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3.1. Cartesian coordinates in the space

71

assuming that the coordinate of the point Mx on the x-axis equals x and there hold the similar relations for the other axes.

z

Mz

M

O

y

My

x Mx

Fig. 1. Cartesian coordinates in the space

Coordinate systems in the space are divided into two classes: righthanded and left-handed.

For right-handed coordinate system the shortest rotation from x-axis to y-axis viewed from the top of z-axis is performed counterclockwise. In the case when the same rotation is clockwise the coordinate system is called left-handed. These cases are illustrated by the following gure.

z

 

 

z

 

 

 

 

 

y

x

x

y

Fig. 2. Right-handed and left-handed coordinate systems

72

Chapter 3. Analytic geometry in the space

We always assume that the coordinate system under consideration is right-handed.

3.1.1Distance between two points

Let us consider two points M1(x1; y1; z1) and M2(x2; y2; z2). We take the rectangular parallelepiped whose faces are parallel to the coordinate planes and pass through these two points. The distance between these points equals the diagonal of this parallelepiped.

z

M2

M1

y

M1x

M2x

x

Fig. 3. Distance between two points

First of all we remind some well known fact from the school math course.

In the rectangular parallelepiped the square of any diagonal equals the sum of squares of its three edges.

The length of the edge of the parallelepiped which if parallel to the x- axis equals the distance between projections M1x and M2x of the points M1 and M2 on the x-axis. This distance equals jx2 x1j. Similarly we nd the

3.1. Cartesian coordinates in the space

73

lengths of the other two edges. They are jy2 y1j and jz2 z1j. From here we get that

p

jM1M2j = (x2 x1)2 + (y2 y1)2 + (z2 z1)2

3.1.2Vectors in the space

Definition. A vector in the space is a directed segment of a straight line, that is, a segment for which it is indicated which of its boundary points

is the beginning and which is the end.

Many de nitions concerning vectors in the space exactly repeat the given earlier de nitions for the case of vectors on the plane. These are the de nitions of equality of vectors, the length of a vector, zero vector, the operations of adding vectors and multiplying a vector by a scalar, the angle between vectors, scalar product and its properties (p. 16), collinear and orthogonal vectors. We do not repeat these de nitions and mention only the properties and relations that are formulated at least slightly di erent di erent from

the case of the plane.

For the points A(a1; a2; a3) and B(b1; b2; b3) in the space the coordinates

AB are de ned as b

1

 

1

, b

2

a

2

and b

3

 

a

3

respectively.

 

 

a

 

 

 

 

 

 

 

of the vector !

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This property is written in the following form:

 

 

 

 

 

 

 

 

 

 

 

 

!

 

 

f

1

 

1

; b

2

2

; b

3 a3g:

 

 

 

 

 

 

 

 

 

AB =

 

b

 

a

 

 

a

 

 

 

 

 

 

 

 

 

 

 

 

 

The operations with the vectors have the following coordinate form.

 

 

 

 

 

 

~

 

 

fb1; b2; b3g then ~a = f a1; a2; a2g,

If 2 R, ~a = fa1; a2; a3g, b =

~

 

 

+ b3g, ~a

 

~

 

 

 

 

b1; a2 b2; a3 b3g.

 

 

~a + b = fa1 + b1; a2 + b2; a3

b = fa1

 

 

 

 

OA where O(0; 0; 0) is the origin and A(a

; a ; a )

From the equality ~a = !

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

1

 

2

3

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

we get that ~a = OA =

 

 

a2

+ a2 + a2 .

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Let us considerj j j

twoj

 

1

 

2

 

3

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

pvectors

 

de ned

in

the

coordinate

form:

~a

=

~

; b2; b3g. As in the case of vectors on the plane, the

fa1; a2; a3g, b = fb1

74

Chapter 3. Analytic geometry in the space

scalar product of these vectors is obtained in the coordinate form by the

~

following similar formula: ~ab = a1b1 + a2b2 + a3b3.

