
топология / Tom Dieck T. Algebraic topology (EMS, 2008)
.pdf138 Chapter 6. Homotopy Groups
(6) Let vi W W n ! R, 1 i n be functions such that vi .x/ < 0 for x 2 Ci . / and vi .x/ > 0 for x 2 Ci .C/. Then there exists x 2 W n such that vi .x/ D 0 for each i (Intermediate Value Theorem).
(7) Suppose Bi separates Ci . / and Ci .C/ for 1 i n. Then the intersection B1 \ B2 \ \ Bn is non-empty.
(8) Let B0; : : : ; Bn be a closed covering of n such that ei … Bi and @i n Bi .
Then TnD Bi D6 ;. The same conclusion holds if we assume that the Bi are
i 0
open.
(9) Let B |
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be a closed covering of n such that e |
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and @ |
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;. Then |
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iD0 Bi D6 ;. |
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The fixed |
point theorem expresses a topological property of Dn |
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is a homeomorphism and f |
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X a self-map, then hf h 1 has a fixed point z |
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and therefore f has the fixed point h.z/. We can apply (2) to the pairs .W |
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; @W |
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and . n; @ n/, since they are homeomorphic to .Dn; Sn 1/. Statement (3) is also equivalent to the inclusion Sn 1 Rn X f0g not being null homotopic (similarly for @W n in place of Sn 1).
Proof. .1/ ) .2/. Suppose r is a retraction. Then x 7! r.x/ is a map without fixed point.
.2/ ) .3/. The map r W Dn ! Sn 1 which corresponds by (2.3.4) to a null homotopy of the identity is a retraction.
.3/ ) .1/. Suppose b has no fixed point. Then
Sn 1 |
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Sn 1 |
; .x; t/ |
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x tb.x/ |
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N.x |
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tb.x// |
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7!kx tb.x/k |
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is a homotopy from the identity to the map f W x 7! N.x b.x//. |
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Since |
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has no fixed point, the formula for f defines a map on the whole of D , and then .x; t/ 7!f .tx/ is a homotopy from the constant map to f . Thus f is null homotopic, and therefore also id.Sn 1/.
.2/ ) .4/. If x is contained in the interior of Dn, then there exists a retraction r W Rn X x ! Sn 1 of Sn 1 Rn X x. If x is not contained in the image of f ,
then r |
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Sn 1 contradicts the retraction theorem. |
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.4/ ) .5/. Define a map f W D |
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! R by |
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f .x/ D 2x g.2x/; |
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kxk 1=2; |
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(ii) |
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f .x/ D kxk 1x 2 1 kxk g kxk 1x ; |
kxk 1=2: |
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For kxk D |
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we obtain in both cases 2x g.2x/. Thus f is a well-defined |
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continuous map. |
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1 we have f .x/ |
x. By (4), there exists |
y with f .y/ |
0. If |
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kyk |
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, then (i) shows that 2y is a fixed point. If kyk > |
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2 , then kyk 6D1, and |
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(ii) shows the second case with |
D .2 2kyk/ 1 > 1. |
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6.6. The Brouwer Fixed Point Theorem |
139 |
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.5/ ) .1/. A specialn |
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case. |
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.x/; : : : ; v |
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.x//. Suppose v.x/ |
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.6/. Set v |
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each x 2 W |
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X 0. Consider h W .t; x/ 7!.1 t/x C tv.x/. |
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If x |
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ni . /, |
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< 0, then .1 |
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.x/ < 0 for each t |
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i.e., x |
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t/x |
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0 is a homotopy from the inclusion to v. Since v has an extension |
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@W |
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to W , it is null homotopic, but the inclusion is not null homotopic. A contradiction.
