
- •Ministry of education and science of ukraine
- •National Aviation University
- •Explanatory note
- •For course paper
- •Kiev 2013
- •1. Thermodynamic calculation of gas-turbine power plant
- •Calculation of working body parameters.
- •In this case pressure drop degree in power turbine and work in it:
- •1.2. Calculation of main parameters of gas-turbine power plant
- •2. Gasdynamic calculation of gas-turbine power plant
- •2.1 Determination of diametrical sizes on the entry of the compressor
- •2.2. Determination of stages and air compression work distribution in two-spool compressors
- •2.3. Determination of diametrical sizes on the entry of the compressor turbine and number of its stages.
- •2.4. Determination of diametrical sizes at the entry to the power turbine and at the exit from it, number of power turbine stages
- •2.5 Determination of diametrical sizes and numbers of hpt and lpt stages.
- •2.6. Determination of powers and frequencies of rotation of rotors in compressors and turbines.
2.3. Determination of diametrical sizes on the entry of the compressor turbine and number of its stages.
In GTPP with two-spool compressor LPC rotates due to low pressure turbine (LPТ), аnd HPC – due to high pressure turbine (HPТ).
Geometrical sizes on the entry to the HPT (section 3) and on the entry to the LPT (section 3H) are determined the same as for one-spool engine. For determination geometrical sizes between HPT and LPT, at first, their works LHPT і LLPT are calculated by the formulas:
LHPT = LHPC/[(1 +gfuel)(1 – gcooling – gexchange)] = 242150.53 / [(1 +
+ 0.0213)(1 – 0.08 – 0)] = 257717,711 (J/kg) ,
LLPT = Lt – LHPT = 451591.652 – 257717.711 = 193873.941 (J/kg)
Temperature Т*3H and pressure р*3H after HPT are defined as:
(K)
(Pa)
HPT efficiency value *CH is taken greater than value*t (chosen on thermodynamic calculation) on 0,01–0,02.
Let’s consider the section before HPT.
Cross sectional area at the entry of the HPT is defined by the formula:
(m2)
Mean diameter on the entry of the HPT is equal to:
D3m = D2t (1.1 ÷1.2) = 1.15 ∙ 0.482 = 0.5543 (m)
h3 = F3/(3,14D3m) = 0.0507 / (3.14 ∙ 0.5543) = 0.0291 (m),
D3t = D3m + h3 = 0.5543 + 0.0291 = 0.5834 (m),
D3H = D3m – h3 = 0.5543 – 0.0291 = 0.5252 (m).
Further let’s consider section after HPT (3Н-3Н).
Cross sectional area at the exit from the HPT is defined by the formula:
(m2)
where Gt = Gair(1 + gfuel)(1– gcooling – gexchange) = 27.724∙(1 + +0.0213)(1-0.08) = 26.049 – gas expenses in turbine; cc = 0,97...0,99 (taken in thermodynamic calculation); n = 0,985...0,995 – coefficient of total pressure losses in the nozzle; m3 = 0,0396; q(λ3) = 1 (because in turbine first stage always there is supercritical pressure difference λ3 = 1) – flux density function, α1 = 15–20 ° hence sin α1 = 0.309 .
Choosing a type of turbine we can find mean diameter, vane height, tip and hub diameters.
At D3Hm = const = D3m = 0.5543 m,
h3H = F3H/(3,14D3Hm) = 0.0979 / (3.14∙0.5543) = 0.0562 (m),
D3Ht = D3m + h3H = 0.5543 + 0.0562 = 0.6105 (m),
D3HH = D3m – h3H = 0.5543 – 0.0562 = 0.4981 (m).
After determination the value of angular velocity on the mean diameter of compressor turbine utcm= uHPC ∙ D3Hm / D1t = 411.25 ∙ 0.5543/ 0.522 = 436.697 (m/s) and choosing the loading coefficient у*= 0,45–0,6 (assume as y* = 0.525), let’s determine approximate number of compressor turbine stages zt.k. by the formula:
zt.k
=
.
By approximation we have 3 stages of compressor turbine. Values
Lt
та *c
are
taken
from
thermodynamic calculation.
2.4. Determination of diametrical sizes at the entry to the power turbine and at the exit from it, number of power turbine stages
Cross sectional area F4 at the entry to the power turbine is defined by the formula:
(m2)
where Gt = Gair(1 + gfuel)(1– gexchange) =27.724∙(1+0.0213) = 28.315 – gas expenses through the power turbine; Т*4, р*4 – gas temperature and pressure before power turbine that is taken fro thermodynamic calculation; т4 = 0,0309; 1 = 20–25(assume as 1 = 23, sin 1 = 0.3907) ; l = 0,98–0,99 – coefficient of pressure losses between turbines. If there is supercritical pressure difference in the power turbine nozzle q(4) = 1.
Assume that compressor turbine has shape with constant mean diameter.
At D4m = const = D3Hm = 0.5543 m,
h4 = F4/(3,14D4m) = 0.195 / (3.14∙0.5543) = 0.112 (m),
D4t = D4m + h4 = 0.5543 + 0.112 = 0.6663 (m),
D4H = D4m – h4 = 0.5543 – 0.112 = 0.4423 (m).
Cross sectional area F5 at the exit from the power turbine is defined by the formula:
(m2),
where value 5 in the range 0,5–0,7 (assume that 5 = 0.6), let’s determine value q(5) = 1,5275(1 – 0,14352)3,02 = 1.527 ∙ 0.6 ∙ (1-– 0.143 ∙ 0.62)3.02 = 0.781. Values Т*т, р*т are taken from thermodynamic calculations.
Let’s determine diametrical sizes at the exit from the power turbine: tip diameter d5t, mean d5m and hub d5H diameters and vane height h5.
At D5H = const = D4H = 0.4423 m,
(m),
h5 = (D5t – D5H) / 2 = (0.7713 – 0.4423) / 2 = 0.1645 (m),
D5m = D5H + h5 = 0.4423 + 0.1645 = 0.6068 (m).
Moreover, for providing the enough strength of turbine last stage vane, it is necessary to fulfill the inequality D5m/h5 > 4.
Let’s check this condition D5m/h5 = 0.6068 / 0.1645 = 3.7 (m). Condition is satisfied.
At first, angular velocity on mean diameter at the entry to the power turbine is chosen (for non-coolant turbine value uptm is taken in the range 220–280 m/s, assume that uptm = 250 m/s) and power turbine stage number is found according to the formula:
zpt = 2у*2Lpt/(*ptu*2ptm) = 2 ∙ 0.5252 ∙ 306026.710 / (0.9 ∙ 2502) = 3.0
Value у* for power turbine is chosen in the same range as for compressor turbine (assume as y* = 0.525).