~

; b2; b3g are orthogonal if and

The vectors ~a = fa1; a2; a3g and b = fb1

only if a1b1 + a2b2 + a3b3 = 0.

 

 

 

 

 

 

~

 

 

 

The vectors ~a = fa1; a2; a3g and b = fb1; b2; b3g are collinear if and

 

 

only if

a1

=

a2

=

a3

.

 

 

b1

b2

 

 

 

 

 

 

 

b3

 

 

 

 

 

 

 

 

 

 

~

 

 

Let us consider three vectors ~{ = f1; 0; 0g, ~| = f0; 1; 0g and k = f0; 0; 1g.

There are valid the equalities j~{ j = 1, j~| j

~

 

= 1, jkj = 1 and these vectors are

pairwise orthogonal. These vectors are called the orthonormal basis in the space.

z

~

k

~|

O

y

~{

x

Fig. 4. Orthonormal basis in the space

Every vector ~a = fa1; a2; a3g has the following representation

~a = a1f1; 0; 0g + a2f0; 1; 0g + a3f0; 0; 1g;

~

so ~a = a1~{ + a2~| + a3k. The obvious geometrical meaning of the values a1, a2, a3 is shown in the following gure.

3.1. Cartesian coordinates in the space

75

a3 z

 

~

~a

k

O

~|

a2

 

y

~{

a1 x

Fig. 5. Coordinates in the space

For an arbitrary vector ~a = fa1; a2; a3g we have the expansion

~

~a = a1~{ + a2~| + a3k:

Taking scalar products of the both sides and the vector ~{

we get

 

 

~

 

 

 

a~{ = a1{~ + a2|~{ + a3k~{ = a1:

 

 

 

~

We obtain that

Here we used the relations {~ = 1, |~{ = 0 and k~{ = 0.

 

 

~

 

a1 = a~{. Similarly we get that a2 = ~a~| and a3 = ~a k.

 

 

 

~

 

Let ' be the angle between some vectors ~a and b such that j~aj = 1 and

~

~

~

 

jbj = 1.

Then ~a b

= j~aj jbj cos ' = cos '. Now we take a vector ~n such

that j~nj

 

 

~

= 1. Let , , be the angles between ~n and the vectors ~{, ~|, k

~

respectively. Then n~{ = cos , ~n~| = cos , ~n k = cos and therefore ~n =

fcos ; cos ; cos g. The values cos , cos , cos are called the direction cosines of the vector ~n. From the equality j~nj = 1 we get that

cos2 + cos2 + cos2 = 1:

An ordered system consisting of three vectors is called the triple. The word \ordered" means that it is known which vector is the rst, which is the

76 Chapter 3. Analytic geometry in the space

second, which is the third. The order of the vectors is usually determined

~

by their position in the record. If the vectors ~a, b, ~c are di erent, then the

following triples obtained by permuting the vectors will also be di erent:

~

~

the triple ~c, ~a, b, the triple b, ~c, ~a and so on.

Definition.

It is said that vectors ~a1, ~a2, . . . , ~ak are coplanar if there

is a plane to which they are all parallel.

Further we'll use the following obvious properties:

Any two vectors are coplanar.

The zero vector is parallel to all planes.

~

If one of the vectors ~a, b, ~c equals the zero vector, then these vectors

 

are coplanar.

~

If among the vectors ~a, b, ~c there is a pair of collinear ones, then these

 

vectors are coplanar.

In the case of coplanar vectors we'll assume that these vectors are reduced to one initial point and the corresponding plane (not necessarily unique) passes through this point.

Definition. The triple of non-coplanar vectors is called right-handed if after reducing these vectors to the common initial point, the shortest

~

rotation from ~a to b viewed from the ending point of ~c onto the plane

~

de ned by ~a and b is performed counterclockwise. If the same rotation is performed clockwise the triple is called left-handed.