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.6/ ) .7/. Let d denote the Euclidean distance. Define vi W W ! R by |
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v |
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d.x; Bi /; |
x 2 Bi . /; |
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D (d.x; Bi /; |
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and apply (6). |
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Let r W W n |
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We define Bi .˙/ D |
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r 1.˙xi |
> 0/ and Bi |
D r 1.xi D 0/. We apply (7) and obtain a contradic- |
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tion. |
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.3/ ) .8/. We use the functions vi .x/ Dn |
d.x; Bi /. Our assumptions imply |
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vi .ei / > 0, and vi .x/ D 0 provided x 2 @i . If thenBi have empty intersection, |
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then v.x/ D .v0.x/; : : : ; vn.x// 6D0 for every x 2 |
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˛ |
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@ n; x |
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1v.x/; |
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because, since the Bi |
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cover , for each x at least one coordinate vi .x/ is zero. If |
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tv.x/ |
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n for each t |
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Œ0; 1 . |
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The identity of @ |
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is therefore homotopic to ˇ D |
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ˇ has the |
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˛j@ n |
/ is null homotopic. |
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extension ˛ it is null homotopic, and therefore also id.@ |
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This contradicts (3). |
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Now suppose the Bi are open. By a general result of point-set topology there |
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exist closed sets C |
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and the Ci still form a covering. In order to |
make sure |
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that the Ci satisfy the hypotheses of (8) we can replace the Ci by Ci [ |
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first part of the proof now shows that the Ci have non-empty intersection. |
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Set U |
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D X Bi . Suppose the Bi |
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.8/ ) .9/. n |
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the Ui cover |
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are a covering, the Ui |
have empty intersection. By |
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construction, ei |
… Ui |
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and @i n Ui . |
We therefore can apply (8) in the case |
of the open covering by the Ui and see that the Ui have non-empty intersection. Contradiction.
.9/ ) .2/. Let Aj |
D f.t0; : : : ; tn/ 2 @ n j tj 1=ng. Let r W n ! @ n be |
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a retraction and set Bj |
D r 1.Aj /. Then (9) tells us that the Bj |
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intersection, and this is impossible. |
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Theorem (6.6.1) has many different proofs. For a proof which uses only basic results in differential topology see [79]. Another interesting proof is based on a combinatorial result, called Sperner’s Lemma [173].
140 Chapter 6. Homotopy Groups
The retraction theorem does not hold for infinite-dimensional spaces. In [70, Chapter 19] you can find a proof that the unit disk of an infinite-dimensional Banach space admits a retraction onto its unit sphere.
Does there exist a sensible topological notion of dimension for suitable classes of spaces? Greatest generality is not necessary at this point. As an example we introduce the covering dimension of compact metric spaces X. (For dimension
theory in general see [94].) Let C be a finite covering of X and " > 0 a real number. We call C an "-covering, if each member of C has diameter less than ". We say C has order m, if at least one point is contained in m members but no point in mC1. The compact metric space X has covering dimension dim X D k, if there
exists for each " > 0 a finite closed "-covering of X of order k C 1 and k 2 N0 is minimal with this property. Thus X is zero-dimensional in this sense, if there exists for each " > 0 a finite partition of X into closed sets of diameter at most ". We verify that this notion of dimension is a topological property.
(6.6.2) Proposition. Let X and Y be homeomorphic compact metric spaces. If X is k-dimensional then also is Y .
Proof. Let h W X ! Y be a homeomorphism. Fix " > 0 and let U be the covering of Y by the open "-balls U".y/ D fx j d.x; y/ < "g. (We use d for the metrics.) Let
ıbe a Lebesgue number of the covering .h 1.U / j U 2 U/. Since dim X D k, there exists a finite closed ı-covering C of X of order k C 1. The finite closed
covering D D .h.C / j C 2 C/ of Y has then the order k C 1, and since each member of C is contained in a set h 1.U /, the covering D is an "-covering. Thus we have shown dim Y k.
We now show that dim Y k, i.e., there exists ı > 0 such that each finite closed ı-covering has order at least k C 1. Let " > 0 be a corresponding number for X. A homeomorphism g W Y ! X is uniformly continuous: There exists a ı > 0 such
that d.y1; y2/ < ı implies d.g.y1/; g.y2// < ". So if C is a ı-covering of Y , then D D .g.C / j C 2 C/ is an "-covering of X. Since D has order at least k C 1, so
has C. |
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(6.6.3) Proposition. There exists " > 0 such that each finite closed "-covering
.Bj j j 2 J / of n has order at least n C 1.
