Добавил:
Upload Опубликованный материал нарушает ваши авторские права? Сообщите нам.
Вуз: Предмет: Файл:

топология / Tom Dieck T. Algebraic topology (EMS, 2008)

.pdf
Скачиваний:
57
Добавлен:
16.04.2015
Размер:
2.72 Mб
Скачать

148 Chapter 6. Homotopy Groups

We use V1.F n/ D Sd m 1 and t .St / Š Z and obtain from (6.8.3) by induction

(6.8.4) Proposition. 2.n k/C1.Vk .Cn// Š Z, 4.n k/C3.Vk .Hn// Š Z.

 

The real case is more complicated. The result is

 

 

 

 

 

(6.8.5) Proposition.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

n k

.V

k

.Rn//

 

Z;

k D 1; or n k even ;

 

 

 

 

 

 

Š (Z=2;

k

 

2; n

 

k odd.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Proof. By (6.8.3) and induction it

n

 

 

 

 

 

D

2. Later we

 

 

 

 

 

 

suffices to consider the case k

 

compute the homology groups of V2.R /, and the theorem of Hurewicz will then give us the desired result.

Problems

1.The group O.n/ has two path components. The groups SO.n/, U.n/, SU.n/, and Sp.n/ are path connected.

2.In low dimensions we have some special situations, namely

U.1/ Š SO.2/ Š S1;

Spin.3/ Š SU.2/ Š Sp.1/ Š S3;

Z=2 ! SU.2/ ! SO.3/; a 2-fold covering,

SU.n/ ! U.n/ ! S1; a fibration.

Use these data in order to verify

1.SO.2//

Š 1.O.2// Š Z;

 

1.SO.3//

Š 1.SO.n// Š Z=2;

m 3;

1.U.1//

Š 1.U.n// Š Z;

n 1;

1.SU.n//

Š 1.Sp.n// Š 0;

n 1;

2.SU.n//

Š 2.U.n// Š 2.Sp.n// Š 0;

n 1;

2.SO.n//

Š 0;

n 3;

3.U.2//

Š 3.U.k// Š Z;

k 2;

3.SU.2//

Š 3.SU.k// Š Z;

k 2;

3.Sp.1//

Š 3.Sp.k// Š Z;

k 1;

3.SO.3//

Š Z:

 

6.9 Proof of the Excision Theorem

In this section we present an elementary proof of the excision theorem (6.4.1). The proof is due to D. Puppe [46]. We derive the excision theorem from a more

6.9. Proof of the Excision Theorem

149

conceptual reformulation (6.9.3). The reformulation is more satisfactory, because it is “symmetric” in Y1; Y2. In (6.4.1) we have a second conclusion with the roles of Y1 and Y2 interchanged.

We begin with a technical lemma used in the proof. A cube in Rn, n 1 will be a subset of the form

W D W .a; ı; L/ D fx 2 Rn j ai xi ai C ı for i 2 L; ai D xi for i … Lg

for a D .a1; : : : ; an/ 2 Rn, ı > 0, L f1; : : : ; ng. (L can be empty.) We set dim W D jLj. A face of W is a subset of the form

W 0 D fx 2 W j xi D ai

for i 2 L0; xj D aj C ı for j 2 L1g

for some L0 L; L1 L.

(W 0 can be empty.) Let @W denote the union

of all faces of W which are different from W . We use the following subsets of

W D W .a; ı; L/:

Kp.W /

x

W

xi < ai

 

ı

for at least p values i

L ;

D

˚

2

j

C

2

 

2

2

 

Gp.W / D

˚x

2 W

j xi > ai

C

ı

for at least p values i

2 L :

Here 1 p n. For p > dim W we let Kp.W / and Gp.W / be the empty set.

(6.9.1) Lemma. Let f W W ! Y and A Y be given. Suppose that for p dim W the inclusions

f 1.A/ \ W 0 Kp.W 0/ for all W 0 @W

hold. Then there exists a map g which is homotopic to f relative to @W such that

g 1.A/ Kp.W /. (Similarly for Gp in place of Kp.)

W

 

!

 

Proof. We can assume that

 

 

1

 

D

 

1

 

 

 

 

 

 

 

 

D

 

W

 

 

 

 

I n, n

 

1. We define h

 

I n

 

I n in the

following manner: Let x

.

