
- •Differential equation of first order. Separable Equations
- •2. Homogeneous Equations. Linear de of first order.
- •3. Bernoulli Equation. Singular Solution
- •4. Ricatti Equation.
- •5. Exact Equations
- •Using an Integrating Factor
- •Existence and uniqueness of solution of Cauchy problem for de of first order and system of equations.
- •Implicit Equation. Introducing the parameter.
- •Singular Solutions.
- •Lagrange and Clairaut Equations.
- •Reduction of Order.
- •Linear homogeneous and non-homogeneous de of n-th order
- •The theorem of existence and uniqueness of the solution for Linear de
- •Linear independent system of functions.
- •Wronskian.
- •Liouville's formula
- •Structure of the General Solution
- •Reduction of order
- •Characteristic equation. The roots of the Characteristic Equation are Real and Multiple, Complex and Distinct, Complex and Multiple.
- •Method of Variation of Parameters
- •Method of Undetermined Coefficients
- •Linear Homogeneous Systems of de with variable coefficients
- •26) Fundamental System of Solutions and Fundamental Matrix
- •27. Wronskian and Liouville’s Formula.
- •28. Method of Variation of Constants (Lagrange Method)
- •29. Linear nonhomogeneous systems of differential equations with constant coefficients.
Reduction of Order.
There are 3 main types of equations that allow the reduction of order. (1) the method for integrating the right side of equation Consider DE’s form as: y(n)=f(x). It is solved by successive integration the right side, and it will be integrate n times.
Ex:
y’’=x2-2x
(2)
DE explicitly missing the function y
Ex:
replace
y’’=z, y’’’=z’
thus, we’ve reduced the equation to the first order. Now share
variables and integrate:
Perform
inverse replacement: z=y’’
and it will be the general solution, where С1,2,3=const
(3)
In DE the independent variable x is missed:
Ex: (y-1)y’’=2(y’)2,
y(0)=2, y’(0)=2
Replace y’=z(y) and find the second
derivative: y’’=(z(y))’=z’(y)y’=z’z and replace the
original equation:
Carry out the inverse replacement:
y’=C1(y-1)2 and
use both the initial conditions: y(0)=2, y’(0)=2
2=
C1(2-1)2 и C1=2,
thus y’=2(y-1)2
and the continuous is simple:
using
initial conditions:
Linear homogeneous and non-homogeneous de of n-th order
(3)
– characteristic equation
Roots:
1) real&distinct
(RD)
,
,
,
2)complex&distinct
(CD)
,
,
,
,
3)real&multiple
(RM)
- order of equation
4)complex&multiple
compose the characteristic equation, and find its root:
,
,
Linear
Inhomogeneous DE of nth
order
with const coefficients
method of Undetermined coefficients
,
,
1)
α
– is not root of Ch. Eq.
Ly1=f1, Ly2=f2, Qk(x)eαx
2)
α
– root of CE, S – multiple
Qk+s(x) eαx
Inhomogeneous
DE
,
p=const,
,
1)
n=1, y’+p1y=f(x)
z-solution
of homogeneous DE
y=C(x)z, y’=C’(x)z+C(x)z’
C’(x)z+C(x)z’+
p1 C(x)z=f(x)
C’(x)z+C(x)[ z’+ p1z]=f(x)
C’(x)z=f(x)
2)
n=2, y’’+p1y’+p2y=f(x), z1,z1
– solution of HDE
{
z1,…,zn
– FSS, y=c1z1+…+cnzn
Pn-1→ y=c1z1+…+cnzn
The theorem of existence and uniqueness of the solution for Linear de
(1)
1. (2)
2. ; on R
Lipschutz’ solution.
Successful approximation.
solution of (existence)
Uniqueness of solution.
Systems of DE of first order
Linear independent system of functions.
Wronskian.
Definition:
System of functions y1(x),
y2(x)
is called linear independent system of functions on (a,b) if there
don’t exist such
if
if
it’s determinant equals 0, it's linear dependent.
The Wronskian Theorems
Suppose
that
is an n-th order linear differential operators with continuous real valued coef-
ficients
on an interval I. Suppose that for j = 1, 2,... ,n,
t)
satisfies L,
= 0.
Definition. The wronskian of these n solutions is defined as the n × n determinant,
W(t):=
Definition.
Theo lutions are linearly dependent when there are constants
not all zero so that
Otherwise
they are linearly independent.
General Wronskian Theorem. The following are equaivalent.
For some
For any values
there are uniquely determined constants
so that y =
is the solution of the initial value problem,
Ly
= 0, y(
)
=
,
y′(
)
=
,
…
(
)
=
.
Every solution of Ly = 0 is of the form for real constants . That is, is the general solution.
4. For all t ∈ I, W(t)
0.
The solutions y1,y2,... ,yn are linearly independent.
Example:
Show that the functions x, sin x, cos x are linearly independent.
Solution.
We find the Wronskian matrix W(x) for the system of functions:
Since the Wronskian is not identically zero, it follows that this system of functions is linearly independent.