Proof. Let " be a Lebesgue number of the covering Ui D n X @i n, i D 0; : : : ; n.
Hence for each j 2 J there exist i such that Bj Ui , and the latter is equivalent to Bj \ @i n D ;. Suppose ek 2 Bj . Since ek 2 @i n for i 6Dk, we cannot have Bj Ui ; thus ek 2 Bj implies Bj Uk . Since each ek is contained in at
least one of the sets Bj we conclude jJ j n C 1. For each j 2 J we now choose g.j / 2 f0; : : : ; ng such that Bj \ @g.j / n D ; and set Ak D [fBj j g.j / D kg; this is a closed set because J is finite. Each Bj is contained in some Ak , hence
the Ak cover n. Moreover, by construction, Ak \ @k n D ;. We can therefore apply part (9) of (6.6.1) and find an x in the intersection of the Ak . Hence for each

6.7. Higher Connectivity |
141 |
k there exists ik such that x 2 Bik . Since each Bj the sets Ak , the element x is contained in the n C 1 the covering.
is contained in exactly one of
members Bik , k D 0; : : : ; n of
We can now compare the covering dimension and the algebraic dimension.
(6.6.4) Theorem. n has covering dimension n. A compact subset of Rn has covering dimension at most n.
Proof. By (6.6.3), n has covering dimension at least n. It remains to construct finite closed "-coverings of order n C 1 for each ". See Problem 4.
Problems
1. Let U; V be an open covering of I 2. Then there exists either a path u W I ! U such that
u.0/ 2 I 0; u.1/ 2 I 1 or a path v2W I ! V such that v.0/ 2 0 I; v.1/ 2 1 I . |
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2. Let |
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D6 ; for each i or a path component of V with a similar property. |
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that Q |
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3.Generalize the preceding two exercises to n dimensions.
4.The following figure indicates the construction of closed "-coverings of order 3 for the square.
Generalize this construction to the cube I n by a suitable induction.
5. Suppose I n is the union of a finite number of closed sets, none of which contains points of two opposite faces. Then at least n C 1 of these closed sets have a common point.
6.7 Higher Connectivity
For many applications it is important to know that the homotopy groups of a space vanish in a certain range. We discuss several reformulations of this fact. In the
following 0.X; x/ D 0.X/ with base point Œx . The space D0 is a singleton and
S 1 D ;.
(6.7.1) Proposition. Let n 0. The following are equivalent:
(1)n.X; x/ D 0 for each x 2 X.
(2)Each map Sn ! X has an extension to DnC1.
(3)Each map @I nC1 ! X has an extension to I nC1.
142 Chapter 6. Homotopy Groups
Proof. The case n D 0 is trivial. The equivalence of (2) and (3) is a consequence of the homeomorphism .DnC1; Sn/ Š .I nC1; @I nC1/. Suppose f W Sn ! X is given. Use e1 D .1; 0; : : : / 2 Sn as a base point and think of f representing an element in n.X; x/. If (1) holds, then f is pointed null homotopic. A null homotopy Sn I ! X factors over the quotient map Sn I ! DnC1, .x; t/ 7!
.1 t/e1 C tx and yields an extension of f . Conversely, let an element ˛ ofn.X; x/ be represented by a pointed map f W .Sn; e1/ ! .X; x/. If this map has an extension F to DnC1, then .F; f / represents ˇ 2 nC1.X; X; x/ D 0 with
@ˇ D ˛.
(6.7.2) Proposition. Let n 0. Let f W .Dn; Sn 1/ ! .X; A/ be homotopic as
a map of pairs to a map k |
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.A; A/. Then f |
is relative to Sn 1 |
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homotopic to a map g such that g.D |
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Proof. The case n |
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from f to k according to the assumption. Define |
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.x; t/ D .2˛.x; t/ 1 x; 2 ˛.x; t// with the function ˛.x; t/ D max.2kxk; 2 t/. Then H D G ı is a homotopy with the desired property from f to g D H1.
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(6.7.3) Proposition. Let n 1. The following assertions about .X; A/ are equivalent:
(1) n.X; A; / D 0 for each choice of 2 A.