4 ; : :n

 

4

/. For a ray y which begins in x we consider

 

 

 

 

 

: ;

 

its intersection P .y/ with @ 0;

1

 

 

and its intersection Q.y/ with @I n. Let h map

 

P .y/

 

 

 

 

 

 

2

 

 

 

 

 

 

 

 

 

 

 

the segment from

 

to

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

x to P .y/ affinely to the segment from x to Q.y/. Then h is homotopic relative to @I n to the identity. We set g D f h. Let z 2 I n and g.z/ 2 A. If zi < 12 for all i,

then z 2 Kn.I n/ Kp.I n/. Suppose now that for at least one i we have zi

21 ,

then h.z/ 2 @I n and hence h.z/ 2 W 0 for some face W 0

with dim W 0 D n 1.

Since also h.z/

2

1

2

Kp.W 0

1

1

 

f 1.A/, by assumption h.z/

 

/. Hence we have for at

least p coordinates 2 > h.z/i . By definition of h, we have h.z/i D 4

C t.zi 4 /

with t 1. We conclude that for at least p coordinates 21 > zi .

 

The next theorem is the basic technical result. In it we deform a map I n ! Y into a kind of normal form. We call it the preparation theorem. Let Y be the union

150 Chapter 6. Homotopy Groups

of open subspaces Y1; Y2 with non-empty intersection Y0. Let f W I n ! Y be given. By the Lebesgue lemma (2.6.4) there exists a subdivision of I n into cubes W such that either f .W / Y1 or f .W / Y2 for each cube. In this situation we claim:

(6.9.2) Theorem. Suppose .Y1; Y0/ is p-connected and .Y2; Y0/ is q-connected (p; q 0). Then there exists a homotopy ft of f with the following properties:

(1)If f .W / Yj , then ft .W / Yj .

(2)If f .W / Y0, then ft is constant on W .

(3)If f .W / Y1, then f1 1.Y1 X Y0/ \ W KpC1.W /.

(4)If f .W / Y2, then f1 1.Y2 X Y0/ \ W GqC1.W /.

Here W is any cube of the subdivision.

Proof. Let C k be the union of the cubes W with dim W k. We construct the homotopy inductively over C k I .

Let dim W D 0. If f .W / Y0 we use condition (2). If f .W / Y1; f .W / 6 Y2, there exists a path in Y1 from f .W / to a point in Y0, since .Y1; Y0/ is 0- connected. We use this path as our homotopy on W . Then (1) and (3) hold. Similarly if f .W / Y2; f .W / 6 Y1. Thus we have found a suitable homotopy on C 0. We extend this homotopy to the higher dimensional cubes by induction over the dimension; we use that @W W is a cofibration, and we take care of (1) and (2).

Suppose we have changed f by a homotopy such that (1) and (2) hold and (3),

(4) for cubes of dimension less than k. Call this map again f . Let dim W D k. If f .W / Y0, we can use (2) for our homotopy. Let f .W / Y1; f .W / 6 Y2. If dim W p, there exists a homotopy ftW W W ! Y1 relative to @W of f jW with f1W .W / Y0, since .Y1; Y0/ is p-connected. If dim W > p we use (6.9.1) in order to find a suitable homotopy of f jW . We treat the case f .W / Y2; f .W / 6 Y1 in a similar manner. Again we extend the homotopy to the higher dimensional cubes. This finishes the induction step.

Let us denote by F .Y1; Y; Y2/ the path space fw 2 Y I j w.0/ 2 Y1; w.1/ 2 Y2g. We have the subspace F .Y1; Y1; Y0/.

(6.9.3) Theorem. Under the hypothesis of the previous theorem the inclusion

F .Y1; Y1; Y0/ F .Y1; Y; Y2/ is .p C q 1/-connected.

Proof. Let a map ' W .In; @In/ ! .F .Y1; Y; Y2/; F .Y1; Y1; Y0// be given where n p C q 1. We have to deform this map of pairs into the subspace. By adjunction, a map of this type corresponds to a map ˆ W I n I ! Y with the following properties:

(1)ˆ.x; 0/ 2 Y1 for x 2 I n,

(2)ˆ.X; 1/ 2 Y2 for x 2 I n,

6.9. Proof of the Excision Theorem

151

(3) ˆ.y; t/ 2 Y1 for y 2 @I n and t 2 I .

Let us call maps of this type admissible. The claim of the theorem is equivalent to the statement, that ˆ can be deformed as an admissible map into a map with image in Y1. We apply the preparation theorem to ˆ and obtain a certain map .

