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Task I. Translate into Russian.

Task II. Open the brackets and put the verbs into the right tense and voice form.

1. There is a number of different IT specialities (offer) by the department of Information Technologies and Computer Systems. 2. A friend of mine (enter) Math and Computer science department at Oxford. 3. The professor (give) a math class to the junior students from 11.35 to 13.05 tomorrow. 4. We (graduate) from the University by 2015. 5. My course paper (submit) before the exams started. 6. He (go) to continue studies at post-graduate school.

Task III. Answer the following questions in English (in writing).

1. What general and special subjects do you study?

2. Why are English skills necessary for a future IT specialist? Is English necessary for you personally?

3. How long does it take to obtain a Math and Computer science degree at OmGTU? At Oxford?

4. What can you work as and where upon graduation from your University?

Task I. Translate into Russian.

Task II. Modal verbs.

a) what modal verbs should be used in translating these sentences?

1. Мне пришлось сделать работу заново. 2. Вы должны сдать свои курсовые к концу семестра. 3. Если хотите, можете воспользоваться справочной литературой. 4. Ты можешь решить это уравнение? 5. Вам следует уделить бóльшее внимание математическому анализу. 6. Я не смог посетить лекцию профессора из Оксфорда.

b) translate the sentences into Russian.

1. I must have forgotten about our appointment. 2. They may be having classes right now. 3. She could have left already, it’s late. 4. He must be driving home at the moment. 5. You might have taken my book by mistake.

Task III. Put in writing the following mathematical operations.

Task I. Translate into Russian.

Task II. Find in the Text A (p. 25) sentences with the Infinitive in the function of.

1. circumstance (обстоятельство);

2. complex subject (сложное подлежащее);

3. part of the nominal predicate (часть составного именного сказуемого);

4. part of the verbal predicate (часть составного глагольного сказуемого).

Task III. Answer the following questions in English (in writing).

1. What are the two major types that computer software falls into?

2. What does application software include?

3. What are the other categories of computer software?

4. What stages does software development process consist of?

5. What are the responsibilities of a software engineer?

6. What software programs can be included into Mathematical Software?

Task I. Translate into Russian.

Task II. Find in the Text A (p. 34) sentences with the Participle I, II in the function of.

1. attribute (определение);

2. predicate (сказуемое);

3. circumstance (обстоятельство).

Task III. Answer the following questions in English (in writing).

1. What methods of programming do you study?

2. What are the most useful programming languages and what are they used for?

3. What is the main purpose of programming?

4. What is a programmer responsible for within video game programming?

Task I. Translate into Russian.

Task II. Find in the Text A (p. 42) sentences with the Gerund in the function of.

1. subject (подлежащее);

2. attribute (определение);

3. object (дополнение).

Task III. Answer the following questions in English (in writing).

1. What is Information System?

2. What does IS Management include?

3. What are the responsibilities of the IS administrator?

4. What are the advantages of the IS administration being outsourced?

( )

round brackets; parentheses

{ }

curly brackets; braces

[ ]

square brackets; brackets

a = b

a equals b; or a is equal to b

a ≠ b

a is not equal to b

a > b

a is greater than b

a₂ > a_d

a second is greater than a d^th

b < a

b is less than a

a >> b

a is substantially greater than b

a ≥ b

a is greater than or equal to b

x trends to infinity

a vector; the mean volume of a

the first derivative

the second derivative

9.510

nine thousand five hundred and ten

32 + 8 = 40

thirty-two plus eight is (are) forty; or, thirty-two plus eight equals forty; or, thirty-two plus eight is equal to forty; or, eight added to thirty-two makes forty

20 – 5 = 15

twenty minus five is fifteen; or, twenty minus five is equal to (equals) fifteen; or, twenty minus five leaves fifteen; or, five from twenty is (leaves) fifteen

a plus or minus b

1 · 1 = 1

once one is one

2 · 2 = 4

twice two is (equals) four; or, twice two makes four

6 · 10 = 60

six multiplied by ten equals sixty; or, six multiplied by ten is (equal to) sixty; or, six times ten is sixty

work = force × distance

work is (equal’ to) the product of the force multiplied by the distance; or, work is (equal to) the product of force times the distance

12 : 3 = 4

twelve divided by three equals (is) four

a (one) half

a (one) third

two-thirds

five-ninths

four and a half

eight and three-quarters

0.6 or .6

point six

5.34

five point thirty-four; or, five point three four

2.01

two point nought one; or two point o [ou] one

0.007

point nought nought seven; or, point two oes [ouz] seven

240 kilometers pro 4 hours

8 : 4 = 2

the ratio of eight to four is two

20 : 5 = 16 : 4 or

the ratio of twenty to five equals (is equal to) the ratio of sixteen to four; or, twenty is to five as sixteen is to four

20°

twenty degrees

6´

six minutes; also, six feet

10´´

ten seconds; also, ten inches

a´

a prime

a´´

a second prime; or a double prime; or a twice dashed

a´´´

a triple prime

9²

nine square, or, the square of nine or, nine to the second power

6³

six cubed; or, six to the third (power)

c¹⁸

c [si:] to the eighteenth (power)

a^–10

a [ei] to the minus tenth (power)

the square root (out) of four is (equals) two

the square root of a

the cube root of a

the fifth root of a square

a plus b all squared

L equals the square root (out) of R square plus x square

x plus square root of x square minus y square all over y

the tenth root (out) of a square plus b square

square root out of F first plus A divided by two xd th twice dashed (or double prime)

a to the m/n th power equals the n^th root out of a to the m^th (power)

dz over dx

y is a function of x

partial d two z over partial dx plus partial d two z over partial dy equals zero

indefinite integral of dx (divided) by the square root out of a² minus x²

integral from zero to µ (mu)

d (divided) by dx (or d over dx) of the integral from x nought to x of X large dx

4c plus W second plus 2 m first a prime plus R a^th equals thirty-three and one-third

V equals u square root of sine square i minus cosine square i equals u

tangent r equals tangent i divided by l

the logarithm of two equals zero point three o[ou] one

a is equal to the logarithm of d to the base c

u is equal to the integral of f sub one of x multiplied by dx plus the integral of f sub two of y multiplied by dy

K is equal to the maximum over j of the sum from i equals one to i equals n of the modulus of a_ij of t, where t lies in the closed interval ab and where j runs from one to n

A_vmax is equal to one half mu by r p^th omega L second omega L first (divided) by square root out of R second round brackets opened R first plus omega square L first square by r p^th round brackets closed

Av is equal to mu omega m omega square L square (divided) by r p^th square brackets opened omega square m square plus R second round brackets opened R first plus omega square L square (divided) by r p^th round and square brackets closed