![](/user_photo/2706_HbeT2.jpg)
Задание 2.
Задана функция распределения F(x,y) двумерной случайной величины (X,Y).
1. Найти вероятность попадания случайной точки (X,Y) в прямоугольник D, заданный неравенствами axb, cyd.
2. Найти двумерную плотность распределения случайной величины (X,Y).
3. Найти вероятность P{(X,Y)D}, используя двумерную плотность распределения.
1. F(x,y) =
,
a =
,
b = 0, c
= –1, d
= 1.
2. F(x,y) =
,
a =
,
b = 0, c
= 0, d
=
.
3. F(x,y) =
,
a = –2, b = 2, c = –, d = 0.
4. F(x,y) =
,
a = –1, b = 0, c = – , d = 0.
5. F(x,y) =
,
a =
,
b =
,
c = 0, d
= +.
6. F(x,y) =
a = –1, b = 2, c = 0, d = 4.
7. F(x,y) =
a = 2,5, b = 5, c = 0, d = 1.
8. F(x,y) =
a = 2, b = 4, c = 1, d = 6.
9. F(x,y) =
a = 2,5, b = 4, c = 2, d = 6.
10. F(x,y) =
a = 1, b = 3, c = 0, d = +.
11.F(x,y)=
a = –, b = 2, c = 1, d =2,5.
12. F(x,y) =
a = 1,5, b = 3, c = 5, d = 6.
13. F(x,y) =
a = -1, b = 1, c = 1, d = 4.
14. F(x,y) =
a = –, b = 0,5, c = 6, d = 9.
15. F(x,y) =
a = –1, b = 2, c = 0, d = 1.
16. F(x,y) = F1(x).F2(y),
где F1(x)
=
F2(y)
=
a =
2, b = 3,
c = –2,
d = 1.
17. F(x,y) = F1(x).F2(y),
где F1(x)
=
F2(y)
=
a =
–1, b =
–0,5, c =
0, d =1,5.
18. F(x,y) = F1(x).F2(y),
где F1(x)
=
F2(y)
=
a =
–2, b =
0,5, c =
–0,5, d
= 1.
19. F(x,y) = F1(x).F2(y),
где F1(x)
=
F2(y)
=
a = 0,25,
b = 1,25,
c = –0,25,
d = 1,25.
20. F(x,y) = F1(x).F2(y),
где F1(x)
=
F2(y)
=
a =
0,5, b =
1,5, c =
0,5, d =
4,5.
21. F(x,y) =
a = 1, b = 2, c = 0, d = 2.
22. F(x,y) =
a = 0, b = 1, c = –2, d = 1.
23. F(x,y) =
a = –2, b = 1, c = 2, d = 4.
24. F(x,y) =
a = 1, b = 2, c = 0, d = +.
25. F(x,y) =
a = –, b = 1, c = 0, d = 2.
26. F(x,y) =
a = 0, b = 2, c = –1, d = 1.
27. F(x,y) =
a = 1, b = 2, c = 0, d = +.
28. F(x,y) =
a = –3, b
=
,
c = 1, d
= 3.
29. F(x,y) =
a = –2, b = 1, c = 1, d = .
30. F(x,y) =
a = –1, b
=
,
c = 0, d
= +.
Задание 3.
Двумерная случайная величина (X,Y), распределенная в области G, задана плотностью распределения p(x,y).
1. Найти значение параметра а.
2. Найти вероятность попадания случайной точки (X,Y) в заданную область D.
3. Найти плотности распределения p1(x) и p2(y) случайных величин X и Y и условные плотности распределения p1(xy) и p2(yx). Сделать вывод о том, являются ли данные случайные величины зависимыми.
4. Найти M(X), M(Y), D(X), D(Y), KXY.
1. p(x,y) = axy4, G = {(x,y): 0x2, 0y1};
D = {(x,y):
x1,
0y
}.
2. p(x,y) = ax2y, G = {(x,y): x1, 0y2};
D = {(x,y): x2, y1}.
3. p(x,y) = ax2y2, G = {(x,y): 0x2, y1};
D = {(x,y): –2x1,
0y
}.
4. p(x,y) = ax3y2, G = {(x,y): 0x1, –2y0};
D = {(x,y): x2, y1}.
5. p(x,y) = axy3, G = {(x,y): 0x3, 0y1};
D = {(x,y): x1, 0y }.
6. p(x,y) = axsiny, G = {(x,y): 0x2,
0y
};
D = {(x,y): 0x
,
0y
}.
7. p(x,y) = ay2cosx
, G = {(x,y): –
x
,
y1};
D = {(x,y): x , 0y2}.
8. p(x,y) = ax3cos
, G = {(x,y): 0x2,
yπ};
D = {(x,y): x1, – yπ}.
9. p(x,y) = ay2sin2x , G = {(x,y): 0x , y2};
D = {(x,y): x , –1y }.
10. p(x,y) = axsin
, G = {(x,y): 0x2,
0y3π};
D = {(x,y): 1x2, π y3π}.
11. p(x,y) = asinxsiny, G = {(x,y): 0x , 0y };
D = {(x,y): –
x
,
y
}.
12. p(x,y) = acosxsiny, G = {(x,y): x , 0yπ};
D = {(x,y): –
x0,
0y
}.
13. p(x,y) = asin
cosy,
G = {(x,y): 0xπ,
0y
};
D = {(x,y): 0x2π, 0y }.
14. p(x,y) = asin2xcos , G = {(x,y): 0x , 0yπ};
D = {(x,y): x , y }.
15. p(x,y) = asin cos , G = {(x,y): 0x π, y };
D = {(x,y): x , y }.
16. p(x,y) = a, G = {(x,y): 0x2, 0y2};
D = {(x,y): x0, y0, x+y2}.
17. p(x,y) = a, G = {(x,y): x1, 0y2};
D = {(x,y): 2xy}.
18. p(x,y) = a, G = {(x,y): 0x2, y1};
D = {(x,y): xy}.
19. p(x,y) = a, G = {(x,y): x0, y0, x+y2};
D = {(x,y): xy}.
20. p(x,y) = a, G = {(x,y): x2, y2};
D = {(x,y): xy}.
21. p(x,y) = a, G = {(x,y): x2+y21};
D = {(x,y): yx}.
22. p(x,y) = a, G = {(x,y): x2+y24};
D = {(x,y): x+y0}.
23. p(x,y) = a, G = {(x,y): y0, x2+y21};
D = {(x,y): x0}.
24. p(x,y) = a, G = {(x,y): x0, x2+y24};
D = {(x,y): x2+y21}.
25. p(x,y) = a, G = {(x,y): y0, x2+y29};
D = {(x,y): x2+y24}.
26. p(x,y) = ae–2x–y, G = {(x,y): x0, y0};
D = {(x,y): 0x2, y1}.
27. p(x,y) = ae–x–3y, G = {(x,y): x0, y0};
D = {(x,y): –1x2, 0y2}.
28. p(x,y) = ae–3x–2y, G = {(x,y): x0, y0};
D = {(x,y): x2, y1}.
29. p(x,y) = a.2–x–y, G = {(x,y): x0, y0};
D = {(x,y): –1x3, 0y2}.
30. p(x,y) = a.3–x–0,5y, G = {(x,y): x0, y0};
D = {(x,y): 0x2, –2y3}.