The deformation in (6.9.2) stays inside admissible maps. Consider the projectionW I n I ! I n. We claim that the images of 1.Y X Y1/ and ˆ 1.Y X Y2/ under are disjoint. Let y 2 ‰ 1.Y X Y2/, y D .z/ and z 2 ‰ 1.Y X Y2/\ W for a cube W . Then z 2 KpC1.W / and hence y has at least p small coordinates. In

a similar manner we conclude from y 2 ‰ 1.Y X Y1/ that y has at least q large coordinates. In the case that n < p C q the point y cannot have p small and q large coordinates.

The set 1.Y X Y1/ is disjoint to @I n, since ‰.@I n/ I / A. There exists

n

W

I n

!

I which assumes the value 0 on 1.Y

X

 

 

a continuous function

 

 

 

Y1

/

and the value 1 on @I [ ‰.Y X Y2/. The homotopy

 

 

 

..x; t/; s/ 7!‰.x; .1 s/t C st .x//

 

 

 

is a homotopy of admissible maps from to a map with image in Y1.

 

 

(6.9.4) Theorem. Under the hypothesis of (6.9.2) the inclusion induces an isomorphism j .Y1; Y0/ ! j .Y; Y2/ for j < p C q and an epimorphism for j D p C q.

Proof. We have the path fibration F .Y; Y; Y2/ ! Y , w 7!w.0/. The pullback along Y1 Y yields the fibration F .Y1; Y; Y2/ ! Y1, w 7!w.0/. The fibre over

is F . ; Y; Y2/. We obtain a commutative diagram of fibrations:

F . ; Y1; Y0/

 

ˇ

 

F . ; Y; Y2/

 

 

 

 

 

 

 

 

 

 

 

 

 

˛

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

F .Y1; Y1; Y0/

 

D

 

F .Y1

; Y; Y2

/

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

A

 

 

 

 

 

 

A.

 

 

 

 

 

 

 

 

The inclusion ˛ is .p C q 1/-connected (see (6.9.3)). Hence ˇ has the same connectivity (see (6.7.8)), i.e., the inclusion .Y1; Y0/ .Y; Y2/,

n.F . ; Y1; Y0//

 

n.F . ; Y; Y2//

 

 

 

 

 

Š

 

 

 

Š

 

 

 

 

 

 

 

 

 

 

 

 

 

nC1.Y1; Y0; /

 

nC1.Y; Y2; /

 

 

 

 

induces an isomorphism for n < p C q 1 and an epimorphism for n D p C q 1.

152 Chapter 6. Homotopy Groups

Problems

1. The hypothesis of (6.4.1) is a little different from the hypothesis of (6.9.4), since we did not assume in (6.4.1) that .Y1; Y0/ and .Y2; Y0/ are 0-connected. Let Y 0 be the subset of points that can be connected by a path to Y0. Show that Y 0 has the open cover Y10 ; Y20 and the inclusion induces isomorphisms .Y10 ; Y0/ Š .Y1; Y0/ and .Y; Y2/ Š .Y 0; Y20 /. This reduces (6.4.1) to (6.9.4).

2.

The map Y0 ! F .Y1; Y1; Y0/ which sends y 2 Y0 to the constant path with value y is

an h-equivalence.

 

 

 

 

3.

The map a1 W F .Y; Y; Y1/ ! Y , w 7!w.0/ replaces the inclusion Y1 ! Y by a fibration.

There is a pullback diagram

 

 

 

 

 

F .Y1; Y; Y2/

 

F .Y; Y; Y1/

 

 

 

 

 

 

 

 

 

 

 

 

 

a1

 

 

 

 

 

 

 

 

 

 

a2

 

 

 

 

 

 

 

 

 

 

F .Y; Y; Y2/

 

 

Y .

 

 

 

 

 

 

 

Thus (6.9.3) compares the pushout Y of Y1

Y0 ! Y2 and the pullback of a1; a2 with

Y0. For generalizations see [73].

 

 

 

 

4.

Show that the proof of (6.4.2) along the lines of this section does not need (6.9.1).

6.10 Further Applications of Excision

The excision theorem is a fundamental result in homotopy theory. For its applications it is useful to verify that it holds under different hypotheses. In the next proposition we show and use that Y is the homotopy pushout.

(6.10.1) Proposition. Let a pushout diagram be given with a cofibration j ,

f

AB

jJ

F

 

X

Y .

