тест 4 / SQL2

1

SELECT AVG (status) AS avgSt FROM s

2

SELECT city, COUNT(*) AS cnt FROM s GROUP BY city ORDER BY city

3

SELECT COUNT (*) AS cnt FROM s

4

SELECT sNo, MAX (qty) AS maxQty FROM sp GROUP BY sNo ORDER BY sNo

5

SELECT sNo FROM s WHERE status BETWEEN 30 AND 50 OR sname LIKE %th ORDER BY sNo

6

SELECT s.sNo AS sNo, sName, qty FROM s INNER JOIN sp ON (s.sNo = sp.sNo) WHERE s.sNo = 's2' ORDER BY qty

7

SELECT COUNT (DISTINCT city) AS nCity FROM s

8

SELECT s.sNo AS sNo, sName, qty FROM s INNER JOIN sp USING (sNo) WHERE s.sNo = 's2' ORDER BY qty

9

SELECT s.sNo AS sNo, sName, qty FROM s, sp WHERE s.sNo = sp.sNo AND s.sNo = 's2' ORDER BY qty

10

SELECT s.sNo AS sNo, sName, qty FROM s LEFT JOIN sp USING (sNo) WHERE s.sNo = 's5’