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Белоногов. Задачник по теории групп

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$ I ϕ E , G = X | R !

Gϕ = Xϕ | R(ϕ) O

W W(X) ψ E X

Xψ > Xψ W (ψ) E , # X W

I ψ ! Xψ W (ψ) X W

 

 

 

R R(X) G E ; H

 

 

ψ

 

X

 

G

!

G = X

ψ

 

 

(

 

 

 

 

 

 

R(ψ)

GD

 

 

 

 

 

 

 

 

 

. G , , X R

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. a, b a4 = b4 = 1, b1ab = a1

( Da, b a2, b2 c, d c2, c1dcd

. D2n a, b an = 1, b2 = 1, b1ab = a1

a, b a2, b5, a1bab2 O

p E G = a, b, c ap = bp = c2 = 1, ab = ba, ca = bc O

! Q+ a1, a2, . . . , an, . . . a22 = a1, a33 = a2, . . . , ann = an−1, . . .

" Q(p) a1, a2, . . . , an, . . . ap2 = a1, ap3 = a2, . . . , apn+1 = an, . . .

# Zpa1, a2, . . . , an, . . . ap1 = 1, ap2 = a1, . . . , apn+1 = an, . . .

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R {y = w} X R

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u

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wy

a, b, c b2, (bc)2 x, y, z y2, z2

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a, b, c, d ab = c, bc = d, cd = a, da = b ?

( S3 a, b a3 = 1, b2 = 1, (ab)2 = 1 x, y x2, y2, (xy)3r, f f 2, f rf r2

. A4 a, b a3 = 1, b3 = 1, (ab)2 = 1 c, d c3 = 1, d2 = 1, (cd)3 = 1

0 S4 a, b a4 = 1, b3 = 1, (ab)2 = 1

% A5 a, b a5 = 1, b3 = 1, (ab)2 = 1

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# ) G = a, b a3 = b3 = 1, ba = a2b2

H = a, b a3 = b6 = 1, ba = a2b2

$ ( I a4 = b4 = 1 ba = a2b2! ab = (ba)2 (ba)5 = 1

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. O

< !

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G HH

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. 7 ,

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. c × d E

G

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n Z

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#

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g n 3 "

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P

i(P ) = gpi | g P

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P

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p

p p

p

 

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p!

! $

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n − 1

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# !

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n

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n

 

y

 

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2

 

ϕ 2

 

 

 

 

 

 

 

 

 

2n

 

 

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= b4 = 1, a2n−2

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2n

 

 

 

 

 

 

 

 

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# #! "

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- < 0 K & !

! Ω1(P ) 1(P )

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! ( I P ! d(P ) = m(P ) = rs(P )

. rs(P ) = max{d(H) | H ≤ P }

0 I N P !

d(P ) ≤ d(P/N ) + d(N )!

m(P ) ≤ m(P/N ) + m(N )!

rs(P ) ≤ rs(P/N ) + rs(N )

! I |P/P | = p3 P E $#! rs(P ) 3

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2 #

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, P ! & cl(P )! m(P )! rs(P )

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0 L P

% a2b2 E $

. P ! ! P

& P/ a2b2 Q8

! P E p4! 4 : a b

! o(a) = o(b) = p2! ab = a1+p ) ( Z(P ), P cl(P )!

. Φ(P )! 0 Ω1(P )

! 2 $ p4 p > 2

, Mp4 ! #

! ! > 7 pn! " $# #

p! , # H Zpn (n ≥ 1)! Zpn−1 × Zp (n ≥ 2)!

Mpn (n ≥ 3)! D2n (n ≥ 3)! Q2n (n ≥ 3)! SD2n (n ≥ 4)

 

×

! " < P = a pn−1

b p #

Φ(P )!

$ !

i(P ) (1 ≤ i ≤ n − 1)!

< ! apn−2 P

! # P Mpn ! n ≥ 3 pn = 8! ! P = a pn−1b p ! ab = a1+pn−2

( P = apn−2 Zp

. Φ(P ) = Z(P ) = ap Zpn−2 0 cl(P ) = 2

% P p + 1 H ap × b abj !

j

{0

, . . . , p

n

1

}i

 

 

 

 

 

 

 

 

 

 

 

 

 

1

 

 

 

 

 

 

 

 

 

 

 

 

& Ωi(P ) = ap − − , b

 

i {1, . . . , n − 1}

 

 

5 <

" x P \ Z(P ) CG(x) = x Z(P ) xP = xP

 

ab = a1

 

 

 

 

 

 

 

 

 

 

 

 

 

!$ P E : D2n ! n

 

 

3!

P = a

2n−1 b 2

( Z(P ) = a2n−2

 

 

P/Z(P )

 

D2n−1

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

. cl(P ) = n − 1!

P E

 

0 P = Φ(P ) = a2

 

 

 

 

 

 

 

 

 

0 P H

 

 

 

 

 

a , a2

 

b

D2n−1 a2

 

ab

D2n−1 .

 

 

 

 

 

 

 

 

 

 

 

 

 

 

% A : P \ a " .

& . " 0 4 : M a2n−2 ! b! ab! 4

(a2n−2 )P = {a2n−2 }!

bP = b a2 ! CP (b) = Z(P ) × b ! (ab)P = ab a2 ! CP (b) = Z(P ) × ab

- J a "

P

6 =" 4 "$! Z(P )!

" P

 

8 P . 4

T0 = Z(P ) × b

 

T1 = Z(P ) × ab

 

 

 

(/ < " # # T H

CP (T ) = T

NP (T ) =

T, a2n−3 D8

 

 

 

 

 

 

 

 

(( ) m(P ) rs(P )

 

 

 

 

 

! P

 

Q2n (n

3)! P = a 2n−1

b 4!

a2n−2 = b2

 

 

 

 

 

 

 

 

ab

= a1

 

 

 

P

 

 

 

 

 

 

(-./ A ! !

P " "$"!

P/Z(P ) D2n−1 !

cl(P ) = n − 1 P E !

P H

a ,

a2

b

Q2n−1 ,

a2

ab

 

Q2n−1

,

 

 

 

 

 

 

 

 

P \ a 4 : %! m(P ) = 1! rs(P ) = 2

! P

 

SD2n ! ! P = a 2n−1

b

2! ab = a1+2n−2

(n ≥ 4)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

2n−2

 

P/Z(P )

 

D2n−1

 

 

 

 

 

( Z(P ) = a

 

 

2

 

 

 

 

 

 

. cl(P ) = n − 1 P E !

 

0 P = Φ(P ) = a2 E $ 2n−2

 

% P 0 H

 

 

 

 

a , a2

 

b

D2n−1

a2

 

ab

 

Q2n−1.

 

 

 

 

 

 

 

 

 

 

& Ω1(P ) E : 2n−1

 

 

 

5 N P

 

N < P

N

P

 

 

 

 

 

 

 

 

·

 

 

 

 

 

 

 

 

- 2 # " , ,

P

6 P \ a : . %

8 2 # $ : 4 :

P ! P . 4 "$# .

4 : %

(/ P ( (

6 I V E

P ! CP (V ) = Z(V ) |NP (V ) : V | = 2

(( I D E : 2m 8 P !

$ D a (. ) m(P ) rs(P )

! ) p! " $