 

 

 

Suppose i .X; A; a/ D 0 for 0 < i < p and each a 2 A, and i .f; a/ D 0 for

0 < i < q and each a 2 A. Then the map .F; f / W n.X; A; a/ ! n.Y; B; f .a// is surjective for 1 n p C q 2 and bijective for 1 n < p C q 2.

Proof. We modify the spaces up to h-equivalence such that (6.4.1) can be applied. Let Z.f / D B[f A Œ0; 1 D BCA Œ0; 1 =f .a/ .a; 0/ be the mapping cylinder of f with inclusion k W A ! Z.f /, a 7!.a; 1/ and projection p W Z.f / ! B a homotopy equivalence. We form the pushout diagrams

 

 

 

k

 

p

 

A

 

 

Z.f /

 

B

 

j

 

 

 

 

L

 

 

 

J

 

 

K

 

 

 

 

P

 

 

 

 

 

 

X

 

 

Z

 

Y

 

 

 

 

 

 

 

 

 

6.10. Further Applications of Excision

153

with pk D f and PK D F . Then P is a homotopy equivalence by (5.1.10) and .P; p/ induces an isomorphism of homotopy groups. Therefore it suffices to analyze .K; k/ . The space Z can be constructed as

Z D B [f A Œ0; 1 [ X D Z.f / C X=.a; 1/ a:

The map .K; k/ is the composition of

.X; A; a/ ! .A 0; 1 [ X; A 0; 1 ; .a; 1//; x 7!.x; 1/

with the inclusion into .Z; Z.f /; .a; 1//. The first map induces an isomorphism of homotopy groups, by homotopy equivalence. In order to exhibit n. / as an isomorphism, we can pass to the base point .a; 1=2/, by naturality of transport. With this base point we have a commutative diagram

n.A 0; 1 [ X; A 0; 1 /

 

 

n.Z; Z.f //

 

 

 

 

 

 

 

 

 

 

 

 

 

Œ0; 1Œ/.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

n.A 0; 1 [ X; A 0; 1Œ/

 

n.Z; B [ A

The vertical maps are isomorphism, by homotopy invariance. We apply (6.4.1) to the bottom map. Note that i .A 0; 1 [ X; A 0; 1 / Š i .X; A/ and

i .B [ A Œ0; 1Œ; A 0; 1Œ/ Š i .Z.f /; A/;

 

again by homotopy invariance.

 

(6.10.2) Theorem (Quotient Theorem). Let A X be a cofibration. Let further p W .X; A/ ! .X=A; / be the map which collapses A to a point. Suppose that for each base point a 2 A,

i .CA; A; a/ D 0 for 0 < i < m; i .X; A; a/ D 0 for 0 < i < n:

Then p W i .X; A; a/ ! i .X=A; / is bijective for 0 < i < m C n 2 and surjective for i D n C m 2.

Proof. By pushout excision, i .X; A/ ! i .X [ CA; CA/ is bijective (surjective) in the indicated range. Note that @ W i .CA; A; a/ Š i 1.A; a/, so that the first hypothesis is a property of A. The inclusion CA X[CA is an induced cofibration. Since CA is contractible, the projection p W X [ CA ! X [ CA=CA Š X=A is a

homotopy equivalence.

 

(6.10.3) Corollary. Let A X be a cofibration.

Assume that i .A/ D 0 for

0 i m 1 and i .X/ D 0 for 0 i m 2. Then i .X; A/ ! i .X=A/

154 Chapter 6. Homotopy Groups

is an isomorphism for 0 < i 2m 1. We use this isomorphism in the exact sequence of the pair .X; A/ and obtain an exact sequence

2m 1.A/ ! 2m 1.X/ ! 2m 1.X=A/ ! 2m 2.A/ ! ! mC1.X/ ! mC1.X=A/ ! m.A/ ! 0:

A similar exact sequence exists for an arbitrary pointed map f W AX where a typical

f

f1

 

portion comes from the cofibre sequence i .A/ ! i .X/ ! i .C.f //.

We now generalize the suspension theorem. Let .X; / be a pointed space. Recall the suspension †X and the homomorphism † W n.X/ ! nC1.†X/.

(6.10.4) Theorem. Let X be a well-pointed space. Suppose i .X/ D 0 for 0 i n. Then † W j .X/ ! j C1.†X/ is bijective for 0 j 2n and surjective for j D 2n C 1.

Proof. Let CX D X I=.X 1[f g I / be the cone on X. We have an embedding i W X ! CX, x 7!Œx; 0 which we consider as an inclusion. The quotient CX=X can be identified with †X. From the assumption that f g X is a cofibration one concludes that i is a cofibration (Problem 1). Since CX is contractible, the exact

sequence of the pair .CX; X/ yields an isomorphism @

W

 

 

.CX; X/

'

.X/.