(2)Each map f W .I n; @I n/ ! .X; A/ is as a map of pairs homotopic to a constant map.
(3)Each map f W .I n; @I n/ ! .X; A/ is homotopic rel @I n to a map into A.
Proof. (1) ) (2). Let f W .I n; @I n/ ! .X; A/ be given. Since J n 1 is contractible, there exists a homotopy of the restriction f W J n 1 ! A to a constant map. Since
J n 1 @I n and @I n I n are cofibrations, f is as a map of pairs homotopic to g W .I n; @I n/ ! .X; A/ such that g.J n 1/ D fa0g. Since n.X; A; a0/ D 0, the
map g W .I n; @I n; J n 1/ ! .X; A; a0/ is null homotopic as a map of triples.
(2) ) (3). (6.7.2). |
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(3) ) (1). Let f W .I n; @I n; J n 1/ ! .X; A; / be given. |
By assump- |
tion (3) Œf is contained in the image of n.A; A; / ! .X; A; |
/. Now use |
n.A; A; / D 0. |
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6.7. Higher Connectivity |
143 |
We call .X; A/ n-compressible if one of the assertions in (6.7.3) holds. More generally, we call a map f W X ! Y n-compressible if the following holds: For each commutative diagram
'
@I n X
\f
I n ˆ Y
there exists ‰ W I n ! X such that ‰j@I n D ' and f ‰ ' ˆ relative to @I n. (This amounts to part (3) in (6.7.3).) This notion is homotopy invariant in the following sense:
(6.7.4) Proposition. Given f W X ! Y and a homotopy equivalence p W Y ! Z. Then f is n-compressible if and only pf is n-compressible.
(6.7.5) Proposition. Let n 0. The following assertions about .X; A/ are equivalent:
(1)Each map f W .I q ; @I q / ! .X; A/, q 2 f0; : : : ; ng is relative to @I q homotopic to a map into A.
(2) The inclusion j W A ! X induces for each base point a 2 A a bijection j W q .A; a/ ! q .X; a/ for q < n and a surjection for q D n.
(3)0.A/ ! 0.X/ is surjective, and q .X; A; a/ D 0 for q 2 f1; : : : ; ng and each a 2 A.
Proof. (1) , (3). The surjectivity of 0.A/ ! 0.X/ is equivalent to (1) for q D 0. The other cases follow from (6.7.3).
(2) , (3). This follows from the exact sequence (6.1.2).
A pair .X; A/ is called n-connected if (1)–(3) in (6.7.5) hold. We call .X; A/ 1-connected if the pair is n-connected for each n. A pair is 1-connected if and
only if j W n.A; a/ ! n.X; a/ is always bijective. If X 6D ;but A D ; we say that .X; A/ is . 1/-connected, and .;; ;/ is 1-connected.
(6.7.6) Proposition. Let n 0. The following assertions about X are equivalent:
(1)q .X; x/ D 0 for 0 q n and x 2 X.
(2)The pair .CX; X/ is .n C 1/-connected.
(3)Each map f W @I q ! X, 0 q n C 1 has an extension to I q .
Proof. The cone CX is contractible. Therefore @ W qC1.CX; X; / Š q .X; /. This and (6.7.5) shows the equivalence of (1) and (2). The equivalence of (1) and
(3) uses (6.7.1).
A space X is n-connected if (1)–(3) in (6.7.6) hold for X. Note that this is compatible with our previous definitions for n D 0; 1.
144 Chapter 6. Homotopy Groups
Let f W X ! Y be a map and X Z.f / the inclusion into the mapping
cylinder. Then f is said to be n-connected if .Z.f /; X/ is n-connected. We then also say that f is an n-equivalence. Thus f is n-connected if and only if
f W q .X; x/ ! q .Y; f .x// is for each x 2 X bijective (surjective) for q < n
(q D n). If f |
is an 1-equivalence we also say that f is a weak (homotopy) |
equivalence. |
Thus f is a weak equivalence if and only if f W n.X; x/ ! |
n.Y; f .x// is bijective for each n 0 and each x 2 X.
