Лабораторные работы по химии
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1. |
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: 2МР( ) + |
2( ) = 2МР ( ) + |
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2 МР |
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-393,5 |
-601,8 |
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0 = 2∆ |
0МР |
- ∆ 0 |
2 |
= 2(-601,8) + 393,5 = -810 |
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2. |
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2. |
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N2 ( ), |
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1) |
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( ) = 2 + 2N2( ), |
∆ |
01 = -557,5 |
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2) |
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2( ) = |
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02 = -393,5 |
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N2 |
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3) N2( ) + 1/2 2 = N2 ( ), |
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∆ 03 = ? |
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(3) |
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(1) |
(2), |
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(-1/2), |
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1) 1/2 |
2( ) + N2( ) = 1/2 ( |
) + N2 |
( ); |
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2) 1/2 ( |
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2( ) |
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3) N2( ) + 1/2 2 = N2 ( ) |
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∆ |
03 |
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∆ |
03 = -1/2 ∆ |
01 + 1/2∆ |
02 = 1/2·557,5 - 1/2·393,5 = 82,0 |
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H10 H 2980 T CP dT, |
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298 |
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HT0 - |
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H2980 - |
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= 298 К. |
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: а |
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CP |
cCP (C ) |
dCP (D) |
aCP ( A) |
bCP (B) , |
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T2 T1 |
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V. |
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= const Qp = ∆H, |
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V = const QV = ∆U |
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V = R, |
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R = 8,314 |
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: 1) |
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S: |
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S = RlnW, |
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R – |
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(∆S>0). |
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(∆S<0). |
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3. |
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1) N 4N |
3( ) = N2 |
( ) + 2 2 ( ); |
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2) 2 2( ) + |
2( ) = 2 |
2 |
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3) 2 2( ) + |
2( ) = 2 |
2 |
( ). |
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(1) |
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∆S3 |
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SH 2O( ) |
SH 2O( ) . |
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S Rln V2 ,
V1
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p2
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n1 n2 – V1 V2 –
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V2>V1, |
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/ л ∙К. |
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∆ : |
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(∆S) |
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(Q = 0, |
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, . . ∆S |
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∆S = 0. |
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, . . |
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(∆S > 0). |
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(∆ < 0, ∆S > 0) |
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G = |
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– S. |
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∆G = ∆ - ∆S. |
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(∆G < 0). |
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(Gmin). |
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(∆G = 0). |
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GT0 RT ln KP .\ |
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1.2 |
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3. |
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15. |
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16. |
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S |
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17. |
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1.3 |
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5.
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1.1 – |
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– 40 |
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20 |
NaOH. |
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1 |
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NaOH |
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5–10 |
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30 |
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