Типовик / Типовик, 1 модуль
.pdfОглавление |
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1. ................................................................................ |
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1 ........................................................................... |
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1 ............................................................................................. |
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2. ........ |
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3. .......................................... |
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4. ....................................... |
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4 ......................................................................... |
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4 ........................................................................................... |
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5. ! ............................................. |
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5 ......................................................................... |
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5 ........................................................................................... |
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6. " ............................................................... |
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6 ......................................................................... |
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6 ........................................................................................... |
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7. ........................................................... |
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7 ........................................................................ |
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7 ........................................................................................... |
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3
Общие рекомендации
" ! # $
: « », « » «% !».
& ' ! # # ,
! ! ' . ( !$
, ! !.
& ' ! # # ,
' # !, '
! # , #
# # .
! # .
! $,
! ' # ! !
, # # .
& ! ! $ !,
# ! # ! !,
! ' ! # $ , ' #,
! ' .
4
Задание 1. Векторная алгебра
Пример выполнения задания 1
) : A(2,−1,3), B(4,5,0), C (2,2,−1), D(2,1,0).
( AB , AB , AB × AC, cos ϕ , ϕ - ! ' ! AB
, $ ! ϕ , S ABC , VABCD , hD .
!:
AB = 4 + 36 + 9 = 7,
AC = 9 +16 = 5.
& ! ! ' ! #$
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uuur uuur |
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AB |
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7 $ !$ !, ! !
! ϕ , b = 10i + 51 j − 43k.
# ! # #$ :
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uuur uuur |
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AB × AC = |
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* #$ :
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Варианты задания 1
) A, B, C, D. ( AB, AB , AB × AC, cosϕ , ϕ --
! ' ! AB AC, $ !
ϕ, S ABC , VABCD , hD .
1.A(1,2,3), B(0,0,1), C (4,4,−3), D(1,2,6).
2.A(−1,2,1), B(3,−1,1), C (1,4,2), D(5,2,1).
3.A(1,−2,3), B(−5,0,0), C (−3,1,3), D(1,1,3).
4.A(2,1,1), B(3,3,3), C (−4,−1,−2), D(6,3,3).
5.A(−2,1,2), B(2,1,5), C (0,2,4), D(−4,0,6).
6.A(−2,−1,1), B(4,−3,4), C (2,2,1), D(2,3,1).
7.A(2,1,3), B(4,3,4), C (4,−2,−3), D(6,3,4).
8.A(2,1,−3), B(2,4,1), C (3,3,−5), D(2,−2,−1).
9.A(2,1,−2), B(−4,−4,0), C (5,1,2), D(3,1,0).
6
10.A(1,−2,1), B(−1,−1,3), C (3,1,−5), D(−1,2,3).
11.A(1,3,−1), B(−2,3,3), C (2,5,−1), D(2,5,8).
12.A(3,1,2), B(1,4,8), C (3,4,−2), D(1,7,8).
13.A(2,1,3), B(1,3,1), C (−1,7,5), D(1,6,1).
14.A(3,1,−2), B(3,−2,2), C (2,3,−4), D(3,4,0).
15.A(3,1,1), B(5,7,−2), C (6,1,−3), D(4,2,2).
16.A(1,−2,2), B(2,−4,4), C (4,0,−4), D(5,−4,4).
17.A(2,1,−1), B(2,4,3), C (4,30), D(2,4,1).
18.A(2,3,−3), B(−1,1,3), C (2,6,1), D(2,1,−1).
19.A(1,1,−1), B(−1,2,1), C (4,3,5), D(1,4,−1).
20.A(2,−2,1), B(−1,−2,−3), C (4,1,7), D(5,−2,4).
21.A(1,−1,2), B(3,2,−4), C (1,2,6), D(1,2,−1).
22.A(2,−1,1), B(1,1,−1), C (−4,2,3), D(6,1,−1).
23.A(3,1,4), B(3,−3,1), C (2,3,2), D(3,4,10).
24.A(3,2,−1), B(−3,−1,1), C (3,5,3), D(3,3,0).
25.A(4,1,5), B(2,2,3), C (−2,−1,2), D(5,2,3).
26.A(2,−1,−3), B(2,3,0), C (3,1,−1), D(2,1,0).
27.A(−3,−1,−2), B(3,−3,1), C (1,2,−2), D(1,3,−2).
28.A(−1,−2,3), B(1,0,4), C (3,−2,0), D(2,−2,6).
29.A(4,2,−5), B(1,2,−1), C (3,0,−3), D(7,2,8).
30.A(3,1,−1), B(6,3,5), C (6,1,3), D(0,−1,−1).
7
Задание 2. Приведение кривой второго порядка к
канонической форме
Пример выполнения задания 2
) ! : 17 2+8 2+12 -2 +4 - =0.
# ,
! # ! . # + ! !$
.
. !:
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(*)
!$ + , !:
8
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+ !, !:
' # !, . . |
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tg a, |
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,
+ ' (*).
+ ! !:
!, !:
9
# !:
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, + ! a=1, b=2.
( ! 1 ' +
.
,Y2 Y1
X1
X2
! 1. - 2
Варианты задания 2
# : ,
# , #
! ! ! #
, '
.
10
1.
2.
3.
4.
5.
6. 13
7.
8.
9. 10.
11.
11
12.
13.
14.
15. 16.
17.
18.
19. 20. 21.
22.
23.
24.
12