Remark. It is obvious that a coordinate system is right-handed if and

~

only if the corresponding vectors ~{, ~|, k form the right-handed triple and

that the similar fact is valid for the case of left-handed coordinate systems.

Definition.

~

For the vectors ~a and b their vector product ~c is de ned

by the following properties:

~

~

1) j~c j = j~a j jb j sin ' where ' is the angle between ~a and b;

3.1. Cartesian coordinates in the space

77

 

 

~

 

2) ~c is orthogonal to ~a and b;

 

 

~

~

 

3) if ~c 6= 0 then ~a, b, ~c is the right-handed triple.

 

Let us analyze this de nition.

 

 

 

~

 

We suppose rst that the vectors ~a and b are collinear. Then we have

one (and only one) of the following cases.

 

~

~

~

 

• ~a = 0 or b

= 0, then the angle ' is undetermined, in the product

j j j~ j

~a b sin ' at least one of the rst two factors vanishes, therefore the

product takes the zero value independently of the undetermined term

 

~

 

sin ', we obtain that j~c j = 0 and ~c = 0;

 

~

~ ~

~

• ~a 6= 0 and b 6= 0, then ' = 0 or ' = , sin ' = 0, ~c = 0 as in the previous case.

~

Therefore, in the case of collinear vectors ~a and b, vector ~c is uniquely

de ned by property 1), property 2) holds, and property 3) does not need to be checked.

 

~

~

Now we turn to the case when ~a and b are not collinear. Then j~aj 6= 0,

jbj 6= 0, the angle ' is de ned, 0 < ' < , therefore j~c j 6= 0. Adding

the property 2) we see that there are de ned exactly two vectors since this

~

vector is orthogonal to ~a and b and has the obtained before nonzero length.

Now the property 3) permits to select one and only one vector from these two ones.

So in each case the vector product is uniquely determined. The vector

~

~

 

product of the vectors ~a and b is denoted by ~a b. The vector product is

 

~

~

also called cross product and is sometimes denoted as [~a b] or [~a; b].

~

In the following, we use some properties of triples. A triple ~a, b, ~c of non-

collinear vectors is either right-handed, or left-handed. These properties we will call the type of a triple. Speaking about transformations of triples we say that the transformation under consideration does not change (changes) the type of a triple if from a triple of some type we always obtain the triple of the same (of the opposite) type.

78

Chapter 3. Analytic geometry in the space

~

~

~

If ~a, b, ~c

is the right-handed triple then b, ~a, b is the left-handed triple.

This property immediately follows the de nition of rightand left-handed triples. Moreover, swapping any two vectors of a triple changes its type. It is easy to see that the cyclic rearrangements of vectors in the triple (obtaining

~ ~

~

 

~c, ~a, b or b, ~c, ~a from ~a, b, ~c) does not change the type of a triple.

 

~

~

If > 0 then the triples ~a, b, ~c and ~a, b, ~c have the same type since

~

the shortest rotations from ~a to b when viewed from the ending point of ~c

or when viewed from the similar point of ~c are performed in the same direction. This property is true for any vector of a triple: multiplication of any vector of a triple by a positive scalar does not change the type of this triplet.

If we change the sign of one vector of a triple then the triple changes its type. Combining this property with the previous one, we get that multiplication of any vector of a triplet by a negative scalar changes the type of

this triplet.

Now we turn to the properties of vector product. From the analysis following the de nition of vector product we obtain the following property.

 

~

 

 

~

~

1) Vectors ~a and b are collinear if and only if ~a b = 0.

 

 

 

 

 

~

As the special case we get that there always holds the equality ~a ~a = 0.

~

~

 

 

 

 

2) b ~a = (~a b) (anticommutative property).

 

 

To prove this property, we will consider two cases.

 

 

~

~

~

~

 

~

If ~a and b are collinear then ~a b

= 0 and b ~a

= 0. Therefore the

equality under consideration is valid.