(6.7.7) Proposition. Let .p1; p0/ W .E1; E0/ ! B be a relative Serre fibration. Let Fjb denote the fibre of pj over b. Then the following are equivalent:
(1).E1; E0/ is n-connected.
(2).F1b; F0b/ is n-connected for each b 2 B.
Proof. This is a direct consequence of (6.3.8). |
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The compression properties of an n-connected map can be generalized to pairs of spaces which are regular unions of cubes of dimension at most n. We use this generalization in the proof of theorem (6.7.9). Consider a subdivision of a cube I n. Let us call B a cube-complex if B is the union of cubes of this subdivision. A subcomplex A of B is then the union of a subset of the cubes in B. We understand that B and A contain with each cube all of its faces. The k-skeleton B.k/ of B consists of the cubes in B of dimension k; thus A.k/ D B.k/ \ B.
(6.7.8) Proposition. Let f W X ! Y be n-connected. Suppose .C; A/ is a pair of cube-complexes of dimension at most n. Then to each commutative diagram
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there exists ‰ W C ! X such that ‰jA D ' and f ‰ ' ˆ relative to A.
Proof. Induction over the number of cubes. Let A B C such that C is obtained from B by adding a cube W of highest dimension. Then @W B. By induction there exists ‰0 W B ! X such that ‰0jA D ' and a homotopy H W f ‰0 ' ˆjB relative to A. Extend H to a homotopy of ˆ. The end ˆ1 of this homotopy satisfies ˆ1jB D f ‰0. We now use that f is n-connected and extend ‰0 over W to ‰ W C ! X such that f ‰ ' ˆ1 relative to B. Altogether we have
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(6.7.9) Theorem. Let ' W .X; X0; X1/ ! .Y; Y0; Y1/ be a map such that the re-
strictions 'i W Xi ! Yi are n-connected and '01 W X0 \ X1 ! Y0 \ Y1 is .n 1/- connected. Suppose X D X0ı [ X1ı and Y D Y0ı [ Y1ı. Then ' is an n-equivalence.
6.7. Higher Connectivity |
145 |
Proof. We use mapping cylinders to reduce to the case of inclusions ' W X Y; 'i W Xi Yi . Let .F; f / W .I n; @I n/ ! .Y; X/ be given. We have to show that this map is homotopic relative to @I n to a map into X. Let
Ai D F 1.Y X Yiı/ [ f 1.X X Xiı/:
These sets are closed and disjoint. By the Lebesgue lemma we choose a cubical subdivision of I n such that no cube W of the subdivision intersects both A0 and A1. Let Kj be the union of the cubes W which satisfy
F .W / Yiı; f .W \ @I n/ Xiı:
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We denote by K the .n 1/-skeleton of a cubical complex; then K \ @I n D
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Since .Y01; X01/ is .n 1/-connected there exists a homotopy relative to @I n \ K01 from F01 to a map g01 W K01 ! X01. Define g0 W K0 \ .@I n [ K / ! X0 by
g0jK0 \ @I n D f0; g0jK0 \ K1 D g01:
(Both maps agree on the intersection.) The homotopy F01 ' g01 and the constant
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homotopy of f0 combine to a homotopy of F0 |
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constant on K0 \ @I . Since the inclusion of a cube complex into another one is a
cofibration, this homotopy can be extended to a homotopy |
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F0 to H0. We obtain a diagram |
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where H0 is homotopic to h0 |
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We prove the second part similarly. We obtain a map g1 W K1 \.@I n [K0 / ! Y1 |
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146 Chapter 6. Homotopy Groups
The maps h0 and h1 coincide on K01 and yield a map h W K0 [ K1 ! X which is homotopic relative @I n to F jK0 [ K1 ; moreover hj@I n D f . Let now W be an n-dimensional cube, say with W K0. Then @W K0 and h.@W / D h0.@W / X0. Since .Y0; X0/ is n-connected, we can deform the map relative to @W to a map into X0.
(6.7.10) Corollary. Let f W X ! Y be an n-connected map between well-pointed spaces. Then †f W †X ! †Y is .n C 1/-connected. If X is n-connected, then †X is .n C 1/-connected. The sphere SkC1 is k-connected.