 

 

 

 

j C1

 

n

 

j

The inverse isomorphism sends an element represented by f W I

 

! X to the

element represented by f id.I /. From this fact we see

 

 

 

 

 

 

† D p ı @ 1 W j .X/

@

j C1.CX; X/

 

 

p

j C1.†X/;

 

 

 

 

 

with the quotient map p W CX ! CX=X D †X. We can therefore prove the theorem by showing that p is bijective or surjective in the same range. This follows from the quotient theorem (6.10.2).

(6.10.5) Theorem. Let X and Y be well-pointed spaces. Assume i .X/ D 0 for i < p . 2/ and i .Y / D 0 for i < q . 2/. Then the inclusion X _ Y ! X Y induces an isomorphism of the i -groups for i p C q 2. The groups

i .X Y; X _ Y / and i .X ^ Y / are zero for i p C q 1.

Proof. We first observe that j W i .X _ Y / ! i .X Y /, induced by the inclu-

sion, is always surjective. The projections onto the factors induce isomorphisms k W i .X Y / Š i .X/ i .Y /. Let j X W X ! X _ Y and j Y W Y ! X _ Y denote the inclusions. Let

s W i .X/ i .Y / ! i .X _ Y /; .x; y/ 7!j X .x/ C j Y .y/:

Then sk is right inverse to j . Hence the exact sequence of the pair .X Y; X _ Y / yields an exact sequence

. / 0 ! iC1.X Y; X _ Y / ! i .X _ Y / ! i .X Y / ! 0:

6.10. Further Applications of Excision

155

In the case that i 2, the sequence splits, since we are then working with abelian groups; hence

i .X _ Y / Š i .X/ ˚ i .Y / ˚ iC1.X Y; X _ Y /; i 2:

Since the spaces are well-pointed, we can apply the theorem of Seifert–van Kampen to .X _ Y; X; Y / and see that 1.X _ Y / D 0. We now consider the diagram

i .X _ Y; Y /

.1/

i .X/

 

i .X _ Y /

 

i .X _ Y; X/

 

 

 

 

 

.2/

i .Y /

with exact row and column. The diagonal arrows are always injective and split; this is seen by composing with the projections.

Since the spaces are well-pointed, we can apply the pushout excision to the triad

.X _ Y; X; Y; /. It says that (1) and (2) are surjective for i p C q 2, and hence bijective (since we already know the injectivity).

We now apply the Sum Lemma (11.1.2) to the diagram and conclude that h j X ; j Y i is an isomorphism, and therefore also the map of the theorem is an isomorphism. The exact sequence now yields i .X Y; X _Y / D 0 for i p Cq 1.

We apply (6.10.2) to i .X Y; X _ Y / ! i .X ^ Y /. By what we have already proved, we can apply this theorem with the data n D p C q 1 and m D min.p 1; q 1/. We also need that X _ Y ! X Y is a cofibration. This

is a consequence of the product theorem for cofibrations.

 

(6.10.6) Proposition.

Let .Yj j

j

2

J / be the family of path components of Y and

 

j

 

 

 

 

c

 

W Yj ! Y the inclusion. Then

 

 

 

h cj i W Lj J k .YjC ^ Sn/ ! k .Y C ^ Sn/

2

is an isomorphism for k n.

Proof. Suppose Y is the topological sum of its path components. Then we have a homeomorphism Y C ^ Sn Š Wj 2J YjC ^ Sn, and the assertion follows for finite J by induction on the cardinality of J from (6.10.5) and for general J then by a compactness argument. For general Y it suffices to find a 1-connected map

X! Y such that X is the topological sum of its path components, because then

XC ^ Sn ! Y C ^ Sn is .n C 1/-connected by (6.7.10) (and similarly for the path

components).

 

156 Chapter 6. Homotopy Groups

(6.10.7) Proposition. Let Y be k-connected .k 0/ and Z be l-connected

.l 1/ and well-pointed. Then the natural maps

j .Z/ ! j .Y Z; Y / ! j .Y Z=Y / ! j .Z/

are isomorphisms for 0 < j k C l C 1.

