167. Using standard warmth of combustion for substances to calculate thermal effect of reaction

C₂H₅OH_(ж)+СH₃СООН_(ж) → CH₃COOС₂H_5(ж)+H₂О_(ж) при 25⁰С, if warmth of combustion of substances are following -1366,9 кJ/mol, -873,8 кJ/mol, -2254,2 кJ/mol :

1. 13,5 kJ;

2. 15,4 kJ;

3. 17,8 kJ;

4. 7,9 kJ;

5. 11,5 kJ

168. Calculate thermal effect of reaction at 292K and 1, 0133⋅10⁵ Па for reaction: Fe₂O_3(тв)+3CO_(г)=2Fe_(тв)+3CO_2(г),

-821,32 кJ/mol, -110,5 кJ/mol, 0, -393,51 кJ/mol :

1. -27,71 кJ;

2. 13,5 кJ;

3. 141,82 кJ;

4. -354,8 кJ;

5. 0;

169. To define thermal effect of reaction: СН  СН + СО + Н₂О (ж) → СН₂ = СНСООН (ж)

at standard pressure, if warmth of formation are known

Substance	[kJ/mol ]
СН  СН	226,75
СО	–110,50
Н2О (ж)	–285,84
СН2 = СНСООН (ж)	–384,37

1. -214,78 кJ

2. 107,36 кJ

3. 1007,36 кJ

4. –623,09 кJ

5. –154,2 кJ

170. Calculate thermal effect of reaction (kJ) at Т = 298К: CuCl₂ + Zn = ZnCl₂ + Cu

Values are resulted in the table:

Substance
ZnCl2	–478,2
CuCl2	–262,3

1. -215,9

2. 740,5

3. –903,6

4. 904,2

5. 370,2

171. Calculate entropy change under standard conditions for reaction: 2H₂S + SO₂ = 2 Н₂О (ж) + 3S,

If values s are given in the table.

Substance	[J/mol К]
Н2О	69,95
S	32,55
SO2	248,1
H2S	205,64

1. –421,81

2. –102,50

3. 513,24

4. 350,72

5. 231,11

172. Using standard warmth of combustion of substances to calculate thermal effect of reaction at 298к

С₂Н₅ОН(ж) + СН₃СООН(ж) → СН₃СООС₂Н₅(ж) + Н₂О (ж)

Substance	Нсг. [kJ/mol ]
С2Н5ОН(ж)	–1366,9
СН3СООН(ж)	–873,8
СН3СООС2Н5(ж)	–2254,2
Н2О (ж)	0

1. 13,5 кJ

2. -2254,2 кJ

3. –240,2 kJ

4. –3,21 kJ

5. –1,34 kJ

173. Calculate standard change of entropy at 298К for reaction: Cd (тв) + 2AgCl (тв) = 2Ag (тв) + CdCl₂ (тв)

on absolute values entropy of chemical compounds

Substance	S [J/mol К]
Cd	51,76
AgCl	96,07
Ag	42,69
CdCl2	115,3

1. –43,22 J/К

2. 10,16 J/К

3. 0

4. 325,82 J/К

5. –10,16 J/К

174. Calculate thermal effect of chemical reaction (kJ) at Т=298К, Р=1,01310⁵ Па

Cd (тв) + 2AgCl (тв) = 2Ag (тв) + CdCl₂ (тв), if warmth of formation of substances are known

Substance	298 [КJ/mol ]
Сd	0
Ag	0
AgCl	–126,8
CdCl2	–389,0

1. –135,4

2. –263,2

3. –515,8

4. 443,2

5. 344,8

175. Calculate standard change of energy of Gibbs (kJ) for reaction: Cd (тв) + 2AgCl (тв) = 2Ag (тв) + CdCl₂ (тв),

if are known Н₂₉₈ = –135,4 kJ; S₂₉₈ = –76,84 J/К.

1. –112,5

2. 1393,55

3. –141,7

4. 24,61

5. 41,42

176. Calculate thermal effect of reaction (kJ) at Т =298К: CuCl₂ + Zn = ZnCl₂ + Cu