Proof. Let †0X denote the unpointed suspension of X. This is a quotient of X I and covered by the open cones C0 D X Œ0; 1Œ=X 0 and C1 D X 0; 1 =X 1 with intersection X 0; 1Œ. We can apply (6.7.7) directly; the cones are contractible and therefore the induced maps Cj .X/ ! Cj .Y / 1-connected. In the case of a well-pointed space X the quotient map †0X ! †X is an h-equivalence.
(6.7.11) Theorem. Let f W X ! Y be a continuous map. Let .Uj |
j j 2 J / and |
.Vj j j 2 J / open coverings of X and Y such that f .Uj / Vj . |
Suppose that |
for each finite E J the induced map fE |
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E Vj is a weak |
equivalence. Then f is a weak equivalence |
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Proof. |
By passage to the mapping cylinder we can assume that f is an inclusion. |
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.Y; X/ be given. We have to deform h relative to @I n into X. |
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the problem to J D f0; 1g. Then we apply (6.7.9). |
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Problems
1.Let Y D f0g [ fn 1 j n 2 Ng and X the same set with the discrete topology. Then the identity X ! Y is a weak equivalence but there does not exist a weak equivalence Y ! X.
2.Identify in S1 the open sets f.x; y/ j y > 0g and f.x; y/ j y < 0g to a point. The quotient map S1 ! S onto the quotient space S, consisting of four points, is a weak equivalence (but not a homotopy equivalence). In particular 1.S/ Š Z. Show that S has a universal covering.
6.8 Classical Groups
We use exact sequences of Serre fibrations and deduce from our knowledge ofi .Sn/ other results about homotopy groups of classical groups and Stiefel manifolds. We use a uniform notation for the (skew) fields F D R; C; H and the
6.8. Classical Groups |
147 |
corresponding groups (orthogonal, unitary, symplectic)
O.n/ D O.n; R/; |
SO.n/ D SO.n; R/; |
U.n/ D O.n; C/; |
SU.n/ D SO.n; C/; |
Sp.n/ D O.n; H/: |
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Let d D dimR F . The starting point are the (Serre) fibrations which arise from the action of the orthogonal groups on the unit spheres by matrix multiplication
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The inclusions j of the groups arise from A |
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colimn O.n; F / and SO.1; F / D colimn SO.n; F /. From |
i .S / D 0, i < n and the exact homotopy sequences of the fibrations we deduce that the inclusions j W O.n; F / ! O.n C 1; F / and j W SO.n; F / ! SO.n C 1; F / are d.n C 1/ 2 connected. By induction and passage to the colimit we obtain
(6.8.1) Proposition. For n < m 1, the inclusions O.n; F / ! O.m; F / and SO.n; F / ! SO.m; F / are d.n C 1/ 2 connected; in particular, the homomorphisms i .O.n; F // ! i .O.m; F // are isomorphisms in the range i n 2 .R/,
i 2n 1 .C/, and i 4n C 1 .H/. |
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We turn our attention to Stiefel manifolds of orthonormal k-frames in F n: |
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Vk .Rn/ Š O.n/=O.n k/ Š SO.n/=SO.n k/; |
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Vk .Cn/ Š U.n/=U.n k/ Š SU.n/=SU.n k/; |
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Vk .Hn/ Š Sp.n/=Sp.n k/: |
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We have the corresponding (Serre) fibrations of the type H ! G ! G=H for these homogeneous spaces. We use (6.8.1) in the exact homotopy sequences of these fibrations and obtain:
(6.8.2) Proposition. i .Vk .F n// D 0 for i d.n k C 1/ 2. |
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We have the fibration |
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The fibre over ekC1 is homeomorphic to Vk .F n/; with W v 7!.v; 0/ we obtain a homeomorphism j W .v1; : : : ; vk / 7!. v1; : : : ; vk ; ekC1/ onto this fibre. From the homotopy sequence of this fibration we obtain
(6.8.3) Proposition. j W i .Vk .F n// ! i .VkC1.F nC1// is an isomorphism for i d.n C 1/ 3.