Proof. The first map is always bijective for j 1; this is a consequence of the exact sequence of the pair .Y Z; Y / and the isomorphism j .Y / j .Z/ Šj .Y Z/. Since the composition of the maps is the identity, we see that the second map is always injective and the third one surjective. Thus if p W j .Y Z; Y / !j .Y Z=Y is surjective, then all maps are bijective. From our assumption about Z we conclude that j .Y Z; Y / D 0 for 0 < j l (thus there is no condition for l D 0; 1). The quotient theorem now tells us that p is surjective

for 0 < j k C l C 1.

 

(6.10.8) Corollary. Let Y be path connected. The natural maps

 

k .Sn/ ! k .Y Sn; Sn/ ! k .Y Sn= Sn/ ! k .Sn/

 

are isomorphisms for 1 k n.

 

(6.10.9) Proposition. Suppose i .X/ D 0 for i < p . 0/ and i .Y / D 0 for i < q . 0/. Then i .X ? Y / D 0 for i < p C q C 1.

Proof. In the case that p D 0 there is no condition on X. From the definition of the join we see that X ? Y is always path connected. For p D 0 we claim thati .X ? Y / D 0 for i < q C 1. Consider the diagram

X

pr

X Y

pr

 

 

 

Y

 

 

 

 

pr

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

X

 

X

 

f g

 

 

 

 

 

 

 

 

and apply (6.7.9). In the general case the excision theorem says that the map

i .CX Y; X Y / ! i .X ? Y; X C Y / is an epimorphism for i < p C q C 1. Now use diagram chasing in the diagram

i .X

 

 

 

 

 

 

 

 

C Y /

 

i

 

1.X

 

C Y /

 

C Y /

 

 

i .X ? Y /

 

i .X ? Y; X

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

i .X Y /

 

i .CX Y /

 

i .CX Y; X Y /

 

 

i 1.X Y /

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(a morphism between exact homotopy sequences).

 

 

 

 

 

 

 

6.10. Further Applications of Excision

157

The excision theorem in the formulation of (6.9.4) has a dual. Suppose given a pullback diagram

E F X

Gf

Y g B

with fibrations f and g. as the fibrewise join of f

The double mapping cylinder Z.F; G/ can be considered and g. It has a canonical map W Z.F; G/ ! B.

(6.10.10) Proposition. Suppose f is p-connected and g is q-connected. Then is p C q C 1-connected.

Proof. Use fibre sequences and (6.10.9).

 

Problems

1.Let 0.X/ D 0 and i .Y / D 0 for i < q. 2/. Then i .X/ ! i .X _ Y / is an isomorphism for i < q. Show also 2.X Y; X _ Y / D 0.

2.Let X and Y be 0-connected and well-pointed. Show 1.X ^ Y / D 0.

3.Show that 3.D2; S1/ ! 3.D2=S1/ is not surjective.

4.Show 1.S2 _S1; S1/ D 0. Show that 2.S2 _S1; S1/ ! 2.S2 _S1=S1/ Š 2.S2/

is surjective but not injective.

5.For X D Y D S1 and i D 1 the sequence . / does not split. The fundamental group1.S1 _ S1/ D Z Z has no subgroup isomorphic to Z ˚ Z.

6.Show that the diagram

X @I [ f g I

p

 

 

X

 

 

 

 

 

 

 

 

 

 

 

i

 

\

 

 

 

 

 

 

 

 

 

 

X I

 

CX

 

 

 

 

 

with p.x; 0/ D x; p.x; 1/ D ; p. ; t/ D is a pushout.

7.If X is well-pointed, then †X is well-pointed.

8.Some hypothesis like e.g. well-pointed is necessary in both (6.10.1) and (6.10.4). Let

A D f0g [ fn 1 j n 2 Zg and A D A 0 X D A I=A 1 with base point .0; 0/.

Then 1.†X/ and 1.A/ are uncountable; † W 0.X/ ! 1.†X/ is not surjective. Note: A X is a cofibration and X=A is well-pointed.

9. Let e1; : : : ; enC1 be the standard basis of unit vectors in RnC1, and let e1 be the base point of Sn. A pointed homeomorphism hn W †Sn Š SnC1 is

hn W †Sn ! SnC1; .x; t/ 7!12 .e1 C x/ C 12 cos 2 t .e1 x/ C 12 je1 xj sin 2 t enC2 where RnC1 D RnC1 0 RnC2.

10. Let K RnC1 be compact. Show that each map f W K ! Sn has an extension to the complement RnC1 X E of a finite set E. One can choose E such that each component of RnC1 X K contains at most one point of E.

Соседние файлы в папке топология