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Завдання 12

Задано координати векторів і у базисі і розклад вектора за цим базисом.

Розкласти вектор за базисом

Номер варіантa

1

(2; –7; 1)

(3; 2; –5)

(–4; 1; 3)

2

(2; 8; 2)

(1; 3; 5)

(3; 5; –1)

3

(5; 3; 2)

(8; –2; 1)

(1; 6; –1)

4

(1; 3; 2)

(2; –5; 7)

(1; 3; –1)

5

(1; 2; 1)

(2; 3; 1)

(–4; –1; –4)

6

(2; –1; 1)

(–1; 1; 3)

(1; –5; –1)

7

(2; 1; 0)

(0; 3; –1)

(5; 16; 10)

8

(2; 1; 1)

(–3; 4; –4)

(1; 2; 0)

9

(–1; 2; 3)

(4; –1; 1)

(–5; 1; –2)

10

(3; 2; 1)

(1; –4; 5)

(–6; 5; –2)

11

(–2; 3; 0)

(5; –1; 4)

(–3; 2; –1)

12

(3; –2; 5)

(–2; 1; 0)

(4; –1; 3)

13

(2; 7; 7)

(–4; 3; 9)

(9; –6; –9)

14

(5; –1; 2)

(–1; 2; 3)

(3; –4; –1)

15

(3; –1; 2)

(–1; –1; 1)

(0; 3; –1)

16

(2; 1; 0)

(1; 0; 5)

(0; 3; –1)

17

(7; 3; –1)

(–1; 0; 8)

(5; 4; –3)

18

(3; 5; 2)

(–2; –8; 1)

(1; 9; 4)

19

(3; –1; 5)

(1; 2; –1)

(–7; –10; 8)

20

(9; –4; 3)

(0; 1; 7)

(1; –6; 8)

21

(4; 0; 5)

(7; 11; –1)

(–1; 2; –3)

22

(–1; 3; 2)

(5; –1; 4)

(–4; 0; –9)

23

(6; 0; 1)

(–2; 4; 7)

(1; –3; –5)

Номер варіантa

24

(1; –8; 3)

(–3; 1; 5)

(7; –1; 0)

25

(–7; 2; 5)

(2; 0; –1)

(–4; –1; 6)

26

(0; 2; 1)

(–3; 2; –7)

(–4; 1; –1)

27

(–2; –1; –6)

(3; –1; 2)

(5; 1; 4)

28

(–4; 7; 2)

(5; 2; –1)

(–1; –1; 1)

29

(–6; 1; 0)

(1; 4; –1)

(–5; 2; 3)

30

(5; 0; –2)

(8; 3; 1)

(1; –7; 6)