
Яблонский К3, К7, К1 вариант 27 / Д-3 вар 27 / Д3_27
.pdf
3 ( 27) |
http://www.termeh.ru |
,
, = 130 / . D ( = 40 )
.
: R = 400V, V – . !
. " , # #
( ). $# # ,
# D m # , #,
% # #.
.1
:
= 40 ,
= 130 / , R = 400V.
1. & D, # .
' # , ( .1).
2. ( ,
. . , ) : # ( ),
F ( ), #R ( ).
3. |
# : mx = P − F − R. |
||||||||||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
* F = 2cλ, λ = (λ + ) − # |
||||||||||||||||
, . . |
mx = P − 2 |
|
(λ + |
|
) − 400V |
mx = P − 2 λ |
− 2 |
|
− 400x. |
||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
# D |
F = P = 2cλ . |
(1) |
||||||||||||||
$ |
mx = −2 |
|
− 400x |
|
mx + 400x + 2cx = 0, |
|
|||||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(2) |
||
$## , |
x +10x + 6.5x = 0. |
|
|||||||||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
" # #(1) |
||||||||||||||||
|
p2 +10 p + 6.5 = 0, |
|
|
|
|
|
|
||||||||||
|
= −5 ± |
|
= −5 ± |
|
|
≈ −5 ± 4.3 |
|
p1 ≈ −9.3, |
|
p2 ≈ −0.7 . |
|||||||
p1,2 |
25 − 6.5 |
18.5 |
|
|
|||||||||||||
|
* % ) % #(2) |
x = C e−9.3t + C |
e−0.7t . |
(3) |
|||||||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
1 |
2 |
|
|
|
http://www.termeh.ru
4. " ## # 1 2 % #.
+t = 0 # B, x0 = -λ ,
, # V0 = 0.
( (1) , λ = |
|
P |
= mg = |
40 ×981 » 150.92 , x |
= -150.92 . |
|||||||
|
|
|||||||||||
|
|
|
|
|
|
|
2c |
2c |
2 ×130 |
|
0 |
|
( t = 0, |
x0 = -150.92, |
|
|
|
|
|||||||
|
x0 |
= V0 = 0. |
, (3) |
|
||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
x0 = C1 + C2 |
|
|
C1 = -C2 + x0 |
= -C2 -150.92; |
|
|
|
|||||
x = -9.3C1e |
−9.3t |
- 0.7C2e |
−0.7t |
|
0 = -9.3C1 - 0.7C2 |
|
C2 » -13.31 1. |
|||||
|
|
|
|
|
|
|
|
|
|
|
||
C2 = -13.31×(- 2 -150.92) 2 |
» -163.18; |
C1 = -150.92 - C2 = -150.92 +163.18 » 12.26 |
: x = 12.26e−9.3t -163.18e−0.7t .