 

 

 

 

 

 

 

 

 

~

Now we consider the case of non-collinear vectors ~a and b. We denote

~

 

 

~

 

 

~c = ~a b. Let ' be the angle between ~a and b. Then ' is also the angle

~

 

 

 

between b and ~a. From the property 1) of de nition of vector product we

~

~

~

~

get the equality j~a bj = jb ~aj.

The both vectors ~a b and b ~a are

~

orthogonal to each of the vectors ~a and b. After applying the property 2)

~ from the de nition we get that there are only two possible values for b ~a:

 

3.1. Cartesian coordinates in the space

79

 

 

 

~

 

~

~c and ~c. The triple ~a, b, ~c is right-handed, therefore the triple b, ~a, ~c is

 

 

 

~

 

~

 

left-handed and the triple b, ~a, ~c is right-handed. We get that b ~a = ~c,

~

~

 

 

 

 

b

~a = (~a b).

 

 

 

 

 

~

~

~

 

 

3) (~a b) = ( ~a) b = ~a ( b):

 

 

 

 

 

~

~

 

We will prove the equality (~a b) = ( ~a) b.

~

 

If ~a and b are collinear or = 0 then the both parts of the equality

under consideration equal the zero vector, and the equality is valid.

~

6= 0. Let ' be the

Now we assume that ~a and b are not collinear and

~

~

angle between ~a and b and let be the angle between ~a and b. Then = '

if > 0 and = ' if < 0. In the second case sin

= sin( ') =

sin ', as in the rst case.

 

~a, > 0

~a

~

' b

~a, < 0

 

 

~

 

Fig. 6. Angles between ~a and b

 

For any 6= 0 we have

 

 

 

~

~

~

 

j (~a b)j = j j j~a bj = j j j~aj jbj sin ';

 

~

~

~

 

j( ~a) bj = j( ~aj jbj sin

= j j j~aj jbj sin ';

 

therefore

 

 

 

 

~

~

(1)

 

j (~a b)j = j( ~a) bj:

~

~

~

 

Since ~a b is orthogonal to ~a and b, we get that (~a b) is orthogonal

~

~

~

The

to ~a and b. The product ( ~a) b is also orthogonal to ~a and b.

80

 

Chapter 3. Analytic geometry in the space

~

~

~

~

 

triple ~a, b, ~a b is right-handed. Therefore the triple ~a, b, (~a b) is also

1)

~

~

 

 

right-handed

. The triple ~a, b, (~a b) is also right-handed. Taking into

 

 

~

~

account the relation (1) we get the desired equality (~a b) = ( ~a) b.

 

 

~

~

 

Similar arguments permit to obtain the equality (~a b) = ~a ( b).

Remark. It is assumed that the operation of multiplication by a scalar has higher priority than the operation of vector multiplication, and the

 

 

 

 

~

~

~

obtained relation may be rewritten in the form (~a b) = ~a b = ~a b.

 

 

 

 

~

~

 

From these relations we also get the equality ~a b = (~a b).

 

The next property we give without proof.

 

 

4)

~

 

~

~

~

 

~a (b + ~c ) = ~a b + ~a ~c, (~a + b ) ~c = ~a ~c + b ~c.

 

5)

~

~

 

~

The length of the

Let ~a 6= 0 and b

6= 0 be non-collinear vectors.

~

vector ~c = ~a b equals the area of the parallelogram with adjacent sides ~a

~

 

and b under the assumption that these vectors are reduced to the same initial

point.

 

Let us denote j~aj

~

= a, jbj = b and let ' be the angle between these

vectors.

~

b

h

'

~a

Fig. 7. Parallelogram de ned by two vectors

The base of the parallelogram equals a, the height of the parallelogram

j ~j h = b sin ', the area A = ah = ab sin ' = ~a b .

Now we are going to nd the vector product in the coordinate form.

~

For the vectors ~{, ~|, k from the orthonormal basis using the de nition of

1)In the case < 0 multiplying the rst vector by we change the type of the triple, then multiplication

of the third vector by restores the initial type.