Приложение 1 Задания для самостоятельной работы по теме «Построение и вычисление выражений»
Вычислить значение выражения при заданных значениях аргументов X (Y)
№ |
Начальное значение |
Выражение |
|
|
X1 = 0,5 X2 = –1,33 X3 = –7,5 |
Y= |
|
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X1 = -1,789 X2 = 3,06 X3 = 4 |
Y
=
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|
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X1 = -0,514 X2 = 0,9 X3 = 2,34 |
Y
=
|
|
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X1 = –3,8 X2 = 0,5 X3 = 4,7071 |
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|
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X1 = –1,84 X2 = 0,651 X3 = 1 |
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X1 = –1 X2 = 0,917 X3 = 6,333 |
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|
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X1 = 2,362 X2 = –0,113 X3 = 1,6512 |
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X1 = -1,5341 X2 = 0,75 X3 = 3,623 |
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X1 = -1,35 X2 = 0,9 X3 = 1,1707 |
Y
=
|
|
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X1 = -1,285 X2 = 0,65 X3 = 6,161 |
Y
=
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X1 = 2,735 X2 = 1,305 X3 = –0,531 |
Y
=
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X1 = -2,1507 X2 = 0,156 X3 = 2,0369 |
Y
=
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|
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X1 = -2,131 X2 = 0,00943 X3 = 2,3918 |
Y
=
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|
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X1 = -2,763 X2 = 0,569 X3 = 4,4917 |
Y
=
|
|
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X1 = -0,196 X2 = 1,254 X3 = 3,759 |
Y
=
|
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X1 = -3,06 Y1 = –5 X2 = 0,77 Y2 = 0,88 X3 = 5,888 Y3 = 4,02 |
Z
=
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X1 = -30,5 Y1 = 5,07 X2 = 6,06 Y2 = 0,6607 X3 = 0,913 Y3 = -5,8 |
Z
=
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X1 = -1 Y1 = 15 X2 = 0 Y2 = 3,555 X3 = 2,57 Y3 = -3,501 |
Z
=
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X1 = -2,409 Y1 = -3,5 X2 = 0,516 Y2 = 0, 516 X3 = 1,7 Y3 = 5,808 |
Z
=
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X1 = -5,15 Y1 = –3,308 X2 = 0,535 Y2 = 0,5 X3 = 2,517 Y3 = 3,6 |
Z
=
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X1 = –2,507 Y1 = –20,09 X2 = 0,09 Y2 = 0,045 X3 = 1,58 Y3 = 1,11 |
Z= |
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X1 = –1,456 Y1 = –1,043 X2 = 0,99 Y2 = 0,4 X3 = 2,1 Y3 = 1,01 |
Z= |
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X1 = –5,031 Y1 = –3,33 X2 = 0,385 Y2 = 1,404 X3 = 3,177 Y3 = 2,38 |
Z= |
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X1 = –0,174 Y1 = –2,345 X2 = 0,241 Y2 = 0,1769 X3 = 5,31 Y3 = 3,009 |
Z
=
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X1 = –5,28 Y1 = 1,375 X2 = 2,115 Y2 = –3,1 X3 = 0,121 Y3 = 0,578 |
Z
=
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X1 = –1,125 Y1 = 0,363 X2 = 1,125 Y2 = –0,363 X3 = 3,042 Y3 = 0,151 |
Z
= |
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X1 = 2,22 Y1 = –11,34 X2 = 0,57 Y2 = 1,3589 X3 = –9,05 Y3 = 3,3805 |
Z= |
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X1 = –2,19 Y1 = 3,17 X2 = 0,53 Y2 = 0,53 X3 = 3,17 Y3 = –2,19 |
Z
= |
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X1 = 1,215 Y1 = –1,517 X2 = 0,833 Y2 = 0,0404 X3 = –2,027 Y3 = 4,5 |
Z= |
|
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X1 = -0,87 Y1 = 2,045 X2 = 1,566 Y2 = 0,031 X3 =0,125 Y3 = -1,51 |
Z
= |
