FOTS designed correctly, if constructed so diagram of energy levels cross the axis B at a point approximately equal to (or slightly higher) than the value рз+Pпр.
Chart
levels of energy potential (Fig. 6.1) is constructed for FOTS STM-4
with a length
=
70 km.
7 Protection of optical cable from the influence of external electromagnetic fields
Protection of optical cables from lightning strikes
Methods of calculating the probability of annual damage to FOCL is based on allowable current of lightning in metal surfaces OF, at which there is no damage to the cable and no connection breaks, and the breakdown of external damage to the hose is not considered as the damage of OF. The magnitude of this current depends on the design of OF, as a rule, calculated experimentally[10].
The estimated probable amount of damage per year depends on the number of lightning strikes, which falls on the surface area that is directly subject to lightning or arc that occurs between the point of impact and cable. Chance of apperence of current in underground cables, which can cause it damage is generally found t by the formula [10]:|
, (7.1)
where
- probabilistic average number of lightning strikes from 1 to 250 kA
into FOCL cable, which is projected;
-
rate risk of damage of optical cable with metal elements [11], which
is determined from Fig. 7.1;
– surface
coefficient (given in Table 3.2.), which is
taken
into account when
the
width of
convergence
of
OC
with terrestrial objects is
smaller
than
;
–
maximum
radius of the spark zone , m.
Value is calculated by the formula:
,
(7.2)
where q – density of lightning strikes per year per km2 earth's surface, year/km2;
– conventional
radius of
the spark
zone, m;
L –length of the line, km.
Let us consider L = 100 км.
The value of q is calculated by the expression:
, (7.3)
where С = 0,067 – average number of lightning strikes per 1 км2 of ground during one hour of thunderstorm;
Т
– average duration of storms in hours.
Conventional
radius
of the spark zone
is defined by the formula:
, (7.4)
where
– resistivity of the soil on the route length
L
of
FOCL,
Ohm • m;
– breakdown voltage of
electric
field in the soil,
kV / m.
Value
varies
from
250 kV/m
and
= 1000 Оm·m
till
до 500 kV/m
and
1000 Оm·m.
To
compare the results with the permissible limits of the expected
probability of damage of OF with metallic elements it is necessary to
calculate
for L
100
km from the formula:
, (7.5)
where
–norm
for the possible
number of damage per 100 km cable route for transport FOCL
= 0,1.
If
,
then the protection to the cable
is
not needed, if this inequality is not satisfied, then apply methods
of protection, such as:
using one or two storm protected cables of type PS-70, or other types;
replacement of cable by dielectric one
|.
Calculating
protection
of OF
cable is as follows. To evaluate the effectiveness of a rope,
factor screening
is
used
[11].
,
(7.6)
where
– allowable
test pulse current, kA;
–current
in the
circle
"protective
rope
wire-ground.".
From
the value
the amount of possible damage to the cable after cable laying of
protective rope is estimated, while instead of
in calculation of Кр
the value
is
taken.If
you
need to use two ropes. The coefficient of screening for different
types according to [11] cables are listed in Table. 7.1 ... 7.4.
Table 7.1 - Coefficient of screening one copper wire or bimetallic cable with a diameter of 4 mm
The distance between the protective wire and cable , mm |
Coefficient of screening one copper wire or bimetallic cable with a diameter of 4 mm |
|||
Diameter of cable jacket, mm |
||||
15 |
20 |
25 |
30 |
|
300 |
0,576 |
0,596 |
0,612 |
0,626 |
400 |
0,571 |
0,590 |
0,605 |
0,617 |
600 |
0,566 |
0,582 |
0,596 |
0,607 |
Table 7.2 - Coefficient of screening two copper wire or bimetallic cable with a diameter of 4 mm
Factor of screening or two copper wire or bimetallic cable of diameter of 4 mm and a depth of laying cable 1.2 m and depth of cables laying 0.4 m |
||||
The distance between the protective wires b, mm |
Diameter of cable jacket, mm |
|||
15 |
20 |
25 |
30 |
|
300 |
0,428 |
0,443 |
0,456 |
0,467 |
400 |
0,418 |
0,433 |
0,446 |
0,457 |
600 |
0,404 |
0,419 |
0,431 |
0,442 |
800 |
0,394 |
0,409 |
0,421 |
0,432 |
1000 |
0,387 |
0,401 |
0,414 |
0,424 |
1500 |
0,675 |
0,389 |
0,401 |
0,411 |
2000 |
0,369 |
0,383 |
0,394 |
0,403 |
3000 |
0,363 |
0,376 |
0,386 |
0,395 |
4000 |
0,360 |
0,372 |
0,382 |
0,390 |
Table 7.3 - Coefficient of screening a galvanized steel wire ПС-70
The distance between the protective wire and cable , mm |
Coefficient of screening a galvanized steel wire ПС-70 |
|||
Diameter of cable jacket, mm |
||||
15 |
20 |
25 |
30 |
|
300 |
0,662 |
0,685 |
0,704 |
0,720 |
400 |
0,657 |
0,678 |
0,695 |
0,710 |
Table 7.4 - Coefficient of shielding of two galvanized steel wires ПС-70
Factor of screening of two galvanized steel wires or bimetallic cable of diameter of 4 mm and a depth of laying cable 1.2 m and depth of cables laying 0.4 m |
||||
The distance between the protective wires, mm |
Diameter of cable jacket, mm |
|||
15 |
20 |
25 |
30 |
|
300 |
0,518 |
0,536 |
0,552 |
0,565 |
400 |
0,506 |
0,524 |
0,540 |
0,553 |
600 |
0,488 |
0,507 |
0,522 |
0,535 |
800 |
0,477 |
0,495 |
0,510 |
0,523 |
1000 |
0,468 |
0,486 |
0,500 |
0,513 |
1500 |
0,454 |
0,471 |
0,485 |
0,497 |
2000 |
0,447 |
0,463 |
0,477 |
0,488 |
3000 |
0,439 |
0,454 |
0,467 |
0,478 |
4000 |
0,435 |
0,450 |
0,462 |
0,472 |
