Теоретическая механика задачи / V8-D16 / V8-D16 / d16 08

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" $ C

= 0,

: ϕ =

M

t 2 . (3)

2

3m R2

1

= -m1aC ,

(4)

'

RO + = 0,

(5)

RO - . " (4) (5) RO - m1aC = 0.

(6)

( %

% 1 1, % ϕ1 ,

t = t1 ( . .).

( aC

%: n − %

aCτ − %, n aCτ

aC = n + aCτ .

' (6) % . , n

aCτ

1 1 ( . .),

R − m a

Cx

= 0 R − (−m an ) = 0 R + m ω 2 R = 0

R = −m ω2 R;

Ox

1

Ox

1

C

Ox

1

Ox

1

R - m a

Cy

= 0 R - m aτ

= 0

R - m εR = 0

R = m εR.

Oy

1

Oy

1 C

Oy

1

Oy

1

'

R

= R2

+ R2

= m R ω 4 + ε 2 ;

O

Ox

